Q5 why are we doing it in such a complex way? We don't know the price of the bikes, but we can just make it up. If one bike is $1 (I like working with small numbers) then we sold 120 bikes for $120 in January. In Feb, we sold 200 bikes making us $120. 120:200 = 0.60 per each bike. 0.60 x 1.6 = 0.96 so less than a dollar, so A is bigger. To check this, I made the price for each bike $50 just to check with a different number and I got A, so A is bigger every time.
Q1, seems faster if we just start substracting 18 from the given numbers to find the answer. Clearly, it can't be E, way too big. Then, all you have to do is 29-18=11 11+29 = 40 so 29 is the correct answer. We could check all of them but it was obvious just by looking at it that the answer will be 29.
Q4 doesn't require any notes, just logical thinking, can't believe questions like this I can solve in head, but I fold on a simple geometry question :(
Q2 did not make sense to me the way it is explained, I would never go with algebra for a question that is clearly a ratio question. If we have 3 colours, W B S, we know there are 3 more W than B, and we don't know the S number of cars, but it could be 1, then why don't we just start by putting the smallest possible numbers that match this question. This would have to be a ratio of 3:1:1. We would have 3/5 for answer A. Now, no matter how many silver cars we add or change the numbers, the fraction will get smaller and smaller as we go, right? So if 3/5 is our answer here, it is smaller than B. What's the point of algebra here?
Query about Question 1; can you pls tell me, why you extract A = E -18 when we can easily put the equation E = A + 18 into first equation that is A = 40 - E, and get the same result.
Q5 why are we doing it in such a complex way? We don't know the price of the bikes, but we can just make it up. If one bike is $1 (I like working with small numbers) then we sold 120 bikes for $120 in January. In Feb, we sold 200 bikes making us $120. 120:200 = 0.60 per each bike. 0.60 x 1.6 = 0.96 so less than a dollar, so A is bigger. To check this, I made the price for each bike $50 just to check with a different number and I got A, so A is bigger every time.
Q1, seems faster if we just start substracting 18 from the given numbers to find the answer. Clearly, it can't be E, way too big. Then, all you have to do is 29-18=11 11+29 = 40 so 29 is the correct answer. We could check all of them but it was obvious just by looking at it that the answer will be 29.
For Last question, I approached 8.08+12/75.
That's a great way of approaching this question! Thank you for sharing it.
more gre quant please, this is super helpful
Q4 doesn't require any notes, just logical thinking, can't believe questions like this I can solve in head, but I fold on a simple geometry question :(
Q2 did not make sense to me the way it is explained, I would never go with algebra for a question that is clearly a ratio question. If we have 3 colours, W B S, we know there are 3 more W than B, and we don't know the S number of cars, but it could be 1, then why don't we just start by putting the smallest possible numbers that match this question. This would have to be a ratio of 3:1:1. We would have 3/5 for answer A. Now, no matter how many silver cars we add or change the numbers, the fraction will get smaller and smaller as we go, right? So if 3/5 is our answer here, it is smaller than B. What's the point of algebra here?
Query about Question 1; can you pls tell me, why you extract A = E -18 when we can easily put the equation E = A + 18 into first equation that is A = 40 - E, and get the same result.