Sir ur excellent work , Any One person who relate this job,when he play ur video.he can't stop or skip any part of ur video,thank u for this informative,and good video.
Excellent video. I was to put a request for a series of video where we can get to know designing a power supply of our own. So I'm really very excited for your upcoming videos with on this topic. Thank you very much for your help and support. Please keep it up.,
6:08 - Setting the frequency to 200 kHz instead of lower will minimize rise time, as you said. But, since the higher the frequency will be the shorter the rise time will be, what would be the drawback if you wanted the frequency to be as high as 500 kHz? Where would you draw the cutoff line?
Assalam o alaikum. I find it very interesting. Could you tell me how many parts of this SMPS Design are there, as they are not in sequence I think. Kindly mention video numbers related to these
Hi, there us a formula from TI for a 12v 4Am SMPS Cin= 2×Pin ×(0.25+1/pi ×ArcSin(Vbulk(min)/√² ×Vin(min))) / (2×Vin(min)² - Vbulk(min)²)× fline(min) Where : VIN Input Voltage 85 --115/230 -- 265 VRMS fLINE Line Frequency 47 --50/60 -- 63 Hz VOUT Output Voltage IOUT(min) ≤ IOUT ≤ IOUT(max) 11.75 -- 12 --12.25 V VRIPPLE Output Ripple Voltage IOUT(min) ≤ IOUT ≤ IOUT(max) 100 mVpp IOUT Output Current 0 -- 4 A η Efficiency 85% My approach is: First, the denominator: 2×Vin(min)² - Vbulk(min)² × fline(min) (2 × 85² - 75² ) × 47 = 414775 Second, the numerator: 2 × Pin ×(0.25+ 1/pi × ArcSin(Vbulk(min)/√2 ×Vin(min))) 2 × Pin ×(0.25+ 1/pi × ArcSin(75/ √2×85)) 2 × Pin ×(0.25+ 1/pi × ArcSin(75/ 120.208)) 2 × Pin ×(0.25+ 1/pi × ArcSin(0.6239)) 2 ×Pin ×(0.25+ 1/pi × 38.6029) 2 ×Pin ×(12.5377) But at the end the power is very huge. That is: 126 = 2× Pin × 12.5377 / 414775 Pin = 2084183 watt My questions are: 1. Is the calculation on denominator correct? 2. Is the calculation on numerator is correct? 3. If correct, is power in that huge?
Kaya 24v 5 amp SMPS ko 36 volt me convert kar sakte ha reference voltage me changes karke aur output ke capcitor ki working voltage Wale lagha kecircuit me
Hi Sir, I hope you can mention along the way how to vary the output current in design from say 5Vdc at 2 Amp to the 5 Vdc at 3 Amp. Which components require the replacement, etc for that purpose. TQ, you simply the best
Thank you very much, can you give the some idea about distributed capacitance in transformer at high frequency and high KV secondary,how to reduce also please give some idea. in transformer design i am selecting the core by Area product method, in that i am fixing the J value initially by 200 amp/cm2, then i choose the core is it correct method of i am going please confirm it. Thank you.
Hi sir In bulk capacitor calculation, if we reverse calculate with 68uF capacitor value the ripple voltage will come as 60V. Is the voltage value taken shoul be Vpeak - Vdc min hole squre??
Thanks for your informative video. I have one question. According to your Bulk capacitor value calculation required value is very high. Normally we found very less capacitance value in practical circuit. As example it is seen for 48W output power, input capacitor value is 47uF, or 68uF. For 65W power supply, it is generally max 100uF. Can you please share what's happened there?
I think the step by step approach is to establish the required capacitor value and it's WVDC rating, although for selection ripple is also very important. For ripple at 100Hz one design goal is to minimize the heat generated within the bulk capacitor due to internal ESR (which depends on which capacitor you choose, from what manufacturer and how it is constructed, you cannot just go by the value calculated). So there is a tradeoff between the capacitor size and its ripple rating or depth (with some added margin because this capacitor has one of the highest failure rates in the design). The choice of 15% ripple for off line is interesting because it was given as a rule of thumb although what is acceptable is the overall design of the capacitor itself. Also, given as a rule of thumb, was an overall power efficiency of 80% (which is reasonable). If you have a thermal camera and examine different capacitors (of the same value and voltage rating but different vendors and types) in operation you can immediately see the heating effect of ripple. You can just simulated the load (converter) with a resistor. Some, input capacitors will get very hot (above 80 C) other will run a lot cooler depending on ESR. This is why the recommendation was for a 105C capacitor and not an 85C rated capacitor the author wanted some margin. But, in actuality, the capacitor you choose at a given worse case supply power should run as cool as possible in order to maximize it's life (temperature versus MTBF). So, what you will find, if reliability is a factor, the capacitor value will be very large in comparison to the calculation. Also, the WVDC rating of 400V assumes to a certain extent that any fast AC line transients beyond the surge voltage rating of the capacitor is minimized on the AC side using a MOV. So, in a way the design is assuming the rating of the capacitor will not be exceeded. And, it was also mentioned that the capacitor would have a current surge (supply surge limiter) using a NTC Thermistor. Which minimizes the surge current into the capacitor.
Can we use the over value for the capacitor rather than the calculated value .... I mean calculated joule increase up to more than 50%. My expectation is capacitor life & life expand. Is it correct
Mr haseeb in current mode smps like welding inverters and all high current mode parellal bulk caps are used what is the purpose of that parellal caps why not to use one cap with large capacity My regards.
Sir, upto how much range of power, we can use smps flyback topology, if we need more power, which topology we can use. and i am eagerly waiting for part 3.
magnet & magnetism, Fundamentals of Magnetism & Magnetic Materials, Electricity and Magnetism, Magnetics Design for Switching Power Supplies, Transformer and Inductor Design
@@HaseebElectronics So it is actually not absolute maximum, it is just average value? I understand there is a ripple across input capacitor. When input AC is 265V, DC peak is 364V, so voltage on capacitor ripples from 362V to 312V (15% down, minus 2 diode drops). So the maximum voltage that goes to inductor is 362V. Why do we need average value? The same applies for lowest AC input voltage 85Vac, where peak is 120V, and voltage on capacitor would be between 118V and 100V. So the minimum voltage on capacitor is 100V
@@Chupacabras222 we are using single diode in output stage, so for single diode we have to consider 1 volt for bridge rectifier we use 1 volt for 2 rectifiers as it is used in low frequency . normally in calculation the input side diode is not considered we always take care for output side for bridge rectifier in input stage just multiply with 1.424 for calculation please check video number 305
Superb piece of information. Accept by accolades. You are one of the best teachers I found on RUclips. I am your fan from India.
Best regards and special thanks
Sir ur excellent work , Any One person who relate this job,when he play ur video.he can't stop or skip any part of ur video,thank u for this informative,and good video.
Many many thanks
Nice instructive video , will watch the 2nd video also , thanx
Excellent video tutorial. You cleared all my concepts.
it is my pleasure
Very good and complete. Thannk you.
Liked and subscribed …Brother you have the best SMPS explanation channel in English ( IMHO ) . Thanks
Thanks and welcome
بارك الله فيك
اللهم زد في علمه و بارك له فيه و اجزه عنه خير جزاء
Aameen. thanks for checking
very useful information. Thank you for posting such a presentation.
Beautiful and excellent demonstration, a very detailed oriented and well explained. Thanks for sharing such a nice video. Keep it up brother.
Very nice video Thanks for shareing Stay connected
Boss I want to learn to say thank you in your language. Because than the less you deserve from Us.
Shukriya (thanks)
please accept my best regards and special thanks
Shukriya electrónics Master
Thanks for sharing this video. watched full and liiked it
Excellent video. I was to put a request for a series of video where we can get to know designing a power supply of our own. So I'm really very excited for your upcoming videos with on this topic. Thank you very much for your help and support. Please keep it up.,
Sir thanks nice learning method god bless you
this a great help teaching this formula how to solve it for the students, thank you my friend
Excellent explanation!
I love your explainations, very instructive, thanks
best regards
Thank you 😊
Very good teacher 😊
You are welcome!
nice job dear bro thanks for sharing
stay blessed
So educative asalam aliykum
MashaAllah good job dear 👍
19:56 why we are using vmin- avg and vpeak min Can we use Vpeak-max and Vmax-avg 19:56
Really enjoy the full tutorial. 🌹🥀💞
It is really useful for the students of electronics. 👍
Wa aliqumuslaam good work brother
Walikum Salaam Dear Brother Like Video Have A Blessed day # 29
Awesome knowledge. Great work as always. Sending you lots of love & support from Australia 🇦🇺❤️
❤️❤Your video is very good. It's amazing to make such a wonderful video.❤️💞 좋아요!!!
Just amazing 👍👍👍👍
Thank you for sharing your knowledge 🙏
best regards
Thanks for shearing knowledge excellent video my brother I watch and like thanks
such a wonderful video sir👍👑
Just Great !!! ⭐⭐⭐⭐⭐
Hello Sir, why did you consider Vdiode : 1V? We have 2 diodes right? I believe 0.7V for each diodes right? Pls clarify me. Thanks in advance
I have the same doubt
Very good,❤❤❤❤
Many many thanks sir ❤
Most welcome
Mashaalha good information lik168
Thanks for your effort impacting your knowledge to us thanks
السلام عليكم بارك الله فيك على مشاركة العلم وجعله الله في ميزان حسناتك
Nice👍👍👍👍
Asalam aliykum sir nice explanation sir
Wa alaikum salaam
thanks a lot
Mashallah amazing video sir 👍
Very Good Work
Nice informative video bhai
MashaAllah , nice video , i like
nice share dear😍
lk 105
Very good informative video
great beautiful video allah bless u
Very knowledgeable video
Excellent 👌👌 bahi
Excellent
Wa alaikum asalam first like dear brother 👍
Sir excellent video , keep it up
Very Interesting video!! Like 119
# Haseeb Electronics, please can you put the link to the website you learnt this from
this not from any site, this i studied in power electronics designing about thirty two years ago
@@HaseebElectronics please can you give me the name of the textbook you used
Thanks for sharing good information 👍
96.. Gooood vediooo
Frnd
Thank you
6:08 - Setting the frequency to 200 kHz instead of lower will minimize rise time, as you said. But, since the higher the frequency will be the shorter the rise time will be, what would be the drawback if you wanted the frequency to be as high as 500 kHz? Where would you draw the cutoff line?
I agree, I wish he spent a few minutes on all factors deciding the frequency... not just rise time.
Informative and nice video
Interesting video friend
88 good sharing 👏👌🙏
Podoba mi się film. Życzę sukcesów.
اسلام و علیکم بھائی جعمہ مبارک
Haseeb super!
Nice share friend
I get a little confused. Do you have a specific playlist just for this flyback design listing the videos in order?
Thanks for Sharing Bhai
Nice explanation. Please make video on i/p filter and protection crt calculation.
Any videos which continues the flyback series and calculates the output capacitor?
Super sir...your next calculate EE42/20/21 - 12 TO 35-+ DC INVERTER
Assalam o alaikum. I find it very interesting. Could you tell me how many parts of this SMPS Design are there, as they are not in sequence I think. Kindly mention video numbers related to these
Sir, you are using 3843 ic. Will this calculation change if we use some different ic.
Hi, there us a formula from TI for a 12v 4Am SMPS
Cin= 2×Pin ×(0.25+1/pi ×ArcSin(Vbulk(min)/√² ×Vin(min))) / (2×Vin(min)² - Vbulk(min)²)× fline(min)
Where :
VIN Input Voltage 85 --115/230 -- 265 VRMS
fLINE Line Frequency 47 --50/60 -- 63 Hz
VOUT Output Voltage IOUT(min) ≤ IOUT ≤ IOUT(max) 11.75 -- 12 --12.25 V
VRIPPLE Output Ripple Voltage IOUT(min) ≤ IOUT ≤ IOUT(max) 100 mVpp
IOUT Output Current 0 -- 4 A
η Efficiency 85%
My approach is:
First, the denominator:
2×Vin(min)² - Vbulk(min)² × fline(min)
(2 × 85² - 75² ) × 47
= 414775
Second, the numerator:
2 × Pin ×(0.25+ 1/pi × ArcSin(Vbulk(min)/√2 ×Vin(min)))
2 × Pin ×(0.25+ 1/pi × ArcSin(75/ √2×85))
2 × Pin ×(0.25+ 1/pi × ArcSin(75/ 120.208))
2 × Pin ×(0.25+ 1/pi × ArcSin(0.6239))
2 ×Pin ×(0.25+ 1/pi × 38.6029)
2 ×Pin ×(12.5377)
But at the end the power is very huge. That is:
126 = 2× Pin × 12.5377 / 414775
Pin = 2084183 watt
My questions are:
1. Is the calculation on denominator correct?
2. Is the calculation on numerator is correct?
3. If correct, is power in that huge?
Walekum Salam brother
Ur great sir
Sir can you please make an video regarding to compensation loop of flyback smps.
sure i will try my best to share CTR and compensation method for compensation and feedback looping
Kaya 24v 5 amp SMPS ko 36 volt me convert kar sakte ha reference voltage me changes karke aur output ke capcitor ki working voltage Wale lagha kecircuit me
Hi Sir, I hope you can mention along the way how to vary the output current in design from say 5Vdc at 2 Amp to the 5 Vdc at 3 Amp. Which components require the replacement, etc for that purpose. TQ, you simply the best
Great
Thank you very much,
can you give the some idea about distributed capacitance in transformer at high frequency and high KV secondary,how to reduce also please give some idea.
in transformer design i am selecting the core by Area product method, in that i am fixing the J value initially by 200 amp/cm2, then i choose the core is it correct method of i am going
please confirm it.
Thank you.
Hi sir
In bulk capacitor calculation, if we reverse calculate with 68uF capacitor value the ripple voltage will come as 60V.
Is the voltage value taken shoul be Vpeak - Vdc min hole squre??
Sir how should we select mosfets and igbt ?
good ...
Can you make a video for design using simulation software and calculation.
Hi , what is reflected voltage?
Thank You
Thanks for your informative video. I have one question. According to your Bulk capacitor value calculation required value is very high. Normally we found very less capacitance value in practical circuit. As example it is seen for 48W output power, input capacitor value is 47uF, or 68uF. For 65W power supply, it is generally max 100uF. Can you please share what's happened there?
I think the step by step approach is to establish the required capacitor value and it's WVDC rating, although for selection ripple is also very important. For ripple at 100Hz one design goal is to minimize the heat generated within the bulk capacitor due to internal ESR (which depends on which capacitor you choose, from what manufacturer and how it is constructed, you cannot just go by the value calculated).
So there is a tradeoff between the capacitor size and its ripple rating or depth (with some added margin because this capacitor has one of the highest failure rates in the design). The choice of 15% ripple for off line is interesting because it was given as a rule of thumb although what is acceptable is the overall design of the capacitor itself.
Also, given as a rule of thumb, was an overall power efficiency of 80% (which is reasonable). If you have a thermal camera and examine different capacitors (of the same value and voltage rating but different vendors and types) in operation you can immediately see the heating effect of ripple. You can just simulated the load (converter) with a resistor. Some, input capacitors will get very hot (above 80 C) other will run a lot cooler depending on ESR. This is why the recommendation was for a 105C capacitor and not an 85C rated capacitor the author wanted some margin. But, in actuality, the capacitor you choose at a given worse case supply power should run as cool as possible in order to maximize it's life (temperature versus MTBF). So, what you will find, if reliability is a factor, the capacitor value will be very large in comparison to the calculation.
Also, the WVDC rating of 400V assumes to a certain extent that any fast AC line transients beyond the surge voltage rating of the capacitor is minimized on the AC side using a MOV. So, in a way the design is assuming the rating of the capacitor will not be exceeded.
And, it was also mentioned that the capacitor would have a current surge (supply surge limiter) using a NTC Thermistor. Which minimizes the surge current into the capacitor.
Can we use the over value for the capacitor rather than the calculated value .... I mean calculated joule increase up to more than 50%. My expectation is capacitor life & life expand. Is it correct
Sir, what is the battery charging methods
Bien 👍
amazing
How do you calculate the out put capacitor
Mr haseeb in current mode smps like welding inverters and all high current mode parellal bulk caps are used what is the purpose of that parellal caps why not to use one cap with large capacity
My regards.
Thanks for replying but you miss understand my question i am asking about parellal caps not series caps thanks.
Sir, upto how much range of power, we can use smps flyback topology, if we need more power, which topology we can use. and i am eagerly waiting for part 3.
Why did you choose current mode smps controller
Sir ...flyback calculation and desing...and flyback driver calculation ...ak video plz
please can you put the name of the textbook you used to learn this when you where studding power electronics designing
magnet & magnetism, Fundamentals of Magnetism & Magnetic Materials, Electricity and Magnetism,
Magnetics Design for Switching Power Supplies, Transformer and Inductor Design
@@HaseebElectronics wow, thanks you are really helping me out, but do you have any pdf format of them?
@@TechFromDan I will check if I can find online books
@@HaseebElectronics please can you drop your WhatsApp number of Facebook username please i need to be clear on a specific point
@@TechFromDan my whatsapp numbers are on my channel homescreen
جزاك الله وشكرا
Great !
Are you sure Vdc(high) is 345V? You should not substract Vripple from Vin(peak), only two diode drops
yes I am sure
and we must get mean value of the ripples
@@HaseebElectronics So it is actually not absolute maximum, it is just average value? I understand there is a ripple across input capacitor. When input AC is 265V, DC peak is 364V, so voltage on capacitor ripples from 362V to 312V (15% down, minus 2 diode drops). So the maximum voltage that goes to inductor is 362V. Why do we need average value? The same applies for lowest AC input voltage 85Vac, where peak is 120V, and voltage on capacitor would be between 118V and 100V. So the minimum voltage on capacitor is 100V
@@HaseebElectronics OK. And why do you substract only 1 diode drop? There are 2 diodes drops in bridge rectifier. Should I substract 2V instead of 1V?
@@Chupacabras222 we are using single diode in output stage, so for single diode we have to consider 1 volt
for bridge rectifier we use 1 volt for 2 rectifiers as it is used in low frequency . normally in calculation the input side diode is not considered
we always take care for output side
for bridge rectifier in input stage just multiply with 1.424 for calculation
please check video number 305