PS.2.2 Worked Example - Stacked Blocks - Choosing the System of 2 Blocks Together

MIT 8.01 Classical Mechanics, Fall 2016
View the complete course: ocw.mit.edu/8-0...
Instructor: Dr. Peter Dourmashkin
License: Creative Commons BY-NC-SA
More information at ocw.mit.edu/terms
More courses at ocw.mit.edu

[@preetharao3640]

appreciate the help sir..... i have a exam in 2 days and this helps me a lot

[@oaycomotnguoicanuocshopeeg504]

Omg😮 you save me prof ❤

[@nadia-sy8cn]

Awesome 👌🏻

[@aytekinayar6952]

I think sir was wrong at the end,F max can be easily found by only analyzing system c as well.All you have to do is writing 2nd law for block 2 and plugging the a value that you get from block 2 into the system c.Because a-c must be equal to a-2,if sliding doesn't occur

[@nikokoro5862]

Then in that case you're analyzing another system besides system c, which goes against the point of this lesson.

[@bobmarley9905]

​@@nikokoro5862 ya so you can use a-b, a-c, or b-c together to solve & u'll get same answer

[@nithinsravan596]

Sir so is it the minimum force required to keep the blocks together?

[@ShreyAroraev3]

0 (magnitude)

[@solsticetwo3476]

In the 2nd approach, when F is low, the a is negative. How can?

[@leoliu7492]

F cannot be less than mu_{static,1} *(m1+m2)g, otherwise it will be stationary

[@nirmalbalamurugan1678]

how f =fk +(m1+m2)a change into f =fk +(m1+m2)g in 3:28

[@nsudhir_here]

It should be a , he corrected it in next line

[@leoliu7492]

They are forces in different directions--i hat and j hat

[@nicodaunt]

is this guy writing backwards?

[@mustafaumutozdemir4513]

no it's mirrored