PS.2.2 Worked Example - Stacked Blocks - Choosing the System of 2 Blocks Together
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- Опубликовано: 25 авг 2024
- MIT 8.01 Classical Mechanics, Fall 2016
View the complete course: ocw.mit.edu/8-0...
Instructor: Dr. Peter Dourmashkin
License: Creative Commons BY-NC-SA
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appreciate the help sir..... i have a exam in 2 days and this helps me a lot
Omg😮 you save me prof ❤
Awesome 👌🏻
I think sir was wrong at the end,F max can be easily found by only analyzing system c as well.All you have to do is writing 2nd law for block 2 and plugging the a value that you get from block 2 into the system c.Because a-c must be equal to a-2,if sliding doesn't occur
Then in that case you're analyzing another system besides system c, which goes against the point of this lesson.
@@nikokoro5862 ya so you can use a-b, a-c, or b-c together to solve & u'll get same answer
Sir so is it the minimum force required to keep the blocks together?
0 (magnitude)
In the 2nd approach, when F is low, the a is negative. How can?
F cannot be less than mu_{static,1} *(m1+m2)g, otherwise it will be stationary
how f =fk +(m1+m2)a change into f =fk +(m1+m2)g in 3:28
It should be a , he corrected it in next line
They are forces in different directions--i hat and j hat
is this guy writing backwards?
no it's mirrored