Sir in atomic case we get gj=gl{j(j+1)+l(l+1-s(s+1)/2j(j+1)}+gs{j(j+1)+s(s+1)-l(l+1)/2j(j+1)} But sir you write in nuclear case gj=gl(1+........)+gs(1+.......) Here an extra 1 is coming .sir i have a confusion in this.pls clarify sir.
Sir if proton or neutron no is odd and the last electron goes in s..... So how we find magnetic moment?????....or we will find for both neutron & proton.
Sir agar x or y mein se kissi ko quantization axis consider kr le toh kya hoga ? Is there any different kind of change we will experience except changes in calculations .
sir ek question please bata dijiye ki jo first example aapne diya he 27Al13 wala usme toh magnetic moment pucha tha aur aapne z-component of magnetic moment nikal diya. Please sir issme bahut confusionho rahi he mughe
sir wo starting me humne magnetic moment liya he proton and neutron ka 2.79 and -1.91 but humne value toh z component of magnetic moment me put kari he. Sir could you please tell this
Sir, we can't write meu(j) = meu(l) + meu(s). But we can in case of pashchan back effect , in high Magnetic field limit, but pashchan back effect is for the moderate fields. Then how we write?
I need someone who know how to use it CCFULL programe for the japanese scientists [ K. Hagino , N. Rowley and A. T. Kruppa ] called : A FORTRAN77 program for coupled-channels calculations with all order couplings for heavy-ion fusion reactions .
Sir last question s state m answer gn aayega but gn ki value to -3.83 btayi h aapne but -1.91 bol rhe h jo meu(n) ki value h......dono m se sahi konsa h???
Last meh meu(n)= -1.9130meu(N) for j=l+1/2 & meu(n) =0.63767meu(N) for j=l-1/2 yeh doon value ahh raha hain mera.... As becoz s orbit meh single nucleon present hain.. Kya yeh thik hain...??
@@kuldeepkumarsingha2053 16 P 31 me proton no 16 & neutron no 15 so according to energy level diagram last neutron S m fill hoga... So j = 1/2 , l =0 so j=l+1/2 so magnetic moment S state m odd neutron ke liye formula = g(n)meu(n) hoga to answer -3.82meu(n) hoga..... According to me this is the solution of this question
@@kuldeepkumarsingha2053 Jb last electron S m h to l=0 ho jayega to wha j=mod of l+1/2 or j=mod of l-1/2 ki condition hi nhi hogi... So we will focus only on odd proton or odd neutron so in this question neutron no is odd so magnetic moment is -g(n)meu(n) hoga where g(n)= -3.82
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Best lecture and explain each aspect of concept in very lucid manner. Thanks a lot for your great effort and beautiful lecture.
Thanks dear enjoy it
Omg plz sir important topics plz utube pr krva do continue plz poor students ki help ho jayegi plz for rpsc frst grd plz
Wonderful lecture 🎉
Thankyou so much sir, 🙏🙏🙏🙏🙏, aapne khod khod kar puri kahani hi clear kar di
Thanks
@1:05:50 third example must be sulphur S instead of phosphorus P
Because of 16 protons
No one noticed that 🤓
your lecture is awesome .......thank you so much sir
sr really good teaching for u ...... I hope sr well-done technic sr g
Thanks
Sir in atomic case we get
gj=gl{j(j+1)+l(l+1-s(s+1)/2j(j+1)}+gs{j(j+1)+s(s+1)-l(l+1)/2j(j+1)}
But sir you write in nuclear case
gj=gl(1+........)+gs(1+.......)
Here an extra 1 is coming .sir i have a confusion in this.pls clarify sir.
sir wrote here wrong , gj have only above expression without having an extra 1
very conceptual lecture..thanks sir
Sir if proton or neutron no is odd and the last electron goes in s..... So how we find magnetic moment?????....or we will find for both neutron & proton.
Sir agar x or y mein se kissi ko quantization axis consider kr le toh kya hoga ? Is there any different kind of change we will experience except changes in calculations .
Thanku sir 🙏
For even even nuclei how magnetic moment is 0???because J contains spin plus orbital term...
sare ho gye
But how the spin of neutron (combo of quarks) will contribute magnetic moment?
Pls upload the lecture after application of Shell model which is now in private mode
Sir teligram p assignment kaise milega or teligram p kaise saruch kre bta dijiye sir
sir ek question please bata dijiye ki jo first example aapne diya he 27Al13 wala usme toh magnetic moment pucha tha aur aapne z-component of magnetic moment nikal diya. Please sir issme bahut confusionho rahi he mughe
sir wo starting me humne magnetic moment liya he proton and neutron ka 2.79 and -1.91 but humne value toh z component of magnetic moment me put kari he. Sir could you please tell this
Sir frictional charge ko Thoda explain kijiya
Sir, we can't write meu(j) = meu(l) + meu(s).
But we can in case of pashchan back effect , in high Magnetic field limit, but pashchan back effect is for the moderate fields.
Then how we write?
Paschen back for high field
Nitrogen vale ka - 0.26 aa rha h negative me bi aa skta h kya
I need someone who know how to use it CCFULL programe for the japanese scientists [ K. Hagino , N. Rowley and A. T. Kruppa ] called :
A FORTRAN77 program for coupled-channels calculations with all order couplings for heavy-ion fusion reactions .
Sir atomic puri nhi krwaoge kya aab aap RUclips pe😢
Try to complete
@@physicsbya.singhsir3629 thank you sir☺️☺️
❤️🙏🙏🙏🙏🙏
Sir from where can i get the assignment of nuclear physics
Telegram -8769828844
Sir last question s state m answer gn aayega but gn ki value to -3.83 btayi h aapne but -1.91 bol rhe h jo meu(n) ki value h......dono m se sahi konsa h???
Last meh
meu(n)= -1.9130meu(N) for j=l+1/2
&
meu(n) =0.63767meu(N) for j=l-1/2
yeh doon value ahh raha hain mera.... As becoz s orbit meh single nucleon present hain.. Kya yeh thik hain...??
@@kuldeepkumarsingha2053 16 P 31 me proton no 16 & neutron no 15 so according to energy level diagram last neutron S m fill hoga... So j = 1/2 , l =0 so j=l+1/2 so magnetic moment S state m odd neutron ke liye formula = g(n)meu(n) hoga to answer -3.82meu(n) hoga..... According to me this is the solution of this question
@@monika.guptaa Magnetic moment nikalne ke liye j=l±½ condition lena partah hain.... Agar p-subshell yaa d-subshell meh nikalna hain... Toh koi prblm nhi atah... Kyuki wahan l≠0 hotah hain, dono meh se ekk condition lekar meu(n) ki value nikala jatah hain...ie, either j=l+½ or j=l-½... Lekin yahan s-orbital peh splitting nhi hotah... Toh kaunsa wala condition lena parega j=l±½ meh se...??? Yaa dono condition leke meu(n) ki doon value nikalna hoga... Yahi doubts hain....
@@kuldeepkumarsingha2053 Jb last electron S m h to l=0 ho jayega to wha j=mod of l+1/2 or j=mod of l-1/2 ki condition hi nhi hogi... So we will focus only on odd proton or odd neutron so in this question neutron no is odd so magnetic moment is -g(n)meu(n) hoga where g(n)= -3.82
Telegram channel link uc browser pe on nhi hota only Google chrome pr hi hota h shi se....mene join kiya to Google chrome se kiya tha link open ..uc browser se nhi ho paya sir do tin bar kr chuke the tb bhi
You can telegram on -8769828844
@@physicsbya.singhsir3629 thanku so much sir ..ho gya telegram pe aab
-1.91