Basic Channel Capacity Behaviors [Video 4]

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  • Опубликовано: 18 дек 2024

Комментарии • 26

  • @khalidshaikh1098
    @khalidshaikh1098 2 месяца назад

    Hello Thankyou for the detailed explaination - I have one question
    If I have a Wi-Fi setup which provides me the following information at the receiver side -
    RSSI (signal strength at the receiver) and the Noise floor in dB and the channel frequency response
    is there any way i can evaluate the capacity of the channel with the above values as I have no acess to baseband signal to get the energy of each bits.?

    • @WirelessFuture
      @WirelessFuture  2 месяца назад

      The easiest thing would be to compute the SNR as the RSSI divided by the Noise power (be careful with the dB-scales). You can then estimate the capacity as "Bandwidth*log2(1+SNR)".

    • @khalidshaikh1098
      @khalidshaikh1098 2 месяца назад

      @@WirelessFuture Thankyou for the explaination , just a follow up question : Considering a 2x2 MIMO channel ,
      I have the channel state information of received signal and RSSI and Noise Floor values of each Tx-Rx path, which formulae can I used to estimate the capacity of Wi-fi system ? considering rest other OFDM parameters (MCS, Bandwidth...etc ) is known to me. It would be reallly help- ful for my Thesis work. Thankyou in advance :)

  • @samant6812
    @samant6812 5 лет назад

    sir your lectures are very much useful.

  • @wafaelhajhmida3863
    @wafaelhajhmida3863 4 года назад +2

    Dear Mr. Bjornson,
    You have an incredible way to convey your knowledge :)
    Could you plz make for us a video to explain why the data rate is related to the frequency bandwidth using Fourier transform ?
    Thx a lot

    • @WirelessFuture
      @WirelessFuture  4 года назад +1

      You don’t need to involve the Fourier transform. Just apply the sampling theorem, which says that a signal is described by a number of samples proportional to the bandwidth. These samples are used to carry information, for example, by designing the signals using pulse-amplitude modulation. It is briefly mentioned in Video 3 and around slide 22 in ruclips.net/video/SR10FeiuAFs/видео.html

    • @wafaelhajhmida3863
      @wafaelhajhmida3863 4 года назад

      @@WirelessFuture thx a lot

  • @juliocarossella6026
    @juliocarossella6026 3 года назад

    00:48 is possible to have a non-symmetric two-sided spectrum??

    • @WirelessFuture
      @WirelessFuture  3 года назад

      Yes, but then the time-domain signal will be complex valued, so such a signal doesn’t exist in practice. However, the non-symmetric complex baseband signal exist and is usually represented as two different signals. (The “in-phase” and “quadrature” signals)

    • @juliocarossella6026
      @juliocarossella6026 3 года назад

      @@WirelessFuture ... but the graph is representing a baseband 2-sided spectrum.... is that possible?

  • @kozhenidres314
    @kozhenidres314 4 года назад

    ♥️😍
    another piece of cake
    but the equation @3:07 should not be in (Symbol/second) instead (bits/s) because i think it's going to be bits/s after modulating the symbols isn't it ?

    • @WirelessFuture
      @WirelessFuture  4 года назад +3

      If you pause the video at 2:34, you will see expressions in symbol/s and in bit/symbol. If we multiply them together it becomes bit/s. This what is presented at 3:07.

  • @thinyuaung9333
    @thinyuaung9333 5 лет назад

    Thank you so much...very nice explanation.

  • @XTQ1179
    @XTQ1179 4 года назад

    The Shannon limit says there is an upper bound for a reliable communication. Then what is the meaning of "reliable communication"? In other words, if one exceeds the limit, how much deterioration will be brought about?

    • @WirelessFuture
      @WirelessFuture  4 года назад +3

      Suppose we transmit a block of N modulation symbols (samples). If their information content is below the Shannon limit, there is a way to encode the information (select the symbols) so that the probability of incorrect reception of the block goes to zero as N increases towards infinity. If we instead exceed the limit, then as N increases, the communication will always fail (with probability approaching 1). So it is really becoming binary. Below the limit: Success. Above the limit: failure.

    • @XTQ1179
      @XTQ1179 4 года назад

      @@WirelessFuture Thank you very much! Great explanation!

  • @abdulazizalakoub1087
    @abdulazizalakoub1087 5 лет назад

    Thank you very much
    B (Symbol/sec) and B (Bandwidth) , I have a confused in this abbreviations

    • @WirelessFuture
      @WirelessFuture  5 лет назад +6

      B is the bandwidth in Hz, but due to the sampling theorem it also equals the number of complex symbols per second. (The sampling theorem says that a signal with bandwidth B is uniquely described by 2B real samples per second or B complex samples.

  • @abinetendale2455
    @abinetendale2455 5 лет назад

    Nice video

  • @lonleyangel95
    @lonleyangel95 4 года назад

    how log2 (1+z)= log2(e)!!!

    • @WirelessFuture
      @WirelessFuture  4 года назад +1

      log2(1+z)≈log2(e)*z when z is close to zero.

    • @lonleyangel95
      @lonleyangel95 4 года назад

      @@WirelessFuture okai thank you

  • @donpkchannel7203
    @donpkchannel7203 2 года назад

    Very bad. You talk without thinking about us understanding. Your just reading of some text. Try to be better.

    • @WirelessFuture
      @WirelessFuture  2 года назад +1

      This is a brief overview of the concept. If you want a more in-depth description, we recommend the following video: ruclips.net/video/VUZSf2NlTyM/видео.html
      In fact, there is an entire lecture series: ruclips.net/p/PLTv48TzNRhaJ66mW48MI_HBBawupV_ZR_