INDIAN || n^6 = 7^6 Olympiads Trick

[@mirkozinauer319]

n^6=7^6
n^6=7^6*e^(2*k*π*i)
(n^6)^(1/6)=(7^6*e^(2*k*π*i))^(1/6)
n=7*e^(k*π/3*i) {k=0,1,2,3,4,5}
k=0, n1=7
k=1, n2=7(1/2+√3/2i)
k=2, n3=7(-1/2+√3/2i)
k=3, n4=-7
k=4, n5=7(-1/2-√3/2i)
k=5, n6=7(1/2-√3/2i)

[@marioalenjandroh4485]

im so happy i did it by myself

[@blyme_lpyt3295]

Just do plus minus 6root of Both and you get plus minus 7.

[@-Inf1]

To solve this question, you must find all sollutions, include complex solutions

[@RealQinnMalloryu4]

3^4^2^3 1^2^2^1^3 1^2^1^3 23(n ➖ 3n+2).

[@vladimirstankovik2253]

if n^6=7^6 only n=7 is the result because 7^6=7^6 ???

[@vladimirstankovik2253]

or negativ -7