Not in general I don't think. Suppose you find the transfer function of a simple voltage divider with no load on the output. It should simplify down to just a constant ratio determined by the R1 and R2. You can determine the ratio of these resistors but not the absolute value of each one, as that information was lost.
@@ElectricalEngineeringAuthority Looking at this from the perspective of a filter circuit the K term would also be the gain at 0 frequency or DC gain correct? This could be seen as a passive 2nd order low pass filter circuit
@@imissmycatsm I believe it depends on what direction you draw the currents entering the node. She drew one current entering the node and 2 currents leaving the node.
The resistors are not in parallel. But you can combine the 4 ohm resistor with the parallel s/10 capacitor and do voltage division and get exactly the same answer. Simplify the following: H(s) = K*(40/(4*s + 10)/(40/(4*s +10) + 2 + s))
Could somebody help😬? I need to find transfer function of [34*10^5 = 128806*10^3 * v'(t) + 91239 * v(t)^2 + 680*10^3 * v (t)] for inserting block in simulink and check simple control system. Be so kind, heelp 😁🙏
got a question close to this...FINALLY knew how to do it now... TQVM u really made my day !!!
If you were to remove the inductor would the process for finding the transfer function remain the same?
Yes. So you still need to find Vo/Vs as your transfer function. If you remove the inductor then you won't have LS there anymore.
nice explanation !!! But is it possible to find the values of R, L and C from the transfer function ?
Not in general I don't think.
Suppose you find the transfer function of a simple voltage divider with no load on the output. It should simplify down to just a constant ratio determined by the R1 and R2. You can determine the ratio of these resistors but not the absolute value of each one, as that information was lost.
Thanks a lot. Really helped me with my assignments
hello, the K in the voltage source stands for what? is it a constant or kilo?
It is a constant
@@ElectricalEngineeringAuthority Looking at this from the perspective of a filter circuit the K term would also be the gain at 0 frequency or DC gain correct? This could be seen as a passive 2nd order low pass filter circuit
mfan981 Yes it is correct
Thank you! This helps a lot!
How to find transfer fucntion of series RLC ckt in frequency domain??
What is name of the software you are using?
one note i guess
What does the K mean? Why not just make it V(s)?
super
Thank you for the video. Now, once I have the transfer function, what do I do with it?
You can LOOK at it. 👀
@@power-max You're so fffffffffunny :)
How to solve with initial conditions?
question, what app did you use for those drawings and was it on an ipad or another tablet?
Looks like the Shetchbook app from Autodesk.
@@YouKnowMeDuh what about to record her screen?
@@Inkieto92 Its Microsoft OneNote which is available for tablet/iPad and you can use OBS to record your screen if on a laptop.
thank you a lot ,, you made it really easy to do
you are the best
nice explanation
Fantastic!
WHATS THE NAME OF THE BOOK THAT U EXPLAINING FROM PLZZZZZZZZZ!!!!!!
Why did you equate in into (Vo-KV(s))/2+s insteaf of zero?
I thought it must be like this
(Vo-KV(s)/2+s) + (Vo/4) + (Vo/10/s) = 0 then
(Vo-KV(s)/2+s) = -(Vo/4) - (Vo/10/s)
Isn't?
@@imissmycatsm I believe it depends on what direction you draw the currents entering the node. She drew one current entering the node and 2 currents leaving the node.
What K stand for at Kvs
អរគុណThank❤
Very good. Thank you.
Why do we have to find transfer function, why is it important
So that you can bodeplot your frequencies
Thank you!!!
for the Vo multiple should the denominator not be 40(2+s) instead of 20(2+s) great video tho
So I have taken the common denominator between 4, 10, and s+2 which is 20(s+2). I hope it answered your question.
Thank you
Could you combine the parallel resistors and then apply voltage divider rule to find H(s) as well?
SizeableVermin I did that. But ended up with a different answer.. 4K/6+s
The resistors are not in parallel. But you can combine the 4 ohm resistor with the parallel s/10 capacitor and do voltage division and get exactly the same answer. Simplify the following:
H(s) = K*(40/(4*s + 10)/(40/(4*s +10) + 2 + s))
Thanks 💕
thanks b
Anyone is here who can do my assignment? :(
Got you bro
Could somebody help😬? I need to find transfer function of [34*10^5 = 128806*10^3 * v'(t) + 91239 * v(t)^2 + 680*10^3 * v (t)] for inserting block in simulink and check simple control system. Be so kind, heelp 😁🙏
this babe has a Persian accent
Thank you