Circuit Analysis using Laplace Transform | Network Analysis

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  • Опубликовано: 28 июн 2024
  • In this video, how to do the circuit analysis of electrical circuits using the Laplace Transform has been explained with few solved examples.
    The circuit analysis using the Laplace Transform involves the following steps.
    1) Find the equivalent electrical circuit in the s-domain
    2) Using circuit analysis techniques like nodal/ mesh analysis, superposition theorem, and source transformation find the node voltage and loop currents in the circuit. And with the help of it, find the voltage or current across any element in the s-domain.
    3) Using inverse Laplace Transform, find the time-domain expression of voltage or current.
    The circuit analysis using the Laplace Transform is specifically useful when the circuit contains a non-standard excitation source like exponential sources, triangular waveform, etc, or it is useful for doing the circuit analysis of second-order RLC circuits.
    In this video, how to find the equivalent s-domain representation for the basic circuit elements (with and without initial conditions) like resistor, capacitor, and inductor is explained.
    And after that, the procedure of doing the circuit analysis using the Laplace Transform is explained through different solved examples.
    The following topics are covered in the video:
    0:00 Introduction
    1:29 S-domain equivalent circuits for resistor, inductor, and capacitor
    8:56 Example 1
    16:44 Example 2
    For other useful videos related to Laplace Transform, check this playlist:
    • Circuit Analysis using...
    This video will be helpful to all the students of science and engineering in understanding, how to do the circuit analysis using the Laplace Transform.
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Комментарии • 31

  • @ALLABOUTELECTRONICS
    @ALLABOUTELECTRONICS  8 месяцев назад +5

    For other useful videos related to Laplace Transform, check this playlist:
    ruclips.net/p/PLwjK_iyK4LLD8Cdj0SKiMZFoK2d3eE6v2&si=zPi5_EwlASecoTIR

    • @saurabhbaidya5304
      @saurabhbaidya5304 8 месяцев назад

      Sir coordinate system and transformation stady this chapter please

  • @Stevensmith30247
    @Stevensmith30247 8 месяцев назад +5

    Just now I searched for the same topic and came the notification of yours.

  • @jaseemajasmin5296
    @jaseemajasmin5296 6 месяцев назад +2

    Thankyou so much for this wonderful classs❤🎉

  • @SophiaNguyen-be5yk
    @SophiaNguyen-be5yk 2 месяца назад +1

    amazing video, pls keep going

  • @NshimiyimanaNorbert-bu8rg
    @NshimiyimanaNorbert-bu8rg 8 месяцев назад +1

    We really thank you you are helping us understand more than we would imagine if its possible call tell us On sit transistor

  • @mayurshah9131
    @mayurshah9131 8 месяцев назад +1

    Very informative 🎉🎉

  • @rsii1322
    @rsii1322 5 месяцев назад

    Have you also made lecture videos on Three phase circuits??
    And I really appreciate your hardwork..

  • @arushisingh29
    @arushisingh29 2 месяца назад +1

    Thank you so much sir

  • @GlobalGrooveTrends
    @GlobalGrooveTrends 3 месяца назад

    In the first example, why do we introduce root 2 squared?

  • @David_94
    @David_94 8 месяцев назад

    5:01 thanks for the video, what does it mean that the inductor has an initial current I(0-)? Is it like there's an initial magnetic field on the coil without being connected to anything or what does it mean?

    • @ALLABOUTELECTRONICS
      @ALLABOUTELECTRONICS  8 месяцев назад +5

      It means that, the initially inductor was connected to some other circuit. And because of that, there is some flow of current through the inductor. Now, as you know, the inductor opposes the instantaneous change in the current. That means even after disconnecting it from the previous circuit, and connecting it to the new circuit, immediately the same current will continue to flow through the inductor. So, in the newly connected circuit of the inductor, that current will be the initial current through the inductor. I hope, it will clear your doubt.
      For more info, you may check this video, which I have made some time back.
      ruclips.net/video/3YinmbkU0DE/видео.htmlsi=RzjcX-HDj1lVEQ5e

    • @David_94
      @David_94 8 месяцев назад

      @@ALLABOUTELECTRONICS thank you, as always excellent explanations 🙏

  • @rudrakshjain8492
    @rudrakshjain8492 2 месяца назад

    While writing the s domail equivalence of inductor, when we get the term v(s) = Lsi(s) + Li(0-), why does that translate to an inductor of ls inductance? Wouldn't that have a different voltage?

    • @ALLABOUTELECTRONICS
      @ALLABOUTELECTRONICS  2 месяца назад

      This is S-domain circuit. In the S-domain circuit I(s) is the current in S-domain. So, Ls represents the equivalent inductance in S-domain.

  • @punnabratachatterjee5681
    @punnabratachatterjee5681 5 месяцев назад

    Sir did you explained convolution theorem in this video series

  • @1InAll.
    @1InAll. 6 месяцев назад +1

    Sir my dought is that in first question final answer was written without u(t)
    But second Question final answer was written in terms of u(t), why?

    • @ALLABOUTELECTRONICS
      @ALLABOUTELECTRONICS  6 месяцев назад +1

      In the first example, I forgot to write it. But while writing the output, one should always write it.

    • @1InAll.
      @1InAll. 6 месяцев назад +1

      @@ALLABOUTELECTRONICS
      Thanks

  • @abinroy7800
    @abinroy7800 2 месяца назад

    in example 2 how does v0(s) become 4*i(s) where does 4 come from

    • @ALLABOUTELECTRONICS
      @ALLABOUTELECTRONICS  2 месяца назад

      It is as per the ohm's law. V = I x R. And here, R is 4 ohm. So, Vo (s) = 4 x I(s). I hope, it will clear your doubt.

  • @sudipbiswas4718
    @sudipbiswas4718 5 месяцев назад

    16:05 sir how it is time shifting?

  • @achalchoudhari8276
    @achalchoudhari8276 3 месяца назад

    why did you multiply 3s on both side ? 13:34

    • @ALLABOUTELECTRONICS
      @ALLABOUTELECTRONICS  3 месяца назад

      On the right hand side, after simplification, in the denominator you will get 3s. So, that is why both sides have been multiplied by 3s.

  • @urnoob5528
    @urnoob5528 8 месяцев назад +1

    can i solve ac circuit this way instead of the phasor domain? man i really hate dealing with complex numbers
    a quick look and i cant seem to find how to solve the phase in s domain
    seems only for transient analysis
    so im stuck with phasor?
    will it actually be harder to solve ac using s domain than phasor domain?

    • @ALLABOUTELECTRONICS
      @ALLABOUTELECTRONICS  8 месяцев назад

      Yes, for sinusoidal analysis, it is better to solve it using the phasors. If you deal it in the s-domain, then it involves a little more mathematics. (Finding the Inverse Laplace Transform is additional step). Moreover, if you deal it in the s-domain, then the response of the circuit contains both transient and steady state response. If you just want to consider steady state response, then first you need to remove the transient response. (The terms which contains decaying exponential terms)
      On the channel, through different videos and different solved examples, the ac analysis of the circuit using the phasors have been already covered.
      If you required, you can check the playlist of network analysis.
      ruclips.net/p/PLwjK_iyK4LLBN9RIDQfl9YB4caBYyD_uo&si=RnvwjOP3Cc03xiZp

  • @user-nd5vg3mf2m
    @user-nd5vg3mf2m 8 месяцев назад

    ممكن تفعيل الترجمه لو تسمح