When I learned my formulae for GCSE Physics I know that Power = Voltage x Current and that Energy = Power x Time (seconds) which is what has been done here to get 1980 Joules after 60 seconds. But... I also learned that Charge (Coulombs) = Current x time = 3.3 x 60 = 198 Coulombs after 1 minute. Then energy = Charge x Voltage = 198 x 9.9 = 1960 Joules. This isn't 1980 but it's close. Would I be wrong to do it this way and why is there a small difference?
Yes, all that is correct., sorry for the confusion. Either way it is Energy = voltage x current x time, the difference is just down to rounding 3.3 x 9.9 x 60 = 1960.2 so that is the correct answer I have done 3.3 x 9.9 = 32.67, rounded this to 33 W then done 33 x 60 = 1980 which is probably a bit naughty! Always keep more significant figures in your working is good advice.
thanks so much. This video was really helpful. I just have one question: would it be acceptable to take a reading of the current and potential difference as well after every 60 seconds and then use an average of each for calculating the power supplied?
Hi thanks. That would be a slight improvement. The resistance of the heater will probably change slightly as it gets hotter and therefore the power input will change slightly, your idea would give a more accurate result.
Here is a booklet containing all of the practicals for physics: filestore.aqa.org.uk/resources/physics/AQA-8463-PRACTICALS-HB.PDF I hope GCSE students in future years will find this as useful as I have.
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6:00 Why were the I and V (I=current, V=Potential difference) fluctuating?
im assuming most of u re from a class?
This was really really helpful before my exam tomorrow, thank you :)
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When I learned my formulae for GCSE Physics I know that Power = Voltage x Current and that Energy = Power x Time (seconds) which is what has been done here to get 1980 Joules after 60 seconds.
But... I also learned that Charge (Coulombs) = Current x time = 3.3 x 60 = 198 Coulombs after 1 minute.
Then energy = Charge x Voltage = 198 x 9.9 = 1960 Joules. This isn't 1980 but it's close. Would I be wrong to do it this way and why is there a small difference?
Yes, all that is correct., sorry for the confusion.
Either way it is Energy = voltage x current x time, the difference is just down to rounding
3.3 x 9.9 x 60 = 1960.2 so that is the correct answer
I have done 3.3 x 9.9 = 32.67, rounded this to 33 W then done 33 x 60 = 1980 which is probably a bit naughty! Always keep more significant figures in your working is good advice.
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thanks so much. This video was really helpful. I just have one question:
would it be acceptable to take a reading of the current and potential difference as well after every 60 seconds and then use an average of each for calculating the power supplied?
Hi thanks. That would be a slight improvement. The resistance of the heater will probably change slightly as it gets hotter and therefore the power input will change slightly, your idea would give a more accurate result.
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Can I copy someone's circuit diagram for this? I don't know how it's supposed to look 😂
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can someone help with my hw
how do you find the specific heat capacity of a copper block
Thanks
Here is a booklet containing all of the practicals for physics:
filestore.aqa.org.uk/resources/physics/AQA-8463-PRACTICALS-HB.PDF
I hope GCSE students in future years will find this as useful as I have.
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