Specific Heat of a Metal Lab
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- Опубликовано: 20 окт 2024
- Part of NCSSM CORE collection: This video shows the collection of data to determine the specific heat of a metal. www.dlt.ncssm.edu
Please attribute this work as being created by the North Carolina School of Science and Mathematics. This work is licensed under Creative Commons CC-BY creativecommons...
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Full answer key, for those who want to get it over with and play gmod/minecraft/fortnite:
Important timestamps:
Formula: 0:42
Filled out table: 4:11(not everything that's graded, though)
Mass of the metal: 0:52
Approx starting temp for the metal: 1:02 and 3:05
Weight for water: 1:10 (later on she says that 1 ml converts to 1 gram)
Starting temp for the water: 2:00
Procedure: 3:19
Ending temp for the water: 3:46
Temperature change for water: 3:49
Answers to Questions, keep in mind these might not be the ones you have:
Water gained energy during the experiment
Metal underwent more temperature change
Water has a higher heat capacity
Ones that have formulas:
Heat absorbed by the water:
Q = 1255.2J =100 * 4.184*3
Heat the metal released:
1255.2 Joules
Specific heat of the metal:
C = 7.09 = 1255.2 / (58.953*3) (I looked it up and the specific heat capacity for cadmium is .23 so IDK if I did something wrong or not)
17 likes but no comment, i want to be the first to tell you you are a king that is loved and appreciated
Thank you so much for your help. KUDOS!!!
I'm actually going to play roblox but thanks anyway!
you are a real one
This man right here is literally goated
Answer Key of the Specific Heat (try to solve it yourself first pls)
First find the Joules the water gained
Q = 100.0g x 4.18j/g*c x (25-22*C)
Q= 1254 J
Since it was 1254 J transferred to the water it was removed from the metal - reduction so make it negative
-1254 J = 58.953g x C x (25-100*C)
-1,254 = 58.953 x C x -75*C
-1254 = -4,421.475 x C
-1254/-4,421.475 = 0.28361
Specific Heat (C) = 0.284 J/g*C
(3 sig figs as there were a low of 3 sig figs in the video)
I hope this helps anyone who was stuck (:
Question why is the specific heat .284 but when I searched it online its .232 I am stuck on this part please help
@@johnroaldcomargo4716 I'm sorry I dont really know why it is showing that, however my teacher did go over these answers so I can confirm that this is a correct answer. I hope this helps!
@@nightcorenerd19 Thank you for the reply I asked my teacher and he said that because the given are not exact that's why its showing different results.
thanks
This is late but according to my teacher and also based on the internet, only the water has a constant specific heat which is 4.18J/g.°C. The 0.232 specific heat for Cd on the internet is only a basis (?) or a theoretical answer. Specific heat also depends on the mass(?). Am not sure tho but this is my understanding. Hope this helps!
Here, how to do it for people who need help.
specific heat water = 4.18 J/g°C
heat gained by water = 100g X 4.18 j/g X 3°C = 1254J
heat lost by Cd = 58.953 g x ( 25°C - 100°C)X specific heat = -4421.475 x specific heat
heat lost + heat gained =0
1254J -4421.475 x specific heat =0
-4421.475 x specific heat = -1254J
specific heat = -1254J/-4421.475
specific heat = 0.28 J/g°C
nobody asked
Nasif Rahman dammmmnnn
Nasif Rahman nobody asked but I needed it so I’m grateful
i still don't get it :(
Thank you! very helpful :)
when you are here forced to watch this because your teach told you to do so :< i cant gain learnings here daaamn its better if you experience this experiment :
I hear ya. I'm not in school. Just wanted to learn something new. Am having a hard time prying the lids open, lol! I'd much rather be DOING this than just watching!
JustRosy2 because its an experiment so we should experience not watching it because it sucks :< maybe i will learn it now but later maybe i’ll forget this easily
When ur lab exam is this exact lab
Same
Honestly if I hadn't watch this video soon enough, I would've probably wrote about how I didn't learn anything for my conclusion..
This is so well explained and helped me understand what i was learning better. Thank you!
Life saver for my class today
There is a problem with this experiment. You can't be sure the measured 100 ml of water from the tap is at room temperature. It would be more accurate to put a second thermometer in this water beforehand so you know exactly what its initial temperature is.
Otherwise, good demonstration--especially the suggestion of not letting the metal touch the glass on the heating phase. I intend to do this with my own students except with the modification I suggested.
Oh never mind! She did that step. The first time I watched I took a bite of my sandwich while she was measuring the temperature and I missed it!
Sorry! It's perfect.
Andrew Stallard Lol
Thank You so much, that was a lot of help and easy to understand. Hope there are more videos like this. I am afraid I will be needing them this semester in Chem.
nobody cares
She gave you all the information in the video.
I simply applied the formula.
no one cares
I teach chemistry and would like to use this video but the value I got was 0.2856 J/gC. The accepted value from the web seems to be between 0.230 to 0.232 on the web. Has anyone else worked this out? If so, what did you get?
What was the temp of the metal before she put it in? Or do we need to use the: Q= mc(Delta)T ?
I think we can assume the metal is 100 degrees C when she takes it out of the boiling water
This is a good video to help with the experiments.
this is such a life-saver!! i will be sharing this with classmates!!
i love u tysm i would've failed my lab exam without this ❤️ haven't done it yet hope i didnt jinx myself lol
did you fail?
What would happen to the final temperature if you put twice as many (i.e., 200 g) cold steel
washers into the water? How does the final temperature depend on the relative mass of the
steel and water
22.4% error. Way to go, grandma.
THANK YOUUU
it is 0.28338871644 so round and if you are using sig fig rules it is 0.3
specify what your answer is .... please
sodium hydroxide- 29 °C
hydrochloric acid- 29°C
calorimeter- 29°C
calorimeter with mixed both chemicals- 30°C
beaker- 114 grams
Calorimeter- 160 grams with water
initial temperature of water- 29 °C
Calorimiter with copper wire- 30°C
initial temperature of metal-85°C
copper wire- 4 grams
plsss help me to solve this especially about of the specific heat of a metal
The demonstrator mentioned that “at room temperature, 100 ml of water have a mass
of 100 g” can anyone please explain using the relevant formulas why this is the case
1 mL = 1 g so 100 mL = 100 g
Has anyone come up with a research question for this?
she seems like a very nice lady 😊
ur rong
May I know what materials are being used in this activity?
Hahaha laban earl😆
• Cadmium metal
• 1 Scale
• 1 Bunsen Burner Set
• 1 150 ml beaker
• Water
• 1 100 ml measuring cylinder
• 2 calorimeter
• 1 thermometer String
• 1 retort stand
• 1 ring clamp
• 1 stirring rod
Why do I suspect that that's how she makes her tea when no one's looking? :)
Thank you very much, I love it.
wait, this isn't a rickroll
Minus the string !!
can someone help me? Show the percentage error calculation and result
what was the quantity of heat?
i hate chemistry with a passion.... That is all.
COVID19 brought me here✊
Anyone have the Materials and Procedure written out?
can someone please tell me all apparatus used
Alguien más por la UTA.
asvcdfvasd
piola xd
does anyone know one possible error that couldve occurred during the experiment?
One possible error is that the reading is not taken from eye level. This leads to a parallax error where the reading is either higher or lower for the temperature.
@@theforgottenandthelost6748 thank you!
TO SOLVE THE LAST PROBLEM
Specific heat of water is given in JOULES, but the question is asking for CALORIES/(g*T) so instead of calculating 100*4.18*3... its only necessary to calculate 100*1*3.... this is because 1 "gram calorie" = 4.184 Joules.
so if we take (100g*1cal*3degree)/(58.953g*75degree)==>(300/4421.475)==> ~.068
given that cadmium's accepted Specific Heat is .055 c/g*T this is a pretty large margin of error, but then again we're using styrofoam cups, so you know it's not like we're sending guys to the moon here.
I need to find the initial mass of the cup and cover (EMPTY) then I need the mass of the cups + cover + 100mL. Can someone please help me?
Wow. Sounds like you've got a real jerk for a Chem teacher, asking you for stuff like that!
Observation pls
Why the heated metal has to transfer quickly
We gotta keep the same temp of the metal if it stayed in the air for a while it's temp will decrease
My chemistry exam has us watching this video because of the Rona. It's today, wish me luck!
I got an A!
@@judelyne08 good for you...?
@@judelyne08 help!!!
What are the variables of this experiment???
very lost. Did anyone Get this?
i know this is 7 years in advance but sorry i can't help you
@@zelsuki LMAOOO
@@zelsuki BRUHHH, hahahahaahha Noah already graduated and finished his residency lmaoooo
This may sound stupid, but how do you know the initial temperature of the Cd metal?
I am doing an experiment with Meat and want to find the specific heat and don't understand how to find the temperature before and after of the meat
it's initial temperature is also room temperature.
she put the metal in boiling water to determine the initial temperature of the metal which was 100 C .. the same temperature of the boiling water
you should heat your meat in water until the meat and water have the same temperature and thats would be the initial one
TOK
What are the apparatus used here
Cadmium Metal
1 Scale
1 Bunsen Burner Set
1 150 ml beaker
Water
1 100 ml measuring cylinder
2 calorimeter
1 thermometer
String
1 retort stand
1 ring clamp
1 stirring rod
@@ayonyescamilla9982 thank you
Good job!
anyone knows how to determine the initial temperature of water?? it looks vague when I first see this video.
Stick a thermometer in the water?
Great video great teacher
Massive thanks
yall don't forget to have the correct sig figs. 12 is not the same as 12.0!
what is the answer? I need to make sure the answer I got is right
darude-sandstorm
WHAT? What is Q? what is the value is Q? please someone tell me ASAP!!
Did you not listen? Q represents the quantity of heat applied or energy of heat!
how do you calculate c without having Q that's what i dont understand
@@freddybishay did you ever figure this out?
Freddy Bishay that’s what I’m saying
@@anisahchowdhury3302 i wonder if they ever figured it out...
VERY COOL!!!
Thank you very much
Of course, no problem.
my girlfriend made me watch this and ion even know what’s going on😭😭😭
right there with ya buddy.
still have the girlfriend at least?
Chem lab sent me here, anyone else??
Do anyone have observation from this lab?
Anyone here from Klawender?
Me just imagining what would happen if that metal was sodium XD
While all the other kids are doing the lab. I´m at home watching this. Tis a hard life...
nice
hiii mga klasmeyts!!
What is the answer
I want to know if I'm wright
Hello classmate 😁🙈
0,18925 J/kg °C
really
Using the values she provided, you get a value of 0.28 j/g/°C.
The actual specific heat capacity of Cadmium is 0.23 j/g/°C.
Perhaps more accurate measurements of the temperature would have yielded better results.
Pretty nifty
hERE MY chem. class
im here because of chemistry
im here because of physics.
she was a nice lady
suffer
Q asco nomas por que me lo envió la maestra
hej nu19
sup
Sup
Get some friends
i love school