YOU ROCK!!! my teacher was not doing a great job of explaining this but you NAILED it for me. Thank you 100% I hope you have a wonderful day my friend!
Hi Aqeel..... I am sure you are enjoying them.... Tomorrow's video will be on centroid of shaded regions..... Thats gonna be fun... So do watch it.... All the best.....
Please make a videos like Question Example:- Two blocks of masses M1 and M2 are connected by a string as shown in Figure 5. below Assuming the coefficient of friction between block Mị and the horizontal surface to be u if the system is released from rest, find velocity of the block A after it has moved a distance of 1 m Assume Ml00kg.and M2-150kg and u0.20.
Thank you sir , you have only calculated the centroid position with respect to x axis and y axis but you have not put the centroid position in diagram where both centroid w.r.t x axis and y axis coinside . If we put the centroid point of whole diagram ,is it sure that the centroid point must be within that diagram or it may anywhere?
Sir please tell me I have little bit confusion when you are calculating the base value of triangle so why you only consider the value of rectangle why not semicircle
Sir solve my question emmidiatly a circular hole of diameter 100mm is cut of from a square plate of 200mm*200mm. find the location of the hole, so that the center of gravity of the remainder be 10mm left from the center of the plate
All the best Rahul..... 1. Engineering Drawing (English) : ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing (Hindi) : ruclips.net/p/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics: ruclips.net/p/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Mechanics of Solids: ruclips.net/p/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 5. Theory of Machines: ruclips.net/p/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 6. Machine Drawing: ruclips.net/p/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w 7. Engineering Services Examination_Engineering Drawing_Prelims: ruclips.net/p/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU 8. Physics for Class 11: ruclips.net/p/PLknJ2c9H1euEwtFJLUGZvkjG35OoVvemM 9. Manas Speaks Series: ruclips.net/p/PLIhUrsYr8yHz9g5V7Lw_BA5UXbAbgVyf0 10. Physics Channel Link: ruclips.net/channel/UC_aqx41HWeOebfL6FqBYU6Q My AMAZON Store - For all you students. www.amazon.in/shop/manaspatnaik
You need radius to calculate area. In this problem its 20. 😀Do share this channel and its playlist with your friends. 1. Engineering Drawing Playlist (ENGLISH): ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS 2. Engineering Drawing Playlist (HINDI): ruclips.net/p/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU 3. Engineering Mechanics Playlist (OLD): ruclips.net/p/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS 4. Engineering Mechanics Playlist (NEW 2023-2024): ruclips.net/p/PLIhUrsYr8yHxeypEyVdWeGNxWHjNxU_JP 5. Mechanics of Solids Playlist: ruclips.net/p/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP 6. Theory of Machines / KOM / DOM Playlist: ruclips.net/p/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU 7. AUTOCAD Playlist: ruclips.net/p/PLIhUrsYr8yHyLArdiiSDLa0Fmz8YKIy7G 8. Machine Drawing Playlist: ruclips.net/p/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w Visit Main Channel Page(@manaspatnaikmech) for Playlists on specific topics. Second Channel for Hindi Audience: @btechplus Download the Manas Patnaik App for Premium content : bit.ly/3wMRxoc
![Centroid | Problem No.5 | Engineering Mechanics | [HINDI]](/img/1.gif)
You are helping me in every semester sir last time drawing and now mechanics thanks a lot sir
You are helping in every time sir last time engineering drawing and this time engineering mechanics ...I'm very interested to happy sir☺️☺️☺️
YOU ROCK!!! my teacher was not doing a great job of explaining this but you NAILED it for me. Thank you 100% I hope you have a wonderful day my friend!
sir, you are doing a great job. please can you explain the semicircle again
Due to lockdown, i couldnt able to understand this topic over zoom classes. Your videos and teaching technic are amazing. Thank you so much Manas.
Thankyou so much for this.........pls do continue uploading great videos like these......
This video was really helpful to me sir, thank u very much 😇😇
Hi Aqeel.....
I am sure you are enjoying them....
Tomorrow's video will be on centroid of shaded regions.....
Thats gonna be fun...
So do watch it....
All the best.....
Sir 20-4r/3&
Sir ur videos are asweme it helped me a lot..... during my semester
Thankyou so much, such a educational video you have here all I have is respect for you
All the best Bryl...
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Direct to the point teaching, Thank you sir.
Thank you sir iam a student from LMCS your explanation help me alot ❤❤
Amazing I understand this from your video sir only
All the best.
1. Engineering Drawing (English) :
ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
2. Engineering Drawing (Hindi) :
ruclips.net/p/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU
3. Engineering Mechanics:
ruclips.net/p/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS
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ruclips.net/p/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP
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ruclips.net/p/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU
6. Machine Drawing:
ruclips.net/p/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w
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ruclips.net/p/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU
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Sir u help me a lot, tqq for sending this video
Thanks for u video sir....it helps me a lot
Excellent sir🔥🔥
Thank you so much sir ❤️❤️
Thank you Sir it was helpful and let me have a good understanding!
Tq very much to clearing all of my doubts.. Sir ❤
It's very effective Mannas thanks for that,but can you explain the same lamina diagram without the semi-circle attached to it?
God bless you my friend, this is so helpful
I love your videos sir
I'm glad to have found you
nice video, thank you kind sir! gute bilder benutzt und frei gesprochen
just watched your vd bro.. love that, simple and very nice explanation. thanks lot
Much easier sir, please also do centroid problems for 3D objects.
There is no centroid for 3D objects smh
Very nice sir your concept
Bhai love u bhai
By watching your videos only
I passed engineering drawing in first attempt with distinction marks
Thats great....
Keep learning and GOD Bless....
Thank u sir its really helpful🤩
Very useful sir thank you
This video is very useful for me 😁
Thank u🙂
Awesome as always...!!!!
Very helpful sir Thank you!!!!
thank you sir help me a lot
😃Ha so simple...thanks.
Tq sir very helpful this video
Nice explanation sir 👏
Your videos are are helpful
Thank you for helping us sir 😊 thank a lot ☺️
All the best
After this series please make videos on thermodynamics
i will try...
brother you are Very intelligence
tq sir..
helped me a lot
thanks sir it's really helpful to me
Please make a videos like
Question Example:-
Two blocks of masses M1 and M2 are connected by a string as shown in Figure 5.
below Assuming the coefficient of friction between block Mị and the horizontal
surface to be u if the system is released from rest, find velocity of the block A
after it has moved a distance of 1 m Assume Ml00kg.and M2-150kg and
u0.20.
ruclips.net/video/pKAM2CVdwmA/видео.html&list=PLIhUrsYr8yHwOZxmY63A_lURu6c-jNk-z&index=15
thank you sir it was really helpfull
Engineering Mechanics | Applied Mechanics: ruclips.net/p/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS
Thank you sir , you have only calculated the centroid position with respect to x axis and y axis but you have not put the centroid position in diagram where both centroid w.r.t x axis and y axis coinside .
If we put the centroid point of whole diagram ,is it sure that the centroid point must be within that diagram or it may anywhere?
Excellent 👍 Sir
Sir please tell me I have little bit confusion when you are calculating the base value of triangle so why you only consider the value of rectangle why not semicircle
Tremendous teaching
Usefull video
done and dusted
you rock bro peace
Sir can you solve questions from timoshenko and mariam
Sir I have 3 backlogs in mechanical engineering in 2nd year itself... should I give up BTech and drop out for something else.
Sir from which this problem is ??????? And sir please tell which book you refer for making engineering mechanics videos ????
Yes sir pls tell us .....🙏🙏🙏🙏🙏🙏🙏🙏
This is from engg mech by RK Rajput.
My favourite problem
Sir reference axis is first quadrant u can explain but how could you solve the problem in fourth quadrant
Sir I thought the direction of the x-axis of triangle will 20/3+x2
If we remove the semi-circle and triangle...then what will be the centroid x and y coordinates?
Sir to find centroid of triangle can't we use (x1+x2+x3)/3,(y1+y2+y3)/3 this formula
Sir moment of Inertia ( m I ) na examples upload plz🙏🙏
CG and Mi pan sir upload videos 🙏🙏
Plz sir send me link🙏
Sir but for semi circle can we take x bar as 4×10/3×pi ?
same question for x sub3
sir after doing the calculation the value of x(centroid) i got 70.9 and how do u get in 50s
Super teaching sir
Sir . How you preparing this ppt . Which software you using sir you will guide me . Because I need put in my class
Sir could I know y the centroid of semi circle is at a height of 4r/3π...?
Sir why is it that Y2 was divided by 3 thank you though for the video that really helped
Hello Miss Woods, that's a triangle so the formula for it is h/3...
Hope this clarified your doubt... Thank you. 😊
Super sir thanks a lot
Make videos on moment of inertia bro please
They will be released very soon....
I want,,,, how to find centroid shaded regions....... And the sectors problem
+Sweety Priya
That video will be released tomorrow.
So stay tuned sweety....
All the best.....
Manas Patnaik
..
tq
ruclips.net/user/edit?o=U&video_id=3ZGxZUiT6SI
Manas Patnaik... Tq sir... I under clearly
You are amazing
Sir i dint understand in semicircle why u minesd (-) means 20 - 4r/3pi.
Why 20 mines u have done?
Yes for the triangle should it not be 80-20/3??
This vedio was very help to me thank you sir ❤❤❤
All the best.
1. Engineering Drawing (English) :
ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
2. Engineering Drawing (Hindi) :
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3. Engineering Mechanics:
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4. Mechanics of Solids:
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5. Theory of Machines:
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6. Machine Drawing:
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7. Engineering Services Examination_Engineering Drawing_Prelims:
ruclips.net/p/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU
8. Physics for Class 11:
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Sir solve my question emmidiatly
a circular hole of diameter 100mm is cut of from a square plate of 200mm*200mm. find the location of the hole, so that the center of gravity of the remainder be 10mm left from the center of the plate
Thanks sir !!
Sir I have an one problem???
Sir how is A3 is done. I am getting only 628. 3.14*400/2 = 1256/2 = 628. But in video it is mentioned that 628.31. Pls clarrify sir.
Best one I found
All the best.
1. Engineering Drawing (English) :
ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
2. Engineering Drawing (Hindi) :
ruclips.net/p/PLIhUrsYr8yHx0C3ebAW-FQxTP8ig8-QxU
3. Engineering Mechanics:
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4. Mechanics of Solids:
ruclips.net/p/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP
5. Theory of Machines:
ruclips.net/p/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU
6. Machine Drawing:
ruclips.net/p/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w
7. Engineering Services Examination_Engineering Drawing_Prelims:
ruclips.net/p/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU
8. Physics for Class 11:
ruclips.net/p/PLknJ2c9H1euEwtFJLUGZvkjG35OoVvemM
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Nyz..Sir🤩🤗
What screen recording software do you use sir?
Why do you have to subtract x3 by 20?
Please sir
When will the x or y coordinate of a centroid be zero??
Thanku sirrrr
thank u soo much
Sir why did you divided 40 by 3 in triangular shape
Area of semi circle is 628.57cm sq
And x bar comes out as 44.4cm
Sir i want to ask how to calculate solid body like elbow?
I mean why you don't combine the value of rectangle and semicircle while calculating the base value of triangle
Thank You ❤
i like you sir
All the best Rahul.....
1. Engineering Drawing (English) :
ruclips.net/p/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS
2. Engineering Drawing (Hindi) :
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3. Engineering Mechanics:
ruclips.net/p/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS
4. Mechanics of Solids:
ruclips.net/p/PLIhUrsYr8yHzft7ygw5THZo4aDcsxEadP
5. Theory of Machines:
ruclips.net/p/PLIhUrsYr8yHx0aFXSQvT7nm6ivJSMKnAU
6. Machine Drawing:
ruclips.net/p/PLIhUrsYr8yHzwT06rv7u3tqdfmmKOCz1w
7. Engineering Services Examination_Engineering Drawing_Prelims:
ruclips.net/p/PLIhUrsYr8yHwFTNav_k3EEIvztQEQHilU
8. Physics for Class 11:
ruclips.net/p/PLknJ2c9H1euEwtFJLUGZvkjG35OoVvemM
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I thought the centroid of y2 is 73.33 cuz you have divide the 40 by 3 and add up by 60.
Sir how can you take X3 value as 20.
It is 10 i think , once check it sir
Thanks sir
How did you get the 3 in the 40/3
Thanks
Tq u so much sir
Ab tk exam me aye huye important problems ke solutions
Sir aapne x3 ko 20 me se minus kyu kiya..???
Tq
Tq so much
Why is the x on triangle not = a+b/3?
Sir how to find symmetry
sir in the q i have no area of semi-circle then how i should calculate it
You need radius to calculate area. In this problem its 20.
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