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Straight forward. Classic. I find it hard when my teacher explain it in class. Finally, you hit want I really looking for....
@@JulianTovena 👍👍
@@KSGEngineering Sir You should also provide videos on how to find section modulus and moment of inertia..
@@JulianTovena ruclips.net/video/tsZ8KTqnNFA/видео.htmlsi=RXfcv6VLlNFd7xQwSee this video. It is on the moment of inertia.And this playlist given below has more videos on moment of inertia. Watch these
ruclips.net/p/PLWwWaCiU58HrX_YWZf-R4UG7vRZ573n2K&si=lUQ1ojoJq8vhcMAP
Really nice explanation sir...now I got clarity..on this topic..❤️
God bless you
This channel deserves million of subscribers
Thanks dear. God bless you. Help me by sharing it with your friebds.
Sir, i am already impressed by ur handwriting. Thank you for such a lovely lecture
Thanks dear. God bless you.
Really explained the symmetric concept . Love it 👌💕
Thanks
well explained and keep up the excellent work
Thanks dear. God bless you
sir is there any case you subtract in y1
Sir what is the centroid location of equilateral triangel
From base it will lie at h/3 where h is the height of the triangle. And it will lie on vertical median from base at h/3
Nice explanation sir 👍
Sir I have Kt in in this subject plz help me in preparation
@@mayurjadhav581 just go to playlist section of my channel and watch mec107 engineering mechanics playlist. All lectures are arranged in sequence
@@KSGEngineering Thank you so much Sir
Shall we find x bar
nice explanation
Increase sound it's not audible sir
X1- 0 kaise hoga sir
Kyunki X1 y axis pe lie kar raha hai. So distance between the centroid of area 1 and y axis is zero
Why we can not find x bar
No need because it has vertical axis of symmetry. So centroid will lie on it. Just calculate y bar.
❤
🙂
y bar tho 175 aa raha h sir
No dear it cannot be 175. It should be 125. Do the calculations carefully
love u
Im getting 75 and 75
Don't get
Dhang se padha le
X1 and x2 = 75
Nice explanation
Straight forward. Classic. I find it hard when my teacher explain it in class. Finally, you hit want I really looking for....
@@JulianTovena 👍👍
@@KSGEngineering Sir You should also provide videos on how to find section modulus and moment of inertia..
@@JulianTovena ruclips.net/video/tsZ8KTqnNFA/видео.htmlsi=RXfcv6VLlNFd7xQw
See this video. It is on the moment of inertia.
And this playlist given below has more videos on moment of inertia. Watch these
ruclips.net/p/PLWwWaCiU58HrX_YWZf-R4UG7vRZ573n2K&si=lUQ1ojoJq8vhcMAP
Really nice explanation sir...now I got clarity..on this topic..❤️
God bless you
This channel deserves million of subscribers
Thanks dear. God bless you. Help me by sharing it with your friebds.
Sir, i am already impressed by ur handwriting. Thank you for such a lovely lecture
Thanks dear. God bless you.
Really explained the symmetric concept . Love it 👌💕
Thanks
well explained and keep up the excellent work
Thanks dear. God bless you
sir is there any case you subtract in y1
Sir what is the centroid location of equilateral triangel
From base it will lie at h/3 where h is the height of the triangle. And it will lie on vertical median from base at h/3
Nice explanation sir 👍
God bless you
Sir I have Kt in in this subject plz help me in preparation
@@mayurjadhav581 just go to playlist section of my channel and watch mec107 engineering mechanics playlist. All lectures are arranged in sequence
@@KSGEngineering Thank you so much Sir
Shall we find x bar
nice explanation
Increase sound it's not audible sir
X1- 0 kaise hoga sir
Kyunki X1 y axis pe lie kar raha hai. So distance between the centroid of area 1 and y axis is zero
Why we can not find x bar
No need because it has vertical axis of symmetry. So centroid will lie on it. Just calculate y bar.
❤
🙂
y bar tho 175 aa raha h sir
No dear it cannot be 175. It should be 125. Do the calculations carefully
love u
God bless you
Im getting 75 and 75
Don't get
Dhang se padha le
God bless you
X1 and x2 = 75
Nice explanation