Thank you so much for the tutorial!@~ BTW, I'm getting this mssage at 03:05 After entering "Pithc1" and "=Dead Coil Pitch" the message says "You can not use a quotation mark as a global variable nam. It is reserved character for equation syntax". Could you help to find the solution?
Thanks for the tutorial. This is exactly what I was looking for. I wanted to design a spring with constant pitch and one dead coil at both ends. Is there any other way ?. Thanks
You could set the pitch manually in the spiral feature. It depends on whether you want it to move. You could also try leaving out some of the equations. I like building the spring as shown in the video as you can use it as a template over and over again. Once you have made it once you’ve done the hard work so it’s always available to reuse. I made 3 spring design videos in this series. See if they help.
You can either form the tension spring loops / hooks by adding to the spring wire sketch or by adding them as separate entities using sketches that reposition when the spring coil sketch length changes.
Convert straight tube to helical/conical tube without changing its length. I need to create different tubes with same surface area(2πL), so length is to be kept constant. Can anyone help? Thanks
Hi, Can you tell me, how to solve the below spring details using helix and spiral option (Variable pitch option). Free length - 10.70" Wire diameter- 0.072" Spring outside diameter - 0.955" Total number of coils- 38 Both end has one dead coil and outside diameter of the dead coil is 0.915" Thanks...
Sorry for the slow reply. I tried building this spring without using any equations. Try the following and you should end up with a spring 10.70 inches in height. Draw your template circle to 0.843 inch diameter Set Helix / Spiral to pitch and revolution P1=0.0721 Rev1=0 Dia1=0.843 P2=0.0721 Rev2=0.9 Dia2=0.843 P3=0.2932 Rev3=1.1 Dia3=0.883 P4=0.2932 Rev4=36.9 Dia4=0.883 P5=0.0721 Rev5=37.1 Dia5=0.843 P6=0.0721 Rev6=38 Dia6=0.843 No further region parameters. Dia7 will probably appear with a diameter. As long as its only equal to Dia6 it should be ok. Make sure there is no P7 or Rev7. I've ignored flattening the ends. If you want to grind the ends, make allowance for this in pitches P3 & P4.
Hi, sorry for the late reply. I didn't see this response.Thanks for your help, much appreciated. I have a little doubt in the basics of spring building, *How did you calculate the pitch and revolutions for this spring ?. I am having a little difficult in understanding the variable pitch options in Solidworks.
P1 and P6 are the wire diameter plus minimum extra needed for clearance. If there was no clearance the CAD might error out as the spring length changes. P2 and P5 is guided by how many dead coils you need. I set the revolutions to 0.1 under the requirement to allow for transition to active coils. P3 and P4 are 0.1 revolutions over (p3) and 0.1 under (p4) to allow for transition from dead coil to active coil. The pitch is worked out from taking the working length, deducting the dead coils plus dead coil pitches, then dividing up the length that’s left by the number of active coils. Everything can be worked out if you know your spring length, wire diameter and coil count. Have a play with the spiral feature in CAD to see what works for you. If the spiral length works out wrong it’s usually a sign there’s I mistake somewhere.
Thank you very much for this tutorial. I will help me a lot in my future design projects.
Saved me a tonne of work figuring it out - many thanks!
Thanks for the thumbs up!
Great Job
thanks
Thank you so much for the tutorial!@~ BTW, I'm getting this mssage at 03:05 After entering "Pithc1" and "=Dead Coil Pitch"
the message says "You can not use a quotation mark as a global variable nam. It is reserved character for equation syntax".
Could you help to find the solution?
Thanks for the tutorial. This is exactly what I was looking for. I wanted to design a spring with constant pitch and one dead coil at both ends. Is there any other way ?. Thanks
You could set the pitch manually in the spiral feature. It depends on whether you want it to move. You could also try leaving out some of the equations. I like building the spring as shown in the video as you can use it as a template over and over again. Once you have made it once you’ve done the hard work so it’s always available to reuse. I made 3 spring design videos in this series. See if they help.
@@PDWCreative Thanks for the suggestions..
I have a hard time understanding why we need 6 pitches, as there are in fact only three different. Why twice Pitch X = Pitch Y and so on?
Experiment with less pitches. These are just guidelines that worked to build this spring
Can hook ends be added to this to make a configuration driven TENSION spring?
You can either form the tension spring loops / hooks by adding to the spring wire sketch or by adding them as separate entities using sketches that reposition when the spring coil sketch length changes.
Convert straight tube to helical/conical tube without changing its length. I need to create different tubes with same surface area(2πL), so length is to be kept constant. Can anyone help? Thanks
Hi, Can you tell me, how to solve the below spring details using helix and spiral option (Variable pitch option).
Free length - 10.70"
Wire diameter- 0.072"
Spring outside diameter - 0.955"
Total number of coils- 38
Both end has one dead coil and outside diameter of the dead coil is 0.915"
Thanks...
Sorry for the slow reply. I tried building this spring without using any equations. Try the following and you should end up with a spring 10.70 inches in height.
Draw your template circle to 0.843 inch diameter
Set Helix / Spiral to pitch and revolution
P1=0.0721
Rev1=0
Dia1=0.843
P2=0.0721
Rev2=0.9
Dia2=0.843
P3=0.2932
Rev3=1.1
Dia3=0.883
P4=0.2932
Rev4=36.9
Dia4=0.883
P5=0.0721
Rev5=37.1
Dia5=0.843
P6=0.0721
Rev6=38
Dia6=0.843
No further region parameters. Dia7 will probably appear with a diameter. As long as its only equal to Dia6 it should be ok. Make sure there is no P7 or Rev7.
I've ignored flattening the ends. If you want to grind the ends, make allowance for this in pitches P3 & P4.
Hi, sorry for the late reply. I didn't see this response.Thanks for your help, much appreciated.
I have a little doubt in the basics of spring building,
*How did you calculate the pitch and revolutions for this spring ?. I am having a little difficult in understanding the variable pitch options in Solidworks.
P1 and P6 are the wire diameter plus minimum extra needed for clearance. If there was no clearance the CAD might error out as the spring length changes.
P2 and P5 is guided by how many dead coils you need. I set the revolutions to 0.1 under the requirement to allow for transition to active coils.
P3 and P4 are 0.1 revolutions over (p3) and 0.1 under (p4) to allow for transition from dead coil to active coil. The pitch is worked out from taking the working length, deducting the dead coils plus dead coil pitches, then dividing up the length that’s left by the number of active coils.
Everything can be worked out if you know your spring length, wire diameter and coil count. Have a play with the spiral feature in CAD to see what works for you. If the spiral length works out wrong it’s usually a sign there’s I mistake somewhere.
Thanks sir....Very useful..
Hi can I get help