My goodness. I always struggled with long division, but this video turned out to be the best one to me compared to other solutions I watched!!!!!!!. THANK YOU SO MUCHHHH for showing the process of long division. Now I am confident to do this division. My heartfelt gratitude to you for making out this video to help the students out there.... THANKK YOUU
Yes , sience I watched that ... Its interesting me to further see it more... So please can you solve that:16^3-6x^2-56x+21... Please solve that cubic expression...
Thanks so much for your video! Is a common maths error here the fact that when you expand x^2 with the factor (x-1) that many write x^3 - 2x and then when subtracting it forget to balance out the positive and negative signs (i.e. many people would write x^3 - 3x^2 - x^3 - x^2 instead of x^3 - 3x^2 - x^3 + x^2 - in term allowing for a subtraction result of -2x^2)? Hope this question makes sense and thanks so much :)!
take the constant and find the factors of it, do trial and error and substitute the factors into the expression and see which one equals to zero, for example if x=2 makes the expression =0, den x-2 would be a factor of that expression
Paraneoz to solve this you really need to use the rational roots theorem. It will tell you all of the possible roots and then you check them 1 by 1. It's tedious and boring actually :(. I don't have a video on the rational roots theorem yet but you should be able to find something good online with a little bit of searching. Goodluck and feel free to message me back.
you find the first root, in x^3+4x^2+x-6 for example, 6 is divisible by 1,2,3,6 so you substitute x=(any of those 4 numbers) and if the equations lines up and equals to 0, then that is one of the roots, and you can use long division for the rest
Best explanation ever, didn't miss a single step leaving no confusion.
My goodness. I always struggled with long division, but this video turned out to be the best one to me compared to other solutions I watched!!!!!!!. THANK YOU SO MUCHHHH for showing the process of long division. Now I am confident to do this division. My heartfelt gratitude to you for making out this video to help the students out there.... THANKK YOUU
The long division method is good for those who view division as repeated subtraction.
THANK YOU SO MUCH OMG I CANT THANK YOU ENOUGH FOR THIS
Thank you sir I'm watching this in 3rd April 2024
BEST EXPLANATION IVE SEEN
Very useful and very well explained.
Yes , sience I watched that ... Its interesting me to further see it more... So please can you solve that:16^3-6x^2-56x+21... Please solve that cubic expression...
Amazing explanation😊
Tysm it helped a lot
I was able to find answer of a question in revision for my SSLC exam with ur help....thnx....
Hello I'm replying you to remind you old days where are you now?
Thanks so much sir 👍
Best explanation ever
Friends before doing long division arrange the degree of the polynomial
Eg:x^2+x^3+x change it to x^3+ d^2+x
😜 But good explanation ☺️
Thank you for clarifying
The only problem was with me that how to reduce the product of divisor and quotient on each step which solved now... thanks a lot ❤️
Thank you so much!! Super helpful :)
Thanks so much for your video! Is a common maths error here the fact that when you expand x^2 with the factor (x-1) that many write x^3 - 2x and then when subtracting it forget to balance out the positive and negative signs (i.e. many people would write x^3 - 3x^2 - x^3 - x^2 instead of x^3 - 3x^2 - x^3 + x^2 - in term allowing for a subtraction result of -2x^2)? Hope this question makes sense and thanks so much :)!
Gud way of teaching..
Thank you for this video this was helpful
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If the leading term is has 1 ad constant
Thank you
Thanks bro
Very helpful..... That is good
and if you have to find the root? how you find the root?
just substitute 1 instead of x and if the answer becomes zero then its a root.
THANK YOU SO MUCH
Thank you so much
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what if they have not given the root
take the constant and find the factors of it, do trial and error and substitute the factors into the expression and see which one equals to zero, for example if x=2 makes the expression =0, den x-2 would be a factor of that expression
Broo fr ur good
reviewing for diffeq rn
I've been working on -4x^3+4x^2+11x-6 for hours now, and even after watching this I cant do it, I wonder if I have done a step here wrong or what.
Paraneoz to solve this you really need to use the rational roots theorem. It will tell you all of the possible roots and then you check them 1 by 1. It's tedious and boring actually :(. I don't have a video on the rational roots theorem yet but you should be able to find something good online with a little bit of searching. Goodluck and feel free to message me back.
@@rootmath hi
Bless you🤩💞💯👌
Legenddddddd
so imagine if it was a 2x^3-3x^2-13x+15 instead of x^3-3x^2-13x+15, we would have had to use a 2x-1 instead of x-1?
I needed to find 2 numbers that add up to -4 and multiply to -4 ...
Very helpful
What if they don't give us the root?
you find the first root, in x^3+4x^2+x-6 for example, 6 is divisible by 1,2,3,6 so you substitute x=(any of those 4 numbers) and if the equations lines up and equals to 0, then that is one of the roots, and you can use long division for the rest
👍👍👍