Learning Algorithms Has Never Been This Easy: Crack Any Algorithm Through Stories | Binary Search

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  • Опубликовано: 30 сен 2024
  • Are you tired of traditional methods that make learning algorithms feel like a chore? In this video, I’ll show you a game-changing way to learn algorithms through storytelling! We’re starting with Binary Search, but instead of dry, technical explanations, I’ll guide you through a fun and easy-to-understand analogy using a phone book.
    Learning algorithms has never been this easy. Whether you’re a beginner or just want to sharpen your skills, this approach will help you unlearn the old methods and reimagine how you learn!
    Subscribe and stay tuned for more episodes in this algorithm series, where we’ll cover other essential algorithms using the same story-driven technique.
    Ready to crack any algorithm? Let’s dive in!
    #AlgorithmsMadeEasy #BinarySearch #codingtutorial #tamilnadu #tamil #LearnAlgorithms #StoryDrivenLearning #UnlearnAndMaster #AlgorithmSeries #CodingForBeginners #ComputerScience #TechEducation #MasterAlgorithms #CrackAlgorithms #BinarySearchExplained

Комментарии • 36

  • @65muralikumarj
    @65muralikumarj 8 часов назад +1

    Bro freshers epdi job vangurathu

  • @mithunmahaadevan463
    @mithunmahaadevan463 8 дней назад +5

    Nice hair cut. All the best for the tournament man, stay healthy. Try incorporating meditation as well. Happy to find a person whose thought process is similar to mine like coding, financial literacy, physical fitness. The content was very useful as always. Please try to improve audio, video and thumbnail as well. With the quality of content you provide you will reach much more audience. If possible make a video on freelancing. Cheers !

    • @surya4615
      @surya4615 5 дней назад

      What tournament bro?

  • @Hyps3106
    @Hyps3106 8 дней назад +4

    Bro great video bruh!
    If the input is sorted:
    Two Pointers
    Binary Search
    If there are multiple sorted sequences or the input is sorted:
    Binary Search
    If the problem involves brackets or arrangements:
    Stack
    Queue
    If asked to find the longest, smallest, shortest, etc.:
    Backtracking
    ipdi entha problem enna method use panalam numsollunga bro it would be helpful

    • @jaya_bhuvanesh
      @jaya_bhuvanesh  8 дней назад +1

      More or less correct but yeah we will cover these things in deep

  • @mareeswaran7644
    @mareeswaran7644 3 дня назад

    Nice video bro . waiting for coding explanation 🙂

  • @Naveenkumar-oe3be
    @Naveenkumar-oe3be 6 дней назад

    Hii bro can you please let me know about scaler devops course?

  • @vasuTamizh-ui1kn
    @vasuTamizh-ui1kn 8 дней назад +3

    Thala ;
    1. If mid is equals to it's previous element,
    Start_point= mid+1;
    else
    End_point = mid - 1;
    Thala mid element athoda previous element kooda pair sh irunthuchuna, apo athuku munnadi entha unpaired element um illa, so naama RIGHT move panniklam, apdi illana ithoda pair pinadi irukuna, apo ithuku munnadi tha antha un_paired element iruku.
    Ithu correct ah thala ?
    pathutu sollunga.

    • @jaya_bhuvanesh
      @jaya_bhuvanesh  8 дней назад +1

      You are thinking in the right way but think how index number will change based on the element occurrence

  • @Philomath_CMA
    @Philomath_CMA 5 дней назад

    Hi bro,I've been looking for a job in a top MNC in Accounts and Finance for one year, but I feel exhausted from the search. Could you make videos on how to select an MNC?

    • @jaya_bhuvanesh
      @jaya_bhuvanesh  4 дня назад

      I have already added a video reg this , kindly check

    • @Philomath_CMA
      @Philomath_CMA 3 дня назад

      @@jaya_bhuvanesh thanks a lot for ur response
      I will check

  • @Hyps3106
    @Hyps3106 8 дней назад +3

    array = 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 8 8
    target =7
    step 1 : mid element
    start = 0 end =17
    = 0+17/2
    mid = 8
    array of [8] = 3 which is lesser than target [7] so increase pannanum i mean right side pakanum.
    step 2 :
    8+17/= 12
    mid = 12
    arr[12] = 5 which is not equal to target so again increase panrrom so apa 12 - 17 kulla than answer irukkum again right side pakurom.
    step 3:
    12+17/2 = 14
    mid = 14
    arr[14] =16 again increase it
    step4
    14+17/2 = 15
    mid = 15
    arr[15] = 7 target found

    • @jaya_bhuvanesh
      @jaya_bhuvanesh  8 дней назад +2

      No here the question is to find odd one out element which occurs only once we dont know what that element is

    • @Hyps3106
      @Hyps3106 8 дней назад

      @@jaya_bhuvanesh
      okay bro
      If mid is even:
      If arr[mid] == arr[mid + 1], the odd element is on the right side.
      Otherwise, it's on the left side.
      If mid is odd:
      If arr[mid] == arr[mid - 1], the odd element is on the right side.
      Otherwise, it's on the left side. correct ah bro.

  • @lucifersom6985
    @lucifersom6985 8 дней назад +1

    Welcome back ↩️ thala

  • @Hyps3106
    @Hyps3106 8 дней назад +1

    bro but sorted ah iruntha thaana binary use panna mudiyum if unsorted array question na then sort pannitu binary search panna TC athigam aagume ithukku enna solution

    • @jaya_bhuvanesh
      @jaya_bhuvanesh  8 дней назад +1

      Yeah sometimes data set from the question has to be sorted but for the square root of an number the solution space is sorted right , there you can apply binary search , similarly in number comes only once ,there solution space indexes are sorted , so you gotta think in terms of solution space
      In short solution you are looking for the problem lies in a range then you can do binary search there and get your answer faster
      Kindly see the video again and try to understand this point its very important

  • @nagarajjmr3543
    @nagarajjmr3543 8 дней назад +1

    Engineering aspirants can only get high package comparable to BSC BCA aspirants tell

  • @harinivas5983
    @harinivas5983 7 дней назад

    Bro ithemari example oda ella algorithm kum podunga bro❤

  • @SAKTHI-zr9dw
    @SAKTHI-zr9dw 6 дней назад

    Dsa padikka aasa..but..enga eppadi start panna nu theriyala..dsa ku munnadi java padikava venama..

  • @dhilip77
    @dhilip77 8 дней назад

    Clear explanation, keep sharing your knowledge.

  • @vasuTamizh-ui1kn
    @vasuTamizh-ui1kn 8 дней назад

    Right uhh vilayadumpothu shoe va pathukonga

  • @DarkPrince-tv3sy
    @DarkPrince-tv3sy 7 дней назад

    Bro can u do C programming please 🙏 i can understand your teaching

  • @phantom_dorex_4573
    @phantom_dorex_4573 8 дней назад

    Best of luck bro 👍

  • @Gopi31563
    @Gopi31563 8 дней назад

    Happy to meet you again jaya bhuvanesh
    ❤😊

  • @SasiKumar-k2r
    @SasiKumar-k2r 8 дней назад

    vaa thalaiva vaa thalaiva vaa

  • @hustle4902
    @hustle4902 8 дней назад

    1st like

  • @nagarajjmr3543
    @nagarajjmr3543 8 дней назад

    There is any eligibility criteria to join Scaler