that is a singular real number point, and as such it doesn't change the quantity of the definite integral at all, because the reals are infinitely dense
another way to think about this is, on the cut off versions of these integrals (from 0 to inf), using a right riemann sum approximation limit instead of a left riemann sum, so the first rectangle is defined with the right edge being located at f(x0), meaning the left edge would be at x=0, but wont ever be defined with f(0), as that is undefined. in the limit, the sum of "rectangles" are the smooth definite integrals, but you never used f(0) for any approximation rectangle, so the definite integral isnt defined using f(0) either, but it is still the exact area from 0 to whatever
The boundaries of the integral will be from infinity to infinity since (negative infinity)^2024 = infinity, and when integrating from infinity to infinity it’s just 0
Shop the Xmas Three sweatshirt: amzn.to/4geMKCE
3:45 for those who don't know how to solve it, use feynman technique.
Any integral fans❤️ here?
Me, i use it everywhere
Me 🙋🏻♂️ :)
u in 12th?
Me
been so many years since a integral battle!
Hi bprp, if you want some harmonic stuff: integrate ln(1-x)•x^n from 0 to 1 where n is an integer :^)
This is the stuff I like to see for new years
I love integral much!
Love these videos
Very small portion of pi(e)!
Always fun to watch my favorite teacher
Hello bprp, can you do a video on vector calculus? Perhaps the gradient or something
beautifully apt integrals.
NICE VIDEO SIR 👍
peak battle
Nice!
he's wearing the poster
can you do a video solving: π = ln(x) * 6^(1/x) ?
Super cool
I don't like integrals.
I LOVE THEM🤩🤩🤩🤩
Do a series video
Sometime I don't try an integral because it looks too difficult, today I realized that was a mistake XD
Cool
Left one evaluates to zero if it converges since it's odd!
But, what about the singularity at x=0 ?
that is a singular real number point, and as such it doesn't change the quantity of the definite integral at all, because the reals are infinitely dense
another way to think about this is, on the cut off versions of these integrals (from 0 to inf), using a right riemann sum approximation limit instead of a left riemann sum, so the first rectangle is defined with the right edge being located at f(x0), meaning the left edge would be at x=0, but wont ever be defined with f(0), as that is undefined. in the limit, the sum of "rectangles" are the smooth definite integrals, but you never used f(0) for any approximation rectangle, so the definite integral isnt defined using f(0) either, but it is still the exact area from 0 to whatever
Very clever u-sub.
what is we divide something by 1/0
for example
4/1/0
=4÷1/0
=4*0
=0
is it right?
pls don't say it is🥲.
No
1/0 Is undefined, you can't divide by undefined
@MatteoDolcin-ye8xm let's not do it the traditional way, rather pls tell me if i did something wrong in steps
@100in10thboards
youd have to use a limit as otherwise this is still undefined, but in a limit this would be correct
@@bain8renn i've seen and did many questions in limit and the crazy part they were expected to be solved in limit
But if we don't use or rely on the properties of odd function, how do we reach the answer 0 if u-sub is used instead, like in the case of x^2025?🤔
The boundaries of the integral will be from infinity to infinity since (negative infinity)^2024 = infinity, and when integrating from infinity to infinity it’s just 0
nice
Do 2026 or COS TAN
2026 is just 0 cause odd
i think he knows math, guys
0那個不是CPV嗎？
how int -∞ to ∞ sin(u)/u became π 🤔
Maybe using u.v form we can do it
Lobachevsky, Laplace, maybe Feynman, etc. So not the standard tricks.
I don’t speak english well, but did he mention a video he did before about it?
He did a video a few years ago:
ruclips.net/video/s1zhYD4x6mY/видео.htmlsi=vlmH0A3qICpiJrdL
@@mables8698 Thank you!
You forgot about +c :(
😂😂 its a defined int, u don't need to put +c
🥐
Hi
Integrate[Sin[x^2024]/x,{x,-∞,∞}]=0 It’s in my head.
Integrate[Sin[x^2025]/x,{x,-∞,∞}]=(0.01(0.049382716 recurring))*π=π/2025 It’s in my head.
I wish you would dedicate a series to explaining the Riemann hypothesis.
69 th i am
first
Hii brbp I'm first ❤
HOW THE HELL IS THIS USEFUL IN EVERY DAY LIFE???????!!!!????
No maths, no RUclips or Facebook 😂
🤡
Integration is useful in many physics and engineering applications
W@ need 'ntegrals to calculate the v@st @mptiness inside your sk@ll