Numerical on myopia (Hindi) | Human eye and the colourful world | Physics | Khan Academy

Let's help our friend, Suresh, to pick the right lens for his glasses.
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[@ASanket]

Yes

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Sir aapka awaaz or batane ka tarika bahut accha
Please support this teacher...

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❤

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4:06
Anyone noticed?😎
He wrote sign of proportionality instead of infinity ♾

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Bahut saare videos dekhne ke Baad mil kar Khush ho gya man samajh main aya ab
Thanku so much sir

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I was totally confused in it
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Aap proportional k sign ko infinite bta rahe h.. please correct it
Your teaching way is too good.

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Super sir jhaakaaaaash

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Sir very good explanation.i understand it in my first attempt

[@iqlipse6189]

Thank you so much sir this is really helpful........

[@abeertodi2388]

Simply in the case of myopia
(near - sightedness) ,
Defective far point = Focal length of the corrective lens
For ex -
here , f of the corrective lens =
- 200 cm (- ve for a concave lens)

[@tanmaymeshram8343]

SIR WHY POWER OF LENS IS EQUALS TO THE RECIPROCAL OF ITS FOCAL LENGTH ... SIR PLZ ANSWER SOON AND IF ANYONE KNOWS ABOUT PLZ REPLY WITH EXPLAINATION

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See the previous chapter of physics i.e. LIGHT

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It is a formula

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[@adityamishra2027]

Because power of lens is inversely proportional to focal length and constant of proportionality is 1

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Power is defined as 1/f . Scientist have named the quantity 1/f as power

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Really?

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Because I used audio to text translater 😂😂

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The Khan Academy website provides a FAQ that lists the tools that they use to create their videos:
Camtasia Recorder/Studio ($200)
ScreenVideoRecorder ($20)
SmoothDraw 3 (Free)
Microsoft Paint (Free)
Wacom Bamboo Tablet ($80)

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A lens of focal length 5cm is being used by a student in the lab as magnifying glass his least distinct vision is 25cm what is the magnification

[@Rosee45]

-0.25 =m

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S

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Anand aa gya

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