Numerical on myopia (Hindi) | Human eye and the colourful world | Physics | Khan Academy
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- Опубликовано: 5 сен 2024
- Let's help our friend, Suresh, to pick the right lens for his glasses.
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Yes
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Z
4:06
Anyone noticed?😎
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Aap proportional k sign ko infinite bta rahe h.. please correct it
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Thank you so much sir this is really helpful........
Simply in the case of myopia
(near - sightedness) ,
Defective far point = Focal length of the corrective lens
For ex -
here , f of the corrective lens =
- 200 cm (- ve for a concave lens)
SIR WHY POWER OF LENS IS EQUALS TO THE RECIPROCAL OF ITS FOCAL LENGTH ... SIR PLZ ANSWER SOON AND IF ANYONE KNOWS ABOUT PLZ REPLY WITH EXPLAINATION
See the previous chapter of physics i.e. LIGHT
It is a formula
Aap 12 class me ao .......eeska proof v milega..
Because power of lens is inversely proportional to focal length and constant of proportionality is 1
Power is defined as 1/f . Scientist have named the quantity 1/f as power
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The Khan Academy website provides a FAQ that lists the tools that they use to create their videos:
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A lens of focal length 5cm is being used by a student in the lab as magnifying glass his least distinct vision is 25cm what is the magnification
-0.25 =m
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