Prove that arctan(x) is bounded (ILIEKMATHPHYSICS) (includes a definition of pi)

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  • Опубликовано: 26 дек 2024

Комментарии • 7

  • @nicolastorres147
    @nicolastorres147 17 дней назад +4

    Can you please prove arctan(1) = pi/4 ?

  • @malik-h2e
    @malik-h2e 18 дней назад +2

    That's a great video!

  • @VicTheMathMan
    @VicTheMathMan 18 дней назад +2

    Why you define π as twice the Sup of arctan image ? If the arctan is the inverse function of tan, the Sup being π/2 should not be a proprerty or even a corolary ?
    I'm a little bit confused

    • @malik-h2e
      @malik-h2e 18 дней назад +2

      He defined arctan as the limit of a sequence. We era not using the definition of it as the inverse function of tan.

    • @VicTheMathMan
      @VicTheMathMan 18 дней назад

      @malik-h2e But what is the motivation for the definition of π/2 as the Sup of arctan ? I didn't get It. In the way that he does sounds like we could take any real number as its Sup

    • @malik-h2e
      @malik-h2e 18 дней назад

      ​@@VicTheMathMan I think is that we are only using real analysis references. In that sense, we can't use the geometric definition of pi directly.

    • @Keithfert490
      @Keithfert490 18 дней назад

      The motivation for defining it as pi/2 is that we know is to draw connections to our outside geometric underatanding. All we know in this proof series so far is that arctan(x)