Contact Force Between Blocks With Kinetic Friction - Physics Problems & Examples

This physics video tutorial explains how to solve contact force problems between blocks with kinetic friction and without friction when the system is under constant acceleration by an applied force and when the masses are moving with constant velocity / speed. In some cases, the coefficient of kinetic friction may be provided. This video contains plenty of examples, practice problems and the equations / formulas needed to solve the contact force of block 1 on block 2 and the force exerted on block 3 by block 2 and vice versa. This video focuses a lot on newton's third law of motion which states that for every action force, there is an equal an opposite reaction force. This video also uses newton's second law of motion which equates to the formula net force equals mass times net acceleration.
Normal Force Problems:
• Normal Force Physics P...
Elevator Physics Problem:
• Elevator Physics Probl...
Net Force Physics Problems:
• Net Force Physics Prob...
What Is a Normal Force?
• Physics - What Is a No...
Static Friction and Kinetic Friction:
• Static Friction and Ki...
____________________________
Contact Forces:
• Calculating Contact Fo...
Tension Force Problems:
• Tension Force Physics ...
Types of Forces:
• How Many Different Typ...
Inclined Planes:
• Introduction to Inclin...
Simple Machines:
• Simple Machines - The ...
______________________________
The 4 Fundamental Forces:
• The Four Fundamental F...
Physics Forces Review:
• Static & Kinetic Frict...
Final Exams and Video Playlists:
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Full-Length Videos and Worksheets:
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[@TheOrganicChemistryTutor]

Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
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[@xenyk]

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Watched these videos to help study for my physics exam and I got a 95! Thanks for your help!

[@khushisomerhalder9193]

In which grade are u??

[@bruhtendr392]

@@khushisomerhalder9193 11th I presume

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[@samanhashim9651]

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You are fabulous
Iwas trying to understand this concept for literally 2 hours and then you came ohhhhhh too good yr

[@samisiddiqi5411]

1) Find Total Force
2) Find Total Acceleration
3) Find component Net Forces
4) Find the force of exertion by calculating Net minus Component.

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[@shanifkp8107]

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[@vaibhavbohra4308]

it help me to understand all concept of contact point system

[@kevink1391]

Just trying to cram all this in before my AP physics final

[@xaratyniz]

Excellent dude. Gracias keep up the great work

[@thescientifichacker9399]

Thank you soooo much Bro. Tomorrow I got an important test and I was total goner until I found this video. Thanks man.

[@blehtron3733]

Hi.
For the second example, you said that the amount of force M2 exerts on M1 is 35N.
Should not it M2 and M3 exert a force of 35N on M1?

[@zitscx886]

This is exactly what i wanted

[@user-fj1st8hu1e]

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[@hihihihi778]

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[@aneeshvaidya7838]

Thanks a lot

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[@simpachowdhury5064]

it's really helpful for students

[@brethagen7776]

I get 2 block problems with a single force on one of them. Seems like some of these give you so much extra information.

[@user-xm3xx3ch4f]

Thanks very much!

[@lakshaya]

its clear all my concepts that u so much

[@archie851]

okay but why contact force has not changed.....i mean it will be 27N even if there is no friction and is 27N when friction is there in the last example.....please explain

[@geetathombare1577]

Thank you bro I loved this video

[@PhuongAnhNguyen-ei4mu]

You save my life

[@sureshareddyhuleppa6111]

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[@GuruRam77678]

You don't make sense at 6:41, you said at the numerator,the force that has is being pushed should be on top,but the force that block 1 applies on 2 is 2*45/9=10N not the block being pushed=3*45/9=15N.

[@breancas]

This was a tremendous help!!!

[@kayth1373]

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[@navyasinghal1143]

THANK YOU SO MUCH! Helped a lot! :)

[@aashunisar1172]

its really helpful thanks

[@maryammumtaz5839]

Thanks a lot Sir

[@saptarshimajumdar180]

in the last problem the 24 N for is the resultant force on the blocks. Then why is frictional force taken into consideration when we are calculating the final force. i think it is wrong

[@anjumakthar9550]

Thank U so much

[@095seihafathima9]

Your amazing
Most comments are so old here

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[@anilathane6023]

Excellent

[@mohithota2198]

thank you sir. please also explain for 3 block friction problem kept one over another.

[@SyahmieHazren]

mohit hota i think the first explanation of three blocks was wrong it should wrote F2,1 not F1,2

[@willynilly3703]

If someone would make these videos but they get straight to the point and are no longer than two minutes

[@MrShagification]

So, in the situation where all the blocks have the same mu with the ground, you can calculate the forces they exert on each other as if there were no friction forces, right?

[@jasminetaank4847]

Life saver ♥️

[@lucaswilliams1019]

Bruh it took me 2 hours and I still didn’t understand and you taught me in 5 minutes

[@jd54541]

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dy/dx

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நன்றி

[@GuruRam77678]

You don't make sense at 6:41, you said at the numerator,the force that has is being pushed should be on top,but the force that block 1 applies on 2 is 2*45/9=10N not the block being pushed=3*45/9=15N.

[@arslanyaqoob9534]

In third problem, if you use formula for contact force then
Force exerted by m1 on m2 and m3=24*9/12
Shouldn't it be this??

[@amanjthomas4779]

thank u

[@architecturedigestor]

My savour for life

[@srinivasulunarayanadas6547]

What is the net force of the 1st object when there are objects are attached

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Killed it

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[@thotamanisankarabhishek9079]

Super dued

[@vishalsgoyal2812]

There's a question I am not able to solve, can you please help me with it?
Q. 3 blocks of mass 1kg, 4kg and 2kg are placed on a smooth horizontal plane. A force of 120 N is applied from the left side and a force of 50 N is applied from the right side. Calculate the contact force between 1 kg block and 4 kg block.

[@creativityking4649]

Net force on the system will be 120N-50N (if you take left applied force positive).

[@debbaranyabiswas1102]

is it 40N?

[@kojustine]

makasih bang

[@kephen4270]

gw juga mau bilang makasih bang

[@GuruRam77678]

You don't make sense at 6:41, you said at the numerator,the force that has is being pushed should be on top,but the force that block 1 applies on 2 is 2*45/9=10N not the block being pushed=3*45/9=15N.

[@ishaperry8878]

at 6:47 how did he get the contact force of block 2 on block 3? Why is it not 30 N, (45-15)

[@scientisthustler3857]

what if the constant force and the accelaration is unknown? and only the total mass is given.

[@scientisthustler3857]

what I mean is, what if the external force is unknown. we are also asked to find the acceleration. only the contact forces between block 1 and 2 are given.

[@thilakhathurusinghe7835]

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cool

[@joshuaflores5741]

Why is there "
Acceleration due to force" when you said there is no acceleration if velocity is constant?

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(Better than a HIGH RANKED UNIVERSITY PROFESSOR

[@m.abubakar2867]

Its awesome! But why is that so? Like we got HOW to calculate but why exactly we do that?

[@iitjeeboy1965]

Abubakar M that comes by experience...

[@nowpanicing9992]

What if there’s friction on the table

[@eric-wo1pp]

late but use example 3

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👌

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Please use a proper mic. These lectures are needed for students like us but voice is ruining them.

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Thanks !