If you mean the dimensions to find the minimum area, then that's because the minimum area would be 0. Imagine that I took the fencing and created a long enclosure that was really thin. So thin, in fact, that nothing could fit inside of it. That would be the minimum area. The dimensions of such an enclosure would be 0 by 300.
Thank you. My test is tomorrow. This helped a lot
i have a test on this in an hour u saved me thanks
Very-well explained!
but how did you find the 2W and 4L thou???
Count the horizontal line, then the four vertical lines on the diagram
Helped alot!! Only thing is that you talk wayyy too fast haha
How did you get 0 for x and not 2?
what is the area?
where did the extra x came from, im a bit lost
It gave idea of ax^2 + bx + c
I can tell mr. james is canadian
lost...
the width could still be more than 150
why don't you discuss how to find the minimum dimensions for the rectangle???
If you mean the dimensions to find the minimum area, then that's because the minimum area would be 0. Imagine that I took the fencing and created a long enclosure that was really thin. So thin, in fact, that nothing could fit inside of it. That would be the minimum area. The dimensions of such an enclosure would be 0 by 300.
Niceeed
❤️
Ur too fast?
You include so many unnecessary things in the video. Maybe that’s why it’s so fucking long