Sir in CIP rule 180 rotationaout plane is not allowed in CIP rule while check S1 in cyclobutane sigma plane it rotation in 180 out plane to know symmetry but this S1 out of plane cannot applied in Determination R/S configuration and to check chirality
I shall be offering a new course on Structure, Stereochemistry and Reactivity of Organic Compounds and Intermediates: A Problem-solving Approach (due to start in Jan 2021) where problems on symmetry and point groups will be discussed.
First of all, the correct name of the compound is cis-1,3-dichlorobutane. It has 2 sigma planes ...one plane perpendicular to the ring plane and passing through C1- and C-3; the other is also perpendicular to the ring plane and passing through C-2 and C-4. There are 2 S1 axes. one axis passing through C-1 and C-3 and the other axis passing through C-2 and C-4. You can verify by rotating the molecule through 360 degrees along the axis and take a mirror image with the mirror placed perpendicular to the axis of rotation. You will find the similarly looking molecule. Hope, it clears your doubt.
He is a professor at a reputed institute and this is a collective effort by NPTEL to make these courses available for free to everyone. No need to support them.
Sir, but you have said that in Meso Tartaric acid it is having chiral centre but is doesn't show optical activity at all. so u introduced a new terminology Stereogenic center .thus, sir am I correct? That the chirality is not necessary in all the cases as u already mentioned in that video
meso-tartaric acid has a plane of symmetry in its fully eclipsed structure and a centre of symmetry in its anti form; it is not chiral and hence does not show any optical activity. Please remember, presence of chirality centre is not a condition for a molecule to be chiral, there are many other molecules like allenes and biphenyls etc that show chirality and hence optical activity. The necessary condition for chirality (and hence optical activity) is that the molecule should be dissymmetric (absence of sigma (=S1), i (=S2)and Sn). I hope this clears your doubt.
Sir in your all vedios no need subtitles, it distracted a lot. Sir Pls remove the subtitles in your all vedios. This is very very humble request sir. Pls sir.
Truly speaking sir u simply change the way to understand stereochemistry ❤️❤️
India will be developed country when educational video's like this will trend at 1 or 2. You may say that it's cinematical but it's true!!.
sir great love for your way of teaching
So great teaching, I am a physics major and I understand these concepts thoroughly, thank you sir!
Sir your teaching is wonderful. You are like MIT professors , even better than them .
Sir...the way you concluded this class is superb. Wish you good health and long life. Thank you.
GREAT GREAT GREAT GREAT Explanation sir..................................................all doubts about chirality is cleared now
truly exceptional...wish I came across these earlier
Thank you so much Sir for teaching this topic
Thank very much sir. You made the concept very simple
Happy Birthday to you Sir. Wonderfull classes these are.
Thank you Aditya...I also wish you a bright future ...take care.
Thank you so much ,Sir. You make topics easy to understand.
It's really helpful 😊🙏.
i see many of lecture in english but sir This is great
Clear explanation.easy to understand.
Sir in CIP rule 180 rotationaout plane is not allowed in CIP rule while check S1 in cyclobutane sigma plane it rotation in 180 out plane to know symmetry but this S1 out of plane cannot applied in Determination R/S configuration and to check chirality
Thank you so much sir, I understand very well about stereochemistry
great work sir
Please list by number of topic
Beautiful
Really nice class Sir
Thank you sir 🙏
Sir....point group detection in which class?...and problems of symmetry elements...in which class you discussed?
I shall be offering a new course on Structure, Stereochemistry and Reactivity of Organic Compounds and Intermediates: A Problem-solving Approach
(due to start in Jan 2021) where problems on symmetry and point groups will be discussed.
Super class 😍love from kerala
Super fine..
god🙏
Supr class sir
Sir in 2,4 cis chloro cyclo butane, s1 is absent but sigma is present. Why sir?
First of all, the correct name of the compound is cis-1,3-dichlorobutane. It has 2 sigma planes ...one plane perpendicular to the ring plane and passing through C1- and C-3; the other is also perpendicular to the ring plane and passing through C-2 and C-4. There are 2 S1 axes. one axis passing through C-1 and C-3 and the other axis passing through C-2 and C-4. You can verify by rotating the molecule through 360 degrees along the axis and take a mirror image with the mirror placed perpendicular to the axis of rotation. You will find the similarly looking molecule. Hope, it clears your doubt.
@@amitbasak4819 thank you sir
Thanks sir
Is this sufficient for iit jam exam....... Plz tell me sir.... Or anyone......... 🙏
Is there any way to support you financially?
He is a professor at a reputed institute and this is a collective effort by NPTEL to make these courses available for free to everyone. No need to support them.
Thank u sir....
sir if a molecule is chiral, will it be optically active . i mean is chirality a necessary condition for showing optical activity?
Not in all the case
Yes, to show optical activity, the molecule has to be chiral
Sir, but you have said that in Meso Tartaric acid it is having chiral centre but is doesn't show optical activity at all. so u introduced a new terminology Stereogenic center .thus, sir am I correct? That the chirality is not necessary in all the cases as u already mentioned in that video
meso-tartaric acid has a plane of symmetry in its fully eclipsed structure and a centre of symmetry in its anti form; it is not chiral and hence does not show any optical activity. Please remember, presence of chirality centre is not a condition for a molecule to be chiral, there are many other molecules like allenes and biphenyls etc that show chirality and hence optical activity. The necessary condition for chirality (and hence optical activity) is that the molecule should be dissymmetric (absence of sigma (=S1), i (=S2)and Sn). I hope this clears your doubt.
@@amitbasak4819 Thank u so much sir🙂 ..you cleared my doubt cent percent.
Thank you sir
Thanks for inside story
sir lecture 3 is missing
Is it still not available?
@@amitbasak4819 Sir are these videos helpful for jee advanced?
Sir in your all vedios no need subtitles, it distracted a lot. Sir Pls remove the subtitles in your all vedios. This is very very humble request sir. Pls sir.
Go to the captions and turn off.Then subtitles will be removed.
Lec2