I think there is an error at 4:20? You have done current multiplied by voltage (1uA x 3.6V), and then have said this is 3.6uAh? That is not correct, you have just calculated the power that the leakage is drawing, that is all (3.6uW). (and even this is only approximate since the battery can change from 4.2V to 3.0V in most single-cell Li-Ion cases). You can then use this, multiplied by 24, to get 86.4uWh as you have done. And again, you can multiply by 30 to see how many Wh over a month, so 2.59mWh per month. But this is in Wh (which is actually a good thing). To get mAh (which is only an estimate, since the voltage can vary), you didn't need to do the multiplication by 3.6V in the first place. There was no need (multiplying by voltage is only needed to go from Ah to Wh). To do this accurately, it needs to be measured and integrated over time, not just multiplied. But for 90% of cases, multiplying by the cell nominal voltage is fine for Wh conversion.
Oops, yes, you are right. This is a mistake. Thanks for pointing it out. It's watt-hour and not AH. Let me see how can I correct it in the existing video else I will upload a new one with correction.
@@PallavAggarwal But regardless, a great video - thanks for sharing Pallav. I have designed many systems, and have never factored in these losses before. Hope I do not seem negative in my comments. This is excellent content. I do not think you need to correct it, people can see from my comment and that is fine.
@@scottwilliams8539 Thanks for pointing it out. I really appreciate it. I will now be more careful with the slides :), need two more eyes for review. Regarding why I have taken 3.6V as the voltage, just to make it easy to understand. It was said in the video as an average voltage. wH is important because power is the ultimate parameter and power over time. Ah alone is not enough when estimating battery backup time. Because your battery could be of any voltage say dual cell 8.4V, then you have more capacity and more battery life.
![YoungBoy Never Broke Again - Sneaking [Official Video]](http://i.ytimg.com/vi/1ILUps2zDFU/mqdefault.jpg)
Thank You Sir, Very useful information..
Important topic you have picked up and explanation is also good to educate us.
Thanks Pallav
Thank you. Glad you found it interesting. More videos are on the way :)
I think there is an error at 4:20?
You have done current multiplied by voltage (1uA x 3.6V), and then have said this is 3.6uAh?
That is not correct, you have just calculated the power that the leakage is drawing, that is all (3.6uW).
(and even this is only approximate since the battery can change from 4.2V to 3.0V in most single-cell Li-Ion cases).
You can then use this, multiplied by 24, to get 86.4uWh as you have done.
And again, you can multiply by 30 to see how many Wh over a month, so 2.59mWh per month.
But this is in Wh (which is actually a good thing).
To get mAh (which is only an estimate, since the voltage can vary), you didn't need to do the multiplication by 3.6V in the first place.
There was no need (multiplying by voltage is only needed to go from Ah to Wh).
To do this accurately, it needs to be measured and integrated over time, not just multiplied. But for 90% of cases, multiplying by the cell nominal voltage is fine for Wh conversion.
Oops, yes, you are right. This is a mistake. Thanks for pointing it out. It's watt-hour and not AH. Let me see how can I correct it in the existing video else I will upload a new one with correction.
@@PallavAggarwal But regardless, a great video - thanks for sharing Pallav. I have designed many systems, and have never factored in these losses before. Hope I do not seem negative in my comments. This is excellent content. I do not think you need to correct it, people can see from my comment and that is fine.
@@scottwilliams8539 Thanks for pointing it out. I really appreciate it. I will now be more careful with the slides :), need two more eyes for review.
Regarding why I have taken 3.6V as the voltage, just to make it easy to understand. It was said in the video as an average voltage.
wH is important because power is the ultimate parameter and power over time. Ah alone is not enough when estimating battery backup time. Because your battery could be of any voltage say dual cell 8.4V, then you have more capacity and more battery life.