Second-Order Passive Low-Pass and High-Pass Filters

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  • Опубликовано: 14 дек 2024

Комментарии • 12

  • @megacycodes
    @megacycodes 26 дней назад

    thank you

  • @DarrenDIY
    @DarrenDIY Год назад

    The way you explain is very intutive, thanks,
    Would love to see a video on second order filters using rc cct

  • @mechmania8450
    @mechmania8450 Год назад

    Takes me back to HNC days. But I need to design a symetrical filter (will work both ways ) However the output and input impedances could be different which would have to be taken into account. This could probably mean the resistances would be different. Many thanks for the explanation.

  • @marinaarsuaga1181
    @marinaarsuaga1181 10 месяцев назад

    Hi! When you do the module of H(jw), wouldn't it be (1-LCw^2)^2 - R^2C^2w^2? Since we are doing j^2 = -1. Let me know if I am wrong.

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041  10 месяцев назад

      No because I am not doing "j^2" for calculating the magnitude of a complex number. I just need to take the imaginary component which is RCW in this case, square it and add it to the square of the real part (this is the definition of magnitude that I have explained in the different video). Hope this helped.

  • @andreasandreou2651
    @andreasandreou2651 7 месяцев назад

    no sound\

  • @nhathapham7115
    @nhathapham7115 7 месяцев назад

    can't hear anything

  • @pathToHaven
    @pathToHaven 2 года назад +2

    Can't hear anything dude

    • @electricalengineeringmadei1041
      @electricalengineeringmadei1041  2 года назад

      I just tested the video. I don't see any problem with the sound!

    • @pathToHaven
      @pathToHaven 2 года назад

      @@electricalengineeringmadei1041 i increased playback speed maybe that's why