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Thank you sir!!! It is easy to understand because of your teaching style.

thank you

Thank you bro literally carrying me

love this chanel. Big thanks for making these vids!

Thank you! This video helped me out.

Super helpful!

Great presentation. Thank you. But what op-amp will I need for hf ?

Great video!

Thank you sir

Do you have this blok?

is it a second order circuit

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can't hear anything

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love it.

One of the purposes of use of an opAmp is now made it clear, well done. Thank you very much.

Are you writing everything backwards from your point of view? That’s impressive!

I know you're applying inverse Laplace, but I still got lost where the Ks came from... more over, if I had to know the values at a specific time, how will I solve those Ks?

man, you are criminally underrated:( Absolutely incredible explanation. Wishing you a lot of success

Hi! When you do the module of H(jw), wouldn't it be (1-LCw^2)^2 - R^2C^2w^2? Since we are doing j^2 = -1. Let me know if I am wrong.

Thanks

Shouldn't the last term in the equation be V_1/20 instead of V_1/45 (at 17:20)? Since the last term is equal to I_phi?

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Awesome video! Your channel is underrated.

Do you have a video which explains almost all types of diodes?

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Takes me back to HNC days. But I need to design a symetrical filter (will work both ways ) However the output and input impedances could be different which would have to be taken into account. This could probably mean the resistances would be different. Many thanks for the explanation.

thank you so much sir. where did you take that example ?

I know that the solution of a differential equation depends on its form. Does this differential equation (L di(t)/dt + Ri(t)/tau = Acos(wt)) have the same solution as the general one (dy(t)/dt + y(t)/tau = Acos(wt)) if there is a constant multiplied by the differential term (L*di(t)/dt)? Or does this constant indicate that the differential equation is not of the same form as the general one? Must we divide by L and take tau to be L/R so the equation becomes di(t)/dt + (R/L)i(t) = (A/L)cos(wt) so that the differential equation matches the general form? Or does this not work because now the amplitude becomes A/L instead of A, the given amplitude?

Hi sir, thanks for your helping us to get better marks. I have a question about the equations in time between 22:30-23:00. We said that i2=i3 and also i3=i4. From the first equation we get V2=-V3 but from the second one, we get 5V3=3V2. Is there something that i might have missed? Best regards.

The way you explain is very intutive, thanks, Would love to see a video on second order filters using rc cct

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I like this

This video series has been very helpful in my Linear Circuits course I'm currently taking. You are even using the exact same textbook as my Professor! Thank you for uploading these.

🙏namaste from India, this series of lecture from your channel are gems. Thanks for making such excellent videos.

hello professor , at 17:34 I couldn't quite understand that V1=Vi . I would be happy if you answer.

great video thank you

Thank you!

Thank you !!!!

hello professor, I have a question on labeling circuits how do we choose the direction of the currents and how do we decide the positive- negative parts of the voltages and currents This problem has been messing with my head and I couldnt find an explanation that I can grasp well. Thank you for nice lectures .

You can continue with you a very necessary theme

Can't hear anything dude

excelent !!! wish you the best with your channel ⭐⭐⭐⭐⭐

Thanks for working out the formula to finding the impedence formula in S-Domain. This really clarified any questions and doubts I had. 👍

mamnoon :)

Just a side note: Classes in school are always exclusively a subject. Just math or just physics. What students need is something that is like a Math/physics class, because after we study just math for a semester, then the next semester just physics, we can't remember all of the math that goes along with the physics so we never see the important connections, of using our math skills to solve real problems. If it was mixed we would learn both of them, because we used all of our skills. I assume you are a professor, so if you agree with me maybe you can pass it down the line. I'm not sure if it is your intention, but watching these videos is what I've needed in an algebra class my whole time in college. Algebra class never took it this far or made it this real and applicable. With these videos I feel like I'm getting two things done at once. I see you simplify things, and sometimes you skip a lot of algebraic steps, but it's what I needed to make those skills solid. When I get stuck on your steps I stop the video and figure it out. Plus I'm learning circuits. Sorry for the long message, but I hope one day schools start to mix classes. I don't know if that's your intention but it's perfectly what I needed. Thanks.

correction: iL(0)=24mA+A1+A2=0

For I(2) I was a little confused. You got conductance for I(2) over conductance for I(3) and I (4)? But the conductance for I(2) is the resistance of I(3) and I(4)? Then total conductance was the added resistance? Does that mean when resisters are parallel that the conductance of the first one is the resistance of the other? If not, I don’t know why you used all resistance values as conductance. Thanks

Hello, there is one thing I am confused about in this video. You are using kilo ohms, but would it make a difference if you used ohms? Is it the same because it's always a ratio multiplied by Vs?

I assume by the end of all the lectures we will understand how you draw in the air.