Diffraction Grating Problems - Physics

This physics video tutorial explains how to solve diffracting grating problems. It explains how to calculate the second order angle given the wavelength of light used in nm and the number of lines per centimeter of the diffraction grating. It explains how to calculate the wavelength of light given the angle of the third order bright fringe. Finally, it explains how to calculate the number of lines per centimeter of a diffracting grating given the wavelength of light and the angle of the second order bright fringe. This video contains plenty of examples and practice problems on diffraction grating.
Ray Diagrams:
• Ray Diagrams
The Huygens Principle:
• Huygens Principle - Ph...
Young's Double Slit Experiment:
• Young's Double Slit Ex...
Single Slit Diffraction:
• Single Slit Diffractio...
Diffraction Grating Problems:
• Diffraction Grating Pr...
Polarization of Light Problems:
• Polarization of light ...
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Brewster's Angle:
• Brewster's Angle, Pola...
Planck's Constant and Blackbody Radiation:
• Planck's Constant and ...
Photon Momentum and Effective Mass:
• Photon Momentum and Ef...
Wien's Law:
• Blackbody Radiation an...
Compton Effect & Wavelength:
• Compton Effect and Com...
Physics 2 Final Exam Review:
• Physics 2 Final Exam R...
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[@TheOrganicChemistryTutor]

Final Exams and Video Playlists: www.video-tutor.net/

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[@anoopkrishna20000]

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[@geoffphillips8183]

Hi, great vids! Quick question if d=1/N , N = number of lines per meter ,for example, d= slit spacing… then are we counting the end edge of the diffraction grating as 1slit? Take a diffraction grating of 1m with one line ( slit) in the middle, we know slit spacing is 0.5 m … we know there are 2 slit spacings & 1 slit. But applying the formula without counting end edge as 1 slit we get o.5 = 1/1 … instead of 0.5=1/2 ( counting the end edge as a slit. ) I hope this makes sense.. thanks 🙏

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[@gamezr4losers]

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[@abhaysuji8052]

(c) Another diffraction grating has half the angle between the first and second order light beams when light of wavelength 532 nm is incident upon it. Estimate the number of lines per mm of this second diffraction grating. [2]
The initial grating has an angle of 7.8 degrees difference between theta 1 and theta 2

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Thanks 👍

[@abdulaiman23]

mantap geng

[@sheldonfrancis7830]

Could make to find the total number of orders of diffracted light? Should the angle be Zero? (dsine 0= m lamda?)

[@Hirwan1889]

What is the distance between fringes produced by a diffraction grating having 139 lines per centimeter for 590-nm light, if the screen is 1.50 m away?

[@wobblyjohn]

Error in defining 'd' at 1:27.

[@swastikpal7230]

the second question u did the wavelength did not fall in the visible range - so how can we see the interference pattern?

[@IonizedComa]

Literally watching this 20 mins before my test

[@ashwinnnnn]

is it m lyamda in both bright and dark frindge?

[@ruchijaiswara2028]

In q no. 3 m getting a diff. Answer for d

[@BitterTast3]

How would the math change if the slits weren't all evenly spaced?

[@connorbellamy8742]

I did this and got 1.1x10^8 but my lines were 500 per mm and the order was second and the angle was 24.8 what did I do wrong

[@jsc3417]

can you do some overlapping problems?

[@remake3693]

what if I need to calculate the order... how do I do that?

[@renfoley5747]

im a year late but.... you gotta rearrange the equation so m is the subject.
i.e. (d*sin(theta))/lambda (wavelength)

[@uddimishra151]

at 1:10, does "m" correspond to minimums or maximums? because m0 seems to be at the central maxima, however m1 and m2 seem to be minimas. Could someone please help me out.

[@qwertykeyboard8563]

By my understanding, M1 and m2 are maximas

[@orekoyaelizabeth9863]

Pls I think there’s a mistake with the conversion from centimeter to meter cos while solving am getting a different answer from yours.

[@dorabinga1101]

im getting 100 he made a mistake

[@mishakireev6195]

Love u

[@Zeewanzeewan]

isn't cm to m Divide by 100? Then why you multipled by 100? stucked please reply

[@TheOrganicChemistryTutor]

yes. To convert cm to m, you need to divide by 100. However, it's the reverse when converting 1/cm to 1/m. You need to multiply by 100. 100 cm = 1 m.

[@Zeewanzeewan]

Yes I got it. I'm a big fool. Thank you so much

[@thai27]

is there any difference between slits/m and lines/m sir

[@reki_kun0725]

nah slits is just the difference between the gap and the other border its the same thing

[@geoffphillips8183]

Hi , sorry I’ve always been confused by the formula d=1/N … see previous msg .. thanks

[@anitaku5153]

Why did you use the equation with sin when the d is very small, I thought you use tan when d is very small 4:26

[@faryalhuma9522]

What the hell is this like n=length/no of lines so how this n suddenly equals to 1/d ???? What's this ?can you please reply me because may be my concept is built wrong.

[@deandramiller8025]

I need assistance doing a physic work.. someone please help

[@naomikumson9684]

Why do you do you do x10-9 on wavelengths

[@melissafigueroa4218]

Naomi Kumson cause The wavelength is (ie 540nm) and 1 nm= 10^-7m then 100nm=10^-9

[@wowshamanful]

@@melissafigueroa4218 *1 nm= 10^-9m *

[@waiitwhaat]

I used to be HELL scared of diffracting gradients. Man those were really easy. Trick is to not be intimidated by the question.

[@cerengulyuz119]

first question, wavelength was 650 why did it become 650x10^-9 ? pls im so confused

[@ImtiazAli-mh8nb]

the initial wavelength was in nm, u have to convert it into meters for calculation

[@harishankarvishwakarma2941]

If there are 15000 lines per in a grating find the grating element

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2:26 anybody else hear the intro for Phineas and Ferb?

[@harishankarvishwakarma2941]

Answer Abhi chahiye

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Hey! Do u know the difference between diffraction and diffraction grating?

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[@syedzamanmehdi2855]

Thank you so much