How to Solve Thin Film Interference Problems in Physics
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- Опубликовано: 6 окт 2024
- An explanation of thin film interference, constructive interference, destructive interference, and index of refraction, and then some practice problems.
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Ive been stuck for literally hours, your video cleared it up in 30 min. Thank you!
Happy to help! Thanks for watching!
I have watched like a dozen videos on thin film interference and this is by far the best one. Builds such a good foundation on the subject, i somehow got all my homework after this
Wow, thanks for the compliment! Where's the award for "Best video on Thin Film Interference"?
Watching this 2 hours before the AP Phys 2 exam, this helped so much!
Good luck!
Thank god I found this in time man...my head was spinning as to why we were switching the formula of constructive and destructive this whole time... Thanks a lot!
Believe me, I wish I knew this sooner too, haha
What a brilliant and straight forward explanation, you're saving lives !
I’m not a doctor. I’m just your normal everyday supertutor.
😀I join Matt-Holdren's comment. I've been stuck trying to solve one exercise for hours, but thanks to your video I was finally able to solve it. The formula and solution method you showed are very clear and easy to remember. I am wondering why it's not explained so clearly in my physics book... Thank you very much!!!
You’re godsend. You made the topic very easy to understand.
Thankyou so much sir!!. Best video for film interference
Thanks! Happy to help!
best video out there on thin film interference. period. thank you a trillion
Thanks for the stellar review!
Thank you so much Dan. You've saved my life.
No problem! Next time, you can save my life.
this was so helpful, thank you so much! I have my physics midterm in a couple hours
Simple and beautiful explanation!
Best tutorr everrr.. i dua you all the best hocamm
Thanks! Appreciate it
Thank u, u saved my life before finals
No prob. Now go crush that exam!
absolute guy for this
perfect teacher and better then our school teacher
Really setting a low bar there… haha thanks!
You are superb ❤ thank you very much very helpful
Thanks! You’re not half bad either.
Thank you Dan. So is
m = 0,5 considered totally block
and if m= 4,84 is just weakened
m=4,2= weakened
m=6 amplified
I am trying to figure out wether something is amplified or not
m= 2tn/ λ
n=film= 1,8
t=0.7*10^-6
m= 420nm, 520nm,590nm,720nm
On a water surface, there is a thin layer of another liquid with a refractive index of 1.80. The thickness of the layer is 0.70 micrometers. Upon reflection of perpendicularly incident white light, some of the light will be maximally strengthened and some of the light will be maximally weakened.
For which wavelength(s) of 420 nm, 520 nm, 590 nm, and 720 nm will the light be
a) maximally strengthened?
b) maximally weakened?
You are great 👍🏼....... Jst cleared my mind
Thanks! Glad to hear it.
Most other videos the wavelength in the formula is taken as the wavelength of the film ,, why you take it as the wavelength of the light???
I was bouta ask the same question
@ Dan the tutor
@hussienbast2342 collegeboard says to use wavelength of film so I’d just do thT
Great explanation, thank you I finally understand this now lol
Thank you!
thanksss i understood it very well !!
i finally understand now !!! thank you!
thanks sir, good vid
Glad you enjoyed!
great video thanks for the help!
Best teaching
For us non physics people, what exactly is a phase shift?
Let me bestow some knowledge to you: light moves like a wave. Just like a sin or cos wave from math class. And so when we say there’s a phase shift, we’re talking about moving the sin graph by exactly half a period (half a cycle). It doesn’t matter if you move the graph left or right because it’s symmetric and it will look the same no matter what.
Thank you much!
There's a point I don't really get it. How can I know there is actually 1 lambda in 2t? if light is blocked out, there's probably 2 lambda in 2t, therefore the answer of thickness might be tow times of yours
Which problem are you talking about?
@@danthetutor2624 thin film interference thickness measurement
Wouldn’t you have to change your wavelength to the wavelength in the film?
I see what you're saying. I think that makes logical sense, but every physics problem I've ever seen doesn't do that. So I'm inclined to say "no, don't change the wavelength" but I don't have a good reason why.
legend!
Dan the tutor❤️
the best love this
2:25 Could you please inform me why we need the smallest value possible and when will we use the greater values?
Good question. Usually, the question has some wording like "minimum thickness", and that means that you use the smallest value for m. You'll notice that my questions did not say that, so technically you can use the larger values for this video.
The only time you NEED the larger values is when the question says something like "what are the first 3 thicknesses that will work?" In that case, you'd use the first 3 values for m (for instance m = 1, 2, 3)
@@danthetutor2624 But why do we need the greater values in the second scenario; I don't have an intuitive feeling for it. Besides, I don't walk with you in the notion of "you can technically use it". What do you exactly mean by this? Will I get the same results even if I use larger values?
It's because there are infinitely many answers to the thickness question, depending on what value you use for m. So for instance the answer could be 1 meter thick, 2 meters thick, 3 meters thick, etc. That's why most problems will say "minimum thickness".
I say "technically" because I meant to put in the word "minimum thickness" but I forgot. So any value of m would work. But most problems will not forget to say that.
Ur the best
Correct
brilliant
niceeee
save my life
that's what I do
He didnt explain anything
He explained everything lol
mwa 💋