Single Slit Diffraction - Physics Problems

This physics video tutorial provides a basic introduction into single slit diffraction. It explains how to calculate the width of the central bright fringe and the angular width in degrees given the separation distance of the single slit, the wavelength of light used, and the distance between the slit and the screen.
Ray Diagrams:
• Ray Diagrams
The Huygens Principle:
• Huygens Principle - Ph...
Young's Double Slit Experiment:
• Young's Double Slit Ex...
Single Slit Diffraction:
• Single Slit Diffractio...
Diffraction Grating Problems:
• Diffraction Grating Pr...
Polarization of Light Problems:
• Polarization of light ...
____________________________
Brewster's Angle:
• Brewster's Angle, Pola...
Planck's Constant and Blackbody Radiation:
• Planck's Constant and ...
Photon Momentum and Effective Mass:
• Photon Momentum and Ef...
Wien's Law:
• Blackbody Radiation an...
Compton Effect & Wavelength:
• Compton Effect and Com...
Physics 2 Final Exam Review:
• Physics 2 Final Exam R...
_________________________________
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Full-Length Videos and Worksheets:
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[@TheOrganicChemistryTutor]

Final Exams and Video Playlists: www.video-tutor.net/

[@DudeWhoSaysDeez]

You have a video for every topic that I am ever stuck on. Thank you 🙏🏻

[@minimarsed]

english isnt even my native language but this is what im resorting to because i have no clue what my teacher is saying, thank you for this man

[@anjani3652]

You are saving my whole degree ✌

[@joeramirez9042]

Mark Wahlberg gonna help m get this A

[@__ICT__1288]

U taught this topic better than my actual teacher, thanks

[@elishi6805]

you should make a video on thin film diffraction !

[@katlegokokoana3476]

God bless you bro... you just made prepared for the physics test.

[@mojo6112]

So how'd you do?

[@sudukikellington3594]

Thank u. You are amazing!

[@SquatSimp]

You are awesome thank you

[@daliaalshawi9907]

Thank you you are amazing

[@mojo6112]

10:38 that's physics for ya.

[@AghahaseebullahkhanSindhi]

Please answer 🙏
Consider a slit of width a producing a diffraction pattern, if 'm' is either positive or negative integer than diffraction minima occur under the conditions
1- M-lamda = a sin
2- 2M lambda = a sin
3- m lambda = 2 a sin
4- (2m+1) lambda = 2 a sin

[@pikachu5188]

At 9:31 The angle (Theta1) should be in degrees and not meters.

[@thai27]

yes boy

[@TwistedKrizZ33]

Thank you so much

[@kuttygundalchannel5455]

Thank you

[@randychong8770]

Thanks

[@richardrivaldo6941]

hello how about phasor and I-y diagram for 4 slits interference?

[@ramaghalayini8282]

Thanks ! This helped me a lot🤩

[@xXishibashiX]

This video gives me but a "whiff" of hope

[@manuelsojan9093]

At 9:33 why is the angle in meters??

[@kamfei4774]

You are right, why is that angle in meter? hahaha maybe it's some careless mistake up there...

[@RaneMatthew]

You're correct, it should have been in degrees. The value itself though, is correct :)

[@luckyprosperity6408]

thanks!

[@aaryansrivastava7835]

thank you :)

[@amnaumar7803]

for dark fringe, shouldn't m be a decimal value like 0.5, 1.5, 2.5 etc?

[@vladimirsheydorov3776]

This what I am confused about, in some book examples I saw m being an integer for destructive interference and in some for constructive??? So annoying...

[@vladimirsheydorov3776]

Never mind, for single slit destructive interference m is integer and for multi-slit constructive interference m is integer

[@TheLover6731]

I thought since the angle is bigger than 10 degrees then we cannot use the formula
y1= Ltan(theta) because it may be used for small angles.
Therefore, wouldn’t we use the formula y=L(m+0.5)lambda/d to find y1? If so, then the distance of the central maximum would be equal to 1.43m.

[@casbox2667]

I think n+0.5 is what I've learned in class as well

[@MegaTiffanym]

Why didn't you convert the 1.6 cm to meters to be consistent with the rest of the units?

[@nirelleksenasitchoa7652]

When you say to use the second formula if theta is really small, what range would you suggest for theta? (anything less the 5 degrees?)

[@alainfabrice5094]

I almost left without liking the video 😅👍

[@piglink10]

0:43 For double slit, wont the bright fringes all have the same intensity? (Same amplitude). The one which you drew isnt it for single slit ?

[@raajkumar8039]

Yup

[@ethanhope9935]

why does destructive interference happen on single slit?

[@mashanatanzon557]

On question one, shouldn;t the answer be 0.952m? We know that theta = lambda/slit width. And that lambda is = opposite over adjacent, making (680x10^-9)/(2x10^-6)=(W/2)/1.4. Resulting in width = 0.952m. Thank you for clarifying this!

[@estherguberman6710]

I got the same answer

[@BlazinblaiserVods]

Why do we do this is Radians and not Degrees when finding the angle?

[@isaitalvarado5727]

what does theta need to be smaller than in order to be small enough to use the (y)(d)=(L)(m)(lamda)?

[@RelevantDad]

Because of how that equation is derived. It is created by assuming that sin(theta) equals tan(theta), which is a close approximation for very small angles.

[@schenzur]

9:33 why aren't we multiplying theta by 2

[@fauzansyauqi2815]

why must?

[@jackwilson4710]

He didn't need to because he halfed the width to get y1

[@blackart2539]

Sir how to relate wavelength and intensity in single slit

[@husnaadibah5924]

I guess it's something related to interference?

[@olympichigh9014]

resolution questions?

[@thai27]

In example 2, why m is 1 sir

[@Benjicmm]

10:15 theta = 0.122 meters?
shouldn't it be in degrees?

[@nemuirostorageroom]

spent 4 hours watching my prof's lecture, and I feel like I have a brain fog. Literally 1 minute into the video (the part where he says the amplitude of the bright fringe decreases progressively), I went "OHHHHHHHH".

[@matthewkoob7600]

what a god

[@samb.7395]

@9:35 it should be degrees not meters

[@lilianawong4819]

can we assume that sin(theta) is = to y/L? For the first problem I paused the video and solved for y first and got a completely different answer. Isolating y I got:
y= (m*lambda*L)/d = 476m ?
Or can I only assume that with double slits? please anyone respond T.T

[@boofmonkey5455]

maybe

[@derekliu4917]

9:40 your theta should be in degrees

[@oscarobioha595]

ahh thank u!.
I was scrolling to look for someone who caught it

[@lojfiojo4725]

Isn’t theta 22?

[@macavmoudbhawanxutra876]

Can you solve jee advance paper?

[@p.n1453]

I want explanation the greatest nation

[@souvikdeyiipcmbi1496]

man my teachers say that intensity remains constant for ydse but u are saying different plx help

[@nabiha5772]

intensity does not remain constant in a single slit diffraction, that's experimentally proven that the bright fringe in the centre is the brightest and the farther you go fringes/light get dimmer. You can have a rough observation on that in a dark room with partially closed door and bright light outside

[@rushvi1611]

i thought as it's a minumun it would be sinø = ((mlamda)/2)/d

[@oscarobioha595]

single slit is different

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try this new 2 edge diffraction setup, over 100 nodes can be seen: ruclips.net/video/HFDs85cEiKI/видео.html

[@arhumnaveed1320]

whatta g

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I just don't understand a single topic idk why

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😁

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Penty

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[@nknm]

Thank you so much! These videos are *literally* a lifesaver. Every time I turn to this channel it has exactly what I'm looking for.

[@masrur_qr]

Thanks