Angular motion variables | Moments, torque, and angular momentum | Physics | Khan Academy
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- Опубликовано: 8 июл 2024
- In this video David explains the meaning of angular displacement, angular velocity, and angular acceleration.
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Bear in mind something can be travelling in a circle with constant speed but because its direction is changing as it travels, the direction of its velocity is changing and hence it is accelerating. So something going around a circle at a constant speed is accelerating. You might ask in which direction is the acceleration, well it's towards the centre of the circle. However if you're talking about Angular Velocity, then something travelling at constant speed in a circle has no Angular acceleration.
this channel deserves way more recognition than physicswallah
THE POINT Y WE USE DEGRESS TO DEFINE ANGULAR MOTION WAS NEVER EVER TAUGHT BY MY TEACHER AND I USED TO BE FED UP LIKE Y SHOULD WE LEARN THIS ONLY NOW I UNDERSTAND THIS..THANK YOU
KHAN ACADEMY
@huge youtuber and standalone educator: FYI this is the third time this video has helped me: High school, college, and now studying for a license. So... thanks. :)
perfectly explained rapper who make me understrand physics.lots of thx
Awesome explanation...i have never seen such a great video...u clear my concepts
Amazing explanation
Great explanation Sir David!
Best explanation ever seen.....hatts off guys......
thank you that really helpful
thank you!!! you explained it so elegantly !
Murgi
Great info but explaining radians before actually using them would be helpful
Thank you so much Khan Academy
Nicely explained..
Thank you so much
Thanks, Rapper.
Thank you so much, it really helped me a lot
Hi! im also a physics teacher and i'd like to know what software did you use to make the animations move in real time, that would be of great help in my classroom. I highly appreciate the help, thanks!
Google it sis
Ing. Danny Colcha little late. But smoothdraw4 and a bamboo tablet which just allows them to draw instead of use a mouse
it's autotesk sketchbook pro
tq khan adademy
superb explanation
👏Awesome 😃🤩
I love you
Thank you ❤️❤️❤️❤️❤️❤️❤️❤️
You are simply awesome. Really helpful
Wonderful, I love you khan academy
R u watching it now
The Angular Acceleration: "alpha" 𝛂 = 1.57rad/sec ➗ 4sec = 0.3925rad/sec².
I think he accidentally divided 1.58 by 4 giving 0.395.
What software are you using
hello, can someone please tell me why the angular acceleration is 0 when there is constant angular velocity? if the direction is changing then shouldn't velocity (cause it's a vector) also change, hence creating an acceleration? i understand the magnitude is not changing, but not the direction part?
angular (not centripetal) acceleration begins @4:46
Is angular displacement a scalar or vector?
0:16 exhilaration->acceleration
Xiao Bo-Wen ii
I dont understand how you got 1.57 rad/second for Wf at the end
It was a given for the problem. He did not solve for it, instead it was given similar to the 4 seconds being given for the time.
Let's assume that we don't know the Wf, but we know that it travelled pi radians in 4 seconds. Using the formula for angular velocity, we'd get that the average angular velocity, would be pi/4 [radians/s].
There is a second way, for finding the average angular velocity: take the average of both velocities at the beginning, and at the end! This means: wavg = (wf+wi)/2. We know, that the average angular velocity is pi/4 radians. We know our initial velocity, which is 0 [rad/s]. As such, we can find wf=
wavg=(wf+wi)/2 ---> wavg=(wf/2)---> wavg*2=wf---> (pi/4) [rad/s]*2= pi/2[rad/s], and that is equal to 1.57 [rad/s].
Note, however, that this only works assuming the velocity increases at the same rate throughout the whole distance it is travelling (in other words, the angular acceleration is constant).
Hope this clears things up!
anyone studying this in grade 9th?
i'm doing college physics and this has come up in our studies