Thank you ma'am👏 this video is very helpful from the exam prospective. Your chemistry is outstanding.. Your channel is help to make chemistry very easy... Specially 2nd year chemistry Thank you 😊😊 so much..
@@Leah4sci you're welcome.. these words comming from my heart 💓, l really appreciate you, to be honest, you have a gift that our good Lord put it in you is that, your single word in explaining any problems in organic chemistry makes more sense, meaning and your Vocal voice is quite cool where it diffuse in to our minds easily without spending much time.. gifted, humble, humility,respect, potential are now your character because Leah4science.. can explain more concerpt in less time so gifted and talented, will explain not too fast or too quite but in good middle mood so humble, humility and in respectful manner,,, thanks Leah for imparting knowledge in to my brain... I Simon Peapo from NEW GUINEA ISLAND (PNG) major in chemistry 3rd year student from university Of Papua New Guinea
Super late and may not be helpful but NaBH4 is only a mild and selective reducing agent, and reacts with esters very slowly at room temp which is why it may not react with the ester.
When dealing with a weaker reducing agent, you have to consider anything on the molecule that will compete or prevent the reaction. In the case of an ester, the extra oxygen's resonance makes the carbonyl carbon less reactive/less accessible. Only a stronger reducing agent can attack, a weaker one will not be able to
Hey Leah, while explaining the mechanism you said Boron contains a negative charge but if we see the electronegativity chart the Hydrogen has electronegativity of 2.1 which is slightly more than that of Boron's (2.0). Therefore, the charge on hydrogen should be partially negative as it will pull the electrons from Boron on which charge should become partially positive. Can you please explain why you represented a negative charge on Boron? Great Explanation by the way!!
Yes, of course! I said that boron has a formal charge of -1. That's because it is surrounded by one more electron than what a typical boron atom would have in its valence shell. I do recognize that hydrogen is more electronegative, and you'll see I explain that the hydride is negative around --0:40--. You can think of BH4^- as a neutral BH3 attached to a negative hydrogen atom, for the purposes of this reaction. To read more about formal charge, you can see my tutorial at leah4sci.com/formal-charge-formula-and-shortcut/
@@Leah4sci I have some questions, u can help me. When react alcohole with thionyl chloride to product alkyl halide what are catalyst and solvent I will use for this reaction
I think adding NAOH is to deprotonate hydrogen From the compound that you have use in lab,,, where oh ion will act as nucleophile by deprotonating H from compound
That's not exactly what this video covers. But as a base, NaOH is a proton acceptor and will choose to pull a proton from another compound, when possible.
I had a lab where we reduced an Imine with NaBH4 and during this step in the lab there was bubbling (and also dissolving of the imine in the solution it was in). I was wondering if hydrogen gas was a by product of the reduction and caused the bubbling. Might hydrogen gas come from this? and if more info's need i could probably delve into it more
I'm sorry but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
In the example with 2 carbonyls why is the aldehyde reduced and not the ketone? I have an example where the structure has a ketone and a carboxylic acid and I'm not sure which one will be reduced.
This example does not have a ketone. Rather, it has an aldehyde group along with an ESTER. An ester is much less reactive than an aldehyde. In fact, its carbonyl group is only weakly electrophilic. Since NaBH4 is a weak reducing agent, we see it selectively choose the ‘easier’ carbonyl to reduce. In this case, that’s the aldehyde. Hope this clears it up for you.
I don't believe that particular reaction is discussed in this video, and unfortunately I do no offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
why is everything neglecting the fact that after abstracting the hydride off of borohydride that the rest will actually bond to the oxygen since the carbonyl oxygen still has free electron pairs to fill the electron deficit of bor. this mechanism is too basic because the cool thing of borohydride is its ability to do this kind of reaction up to 4 times. so using it in reactions you have to be careful with how many equivilants you really need. seems like i dont find the answers i am looking for.
It sounds like you're in an advanced organic chemistry class or beyond. This video is meant for undergraduate students looking to learn the basics of this mechanism for pen-and-paper chemistry. I hope you are able to find the advanced explanations you're looking for
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
U always talk about go back and go back , from where the hell i will search for the videos and waste my time . why dont u upload all the videos in detail on utube ..... i often use to search on ur boring website .. waste of time take action on my comment .. adviced freely ..
I appreciate you taking the time to let me know that you're finding it difficult to go back for the other referenced videos, and for letting me know that you find my website boring. I get that it's not for everyone and that's ok. I strive to make the best videos and resources and accept that not everyone will find it helpful, but as long as some students do, I will continue making these videos. As for where to find resources, they're always linked in the description so you don't actually have to go hunting on my website
I can’t thank you enough, been trying to find a mechanism video like this for the last hour 😭🙏🏼
Glad the video helped!
I just came across your channel as im studying for my lab and I can't say this enough, this is SUCH a good video !!! thank you !!!
Awww, thanks for your kind words! Glad you like it!
thankyou so much
finally someone who cleared this doubt effortlessly
love from india
So happy to help you!
I have a lab on this In an hour :) this makes a lot of sense now!
Same here!
Glad to help!
Thank you so much for such a great video! Actually I never thought about the Mechanism of NaBH4, Its great to know for MCAT!
You're very welcome, happy to help!
Wish I've discovered your channel back when I had second year chemistry! Great video!
Better late than never. Glad you enjoyed it!
@@Leah4sci you guys are studied this at second year .
I am studiying this in 12 th class .
For entrance exam called Jee advanced
Thank you for your nice education, It's really useful to me as a student of engineering college in Korea
Glad it was helpful!
Hi Leah, your videos are truly helpful and useful in all ways.. Organic chem seems to make more sense now..
Awesome, so glad you think so!
thank you! it' s very easy to understand your teaching. It's help a lot
You're very welcome, happy to help!
Thank you ma'am👏 this video is very helpful from the exam prospective. Your chemistry is outstanding..
Your channel is help to make chemistry very easy... Specially 2nd year chemistry Thank you 😊😊 so much..
Thanks so much for your kind words, and you're very welcome!
Legend 👏 explained well, even elementary kids can be able to understand it.. thanks gifted
Thanks so much for your kind words, I appreciate it!
@@Leah4sci you're welcome.. these words comming from my heart 💓, l really appreciate you, to be honest, you have a gift that our good Lord put it in you is that, your single word in explaining any problems in organic chemistry makes more sense, meaning and your Vocal voice is quite cool where it diffuse in to our minds easily without spending much time.. gifted, humble, humility,respect, potential are now your character because Leah4science.. can explain more concerpt in less time so gifted and talented, will explain not too fast or too quite but in good middle mood so humble, humility and in respectful manner,,, thanks Leah for imparting knowledge in to my brain... I Simon Peapo from NEW GUINEA ISLAND (PNG) major in chemistry 3rd year student from university Of Papua New Guinea
Very good explanation! Thank you very much!
Thanks! You're welcome Kaio! :)
this video explains the science not leaving out any information. very good! thank you :)
My pleasure, glad it was helpful!
Thanks Leah, like your explanations always .Keep going on.
You're welcome! Will do!
your didactics are so good, amazing video!
Thank you, after having to google didactics, I'm humbled and honored as that is something I strive for every day
@@Leah4sci aah you deserve it, it's such a hard skill and you do a really incredible job :)
Very Clear ~~ thank you !
you're welcome!
Great video. At 3:37 why will it reduce the aldehyde and not the ester?
Super late and may not be helpful but NaBH4 is only a mild and selective reducing agent, and reacts with esters very slowly at room temp which is why it may not react with the ester.
@@kc4648 Thanks a lot sir/mam for your explanation. I got it.
When dealing with a weaker reducing agent, you have to consider anything on the molecule that will compete or prevent the reaction. In the case of an ester, the extra oxygen's resonance makes the carbonyl carbon less reactive/less accessible. Only a stronger reducing agent can attack, a weaker one will not be able to
Your videos are always remarkable! Thank You! :) :)
You're welcome :)
This video was helped me big time. Thank you
You're welcome!
Thank you
Nice explanation
I am from India ❤❤❤
You're welcome. Happy to help.
Hey Leah, while explaining the mechanism you said Boron contains a negative charge but if we see the electronegativity chart the Hydrogen has electronegativity of 2.1 which is slightly more than that of Boron's (2.0). Therefore, the charge on hydrogen should be partially negative as it will pull the electrons from Boron on which charge should become partially positive. Can you please explain why you represented a negative charge on Boron?
Great Explanation by the way!!
Yes, of course! I said that boron has a formal charge of -1. That's because it is surrounded by one more electron than what a typical boron atom would have in its valence shell. I do recognize that hydrogen is more electronegative, and you'll see I explain that the hydride is negative around --0:40--. You can think of BH4^- as a neutral BH3 attached to a negative hydrogen atom, for the purposes of this reaction. To read more about formal charge, you can see my tutorial at leah4sci.com/formal-charge-formula-and-shortcut/
Great video, I´m from Argentina and I couldn´t find an explanation for NaBH4
Glad it helped!
Thank you... Very helpful clz
You're welcome 😊
Excellent video
Glad you liked it!
This video is very nice.
Thank u so much for this video
You're welcome!
@@Leah4sci I have some questions, u can help me.
When react alcohole with thionyl chloride to product alkyl halide
what are catalyst and solvent I will use for this reaction
Thanks i needed to check if ch3ona was indeed forming.
You're welcome
ur video made my day
Glad I could help :)
Hi Leah thanks for your video..Really helped me a lot. What would be the purpose of adding NAOH to the solution during lab?
I think adding NAOH is to deprotonate hydrogen From the compound that you have use in lab,,, where oh ion will act as nucleophile by deprotonating H from compound
That's not exactly what this video covers. But as a base, NaOH is a proton acceptor and will choose to pull a proton from another compound, when possible.
Thank you 😇
You're welcome!
I have a question, what do you mean by looking for a nucleophilic attack rather than basic? *isn't a nucleophile a base? 1:08
not exactly! They can be but the definition is determined by context
I had a lab where we reduced an Imine with NaBH4 and during this step in the lab there was bubbling (and also dissolving of the imine in the solution it was in). I was wondering if hydrogen gas was a by product of the reduction and caused the bubbling. Might hydrogen gas come from this? and if more info's need i could probably delve into it more
I'm sorry but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
In the example with 2 carbonyls why is the aldehyde reduced and not the ketone? I have an example where the structure has a ketone and a carboxylic acid and I'm not sure which one will be reduced.
This example does not have a ketone. Rather, it has an aldehyde group along with an ESTER. An ester is much less reactive than an aldehyde. In fact, its carbonyl group is only weakly electrophilic. Since NaBH4 is a weak reducing agent, we see it selectively choose the ‘easier’ carbonyl to reduce. In this case, that’s the aldehyde. Hope this clears it up for you.
thank u so mush for this
you're very welcome
Hi, can i ask a what is the major product for the reaction of sodium borohydrite with propan-2-ene. Thank you!
I don't believe that particular reaction is discussed in this video, and unfortunately I do no offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
nice lectur
Glad you liked it
Thank you for the video, I forgot about the Na + ion hahahaha
Can't forget that! Glad I could help
why is everything neglecting the fact that after abstracting the hydride off of borohydride that the rest will actually bond to the oxygen since the carbonyl oxygen still has free electron pairs to fill the electron deficit of bor.
this mechanism is too basic because the cool thing of borohydride is its ability to do this kind of reaction up to 4 times. so using it in reactions you have to be careful with how many equivilants you really need.
seems like i dont find the answers i am looking for.
It sounds like you're in an advanced organic chemistry class or beyond. This video is meant for undergraduate students looking to learn the basics of this mechanism for pen-and-paper chemistry. I hope you are able to find the advanced explanations you're looking for
Thank you you save me
you're very welcome
Thank you
You're welcome
Does NaBH4 reduce Ketal and Acetal?
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
good
thanks
Nice video
Thanks!
MAM , NaBH4 in ACIDIC Methylene blue how to react . mam if you have solve this reaction then mentioned me plz on the vadio
I have no plans to do a video on that anytime soon, sorry
if acid and ester both functional group present in one molecule... BH4 react with acid not ester why????
see the video comparing LiAlH4 to NaBH4 in this series: leah4sci.com/redox
😍😍😍nice
Thanks 🤗
Can I cite this ?
Yes, just give full credit to my channel.
which Bond will Break In Butanone By Oxidation...Tell Me which Bond and also with Reason..Anyone here
For help with this question and more, I recommend joining the orgo study hall. Full details: leah4sci.com/join
@@Leah4sci thanks Mam
truly amazing
Glad you like it!
Come teach at Wayne State University, the lead professor for our lab sucks.
Sorry your professor isn't ideal, but why would I limit myself to teaching at one school when I can help more people by being on RUclips ;)
Chemistry exam tomorrow. Lets have some fun
How'd it turn out?
Sodium has a weak reducing agent
I’m sorry, but I don’t understand your question. Is there a specific point in the video you are concerned about?
Suprrrr......❣️❣️
Woohoo!
Easy as pi (bonds)
lol!
👏👏
Glad you like it!
This shits crazy
Crazy awesome :)
oi
Hope you liked the video!
Your voice is like the girl who says...
Hey you yes you! 😂
hahaha! thanks? I hope the video helped you.
@@Leah4sci don't get offended I was actually talking about the girl in adult sites.😅
U always talk about go back and go back , from where the hell i will search for the videos and waste my time .
why dont u upload all the videos in detail on utube ..... i often use to search on ur boring website .. waste of time take action on my comment .. adviced freely ..
I appreciate you taking the time to let me know that you're finding it difficult to go back for the other referenced videos, and for letting me know that you find my website boring. I get that it's not for everyone and that's ok.
I strive to make the best videos and resources and accept that not everyone will find it helpful, but as long as some students do, I will continue making these videos.
As for where to find resources, they're always linked in the description so you don't actually have to go hunting on my website
thank you so much!!!
You're very welcome!