Moment of Inertia of a Sphere, Derivation

This is a derivation of the moment of inertia of a solid sphere, where the axis of rotation is through its center.
I hope that you enjoy the video! Please comment with any questions or suggestions for future videos!

[@TheAnarchist99]

What an in-depth and clear explanation , it helped me clear up my doubts better than my professor. Thanks

[@archandutta348]

Professor? Isn't class 11 Physics to be done in school

[@-TOLINSKI]

Thank you! your explanation is detailed and clear! cheers

[@hourlongagate9360]

Helped me write my physics with calculus final God bless you

[@mayyousayhd5967]

Thank you
I think there is a mistake denoting dI as (1/2) r^2 dM
since I is integral of dI, and not (1/2)I

[@caleblarsen4967]

the I of a disk is 1/2r^2M, so dI is 1/2r^2dM

[@nimaalz4513]

why 1/2 ???
@@caleblarsen4967

[@tonikpayc]

​@@caleblarsen4967 why is it that moment of inertia I = r^2 dM = r^2 dM /2

[@noobkilla3]

Thanks a lot for the explanation!

[@rasuru_dev]

Wow thanks, this is very clear

[@gastonbaeza4969]

Excelent! tnks!

[@samudrajs5409]

Thank you

[@yawt3836]

I don't really understand the breakout

[@eivor6882]

thnx

[@dylanbrookbank1935]

Holy i got a lot of work to do

[@luukpieter2001]

you sound like nate from the office, but thanks

[@nathanmiranda8917]

Speak louder pls

[@diogogoncalves200]

you can turn up your volume, I suppose than can solve your problem!

[@tonikpayc]

How is it that we have I = r^2 dM = r^2 dM / 2 ?

[@mlachin3873]

thank you

[@kustin4208]

man the best explanation out there, thank you so much

[@tamirelazr]

Thank you