If f=0,then it gives XL=0, which means no impedance which is short circuit ,not open circuit. Similarly, if f=0, then Xc=infinite, which means infinite impedance that is no current flows ,it is open circuit.
Sir, initially since the inductor is unable to accept sudden changes in current, and if no current has been passed through it due to the previous circuit, it will act as open, but when steady state has reached, XL = 0 for dc , so that inductor will act as a short circuit. Similarly, initially since the capacitor is unable to accept sudden changes in voltage, and if it has not been charged initially due to the previous circuit, it will act as short, but when steady state has reached, Xc = infinity for dc , so that capacitor will act as an open circuit,
Hello sir, when you talk about multistage amplifier, you said coupling capacitor is open circuit incase of dc. Here you are telling short circuit incase of dc. How come?
Reactance infinite means it won't allows the current And also as you said if inductor won't allows the dc means how the inductor charged by the capacitor's dc current????
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If f=0,then it gives XL=0, which means no impedance which is short circuit ,not open circuit.
Similarly, if f=0, then Xc=infinite, which means infinite impedance that is no current flows ,it is open circuit.
Wonderful lecture sir. I completed it on 02-12-2022
And your way of teaching very good sir your way teaching are helping us to keep our knowledge more better
Thank you for taking this subject Electronic devices and circuits in 3rd sem. Please take full topic in lesson 3,4 and 5
Lesson 3,4 and 5 please Sir🙏🙏🙏
Genius professor you are sir ❤
Sir, initially since the inductor is unable to accept sudden changes in current, and if no current has been passed through it due to the previous circuit, it will act as open, but when steady state has reached, XL = 0 for dc , so that inductor will act as a short circuit. Similarly, initially since the capacitor is unable to accept sudden changes in voltage, and if it has not been charged initially due to the previous circuit, it will act as short, but when steady state has reached, Xc = infinity for dc , so that capacitor will act as an open circuit,
Hello sir, when you talk about multistage amplifier, you said coupling capacitor is open circuit incase of dc. Here you are telling short circuit incase of dc. How come?
Same doubt ..? Ungaluku answer theriyuma..
@@nithyananthamr2799 same doubt..? Ungaluku answer theriyuma..
wonderful explanation sir :)
Reactance infinite means it won't allows the current
And also as you said if inductor won't allows the dc means how the inductor charged by the capacitor's dc current????
Nice explanation sir, thx for this video
thank you so much sir.
Super explanation
Relays and is types patina vedios konjam podunga sir
Sir why sir the positive charges from capacitor discharges to down side of inductor
Initially no charges and xc in the capacitor so it is act as short circuit current flow. Than charged capacitor act as open circuit no current flow
நன்றி sir
thank you sir.
Sir ஒரு சந்தேகம்Inductive Coil openCircuit என்று கூறினீர்கள் பிறகு எப்படி அதில் Charge மற்றும் discharge வேலை செய்கிறது DC Supply ல்
Please reply me
அது dc க்கு மட்டுமே.... dc ஐ remove செய்தவுடன், discharging ல் magnetude மாறுவதால், charge ஆகின்றது
Sir,
capacitor reactance xc=infinite meaning capacitor should act as open circuit right?
Correct
Low frequency as capacitor performance high because open circuit and sometimes high frequency as capacitor act as short circuit low performance
Nice சார்
எனக்கு 555 reset simple circuit வேண்டும்
தொடர்பு கொள்ள முடியுமா?
தங்களை போல் தமிழ் ல
விளக்கம் தர வேற யாரும் இல்லையே !
Thank u sir
Super
Thanks
Xc=infinity means capacitor open circuited
Sir XL =0 its a short circuit...... XC =infinite its a open circuit..... kindly change that content sir