Trigonometric Parallax: Space: Edexcel A-level Physics
HTML-код
- Опубликовано: 25 авг 2024
- The first video in a series detailing how we measure distances in space and so explore the origins of the Universe. Explaining how nearby star distances are measured using the technique of trigonometric parallax and what the limitations are.
If you liked this video, consider shouting me a coffee at: www.buymeacoff...
Patreon: / nutshellphysics
Website: www.stemtutors...
If possible pls continue the videos on cosmology. It is really helpful indeed.
Thank you soooooooooooooooooooooooooooooooooooooooooooo much!!! That was so useful!!!!!! Please upload more videos like this!!!!!
this was very helpful thank u very very much
There is no parralax in the stars from earth, scientists claimed to have seen parallax from a spaceship that took photos after lining up to 50 other stars. As for finding the distance, size or speed of any bodies in the solar system/galaxy/universe, one would need to know at least the distance and size of at least 2 of said bodies. No one seems to be able to explain how they come up with the first distance of a planet without knowing any other distances.
What are you yapping about
how do we measure the angle tho? the one you divided by two to find the parallax angle
That’s measured by how the near star has moved against the background. If you think of the sky as 180 degrees you can see where it was and where it is 6 months later.
How long do the rest of the videos take?
Is it necessary to convert to Au or can we keep them in Km?
You can keep them but you need to know about AU. And pc.
you have no clue how you saved me for my exam in 2 days, didnt understand parallax well but now i do and im going to see for the doppler effect and luminosity and a few more things... pls wish me luck ;-;
The very best of luck!!
i thought 1Au was 150x10^6 not 10^9 ?
Depends on whether you’re talking metres or km.
6:10 I did not get this part, how did we get the 1.5° here
If,
1 second = (1/3600)°
0.75 seconds = 0.75×(1/3600)°
0.75 seconds = (2.083×10^-4)°
Am I right?
he meant 1.5" total between summer and winter equinox
How do you measure the parallax angle? I watched some of these videos, and no one has mentioned how to measure the angle. Anyone with a high school math knowledge knows how to solve a right triangle, it doesn't need tutorials.
This is for high school students. Hence the ‘tutorial’.
Bro got smoked, Don't mess with your friendly neighbourhood scientist!
so its always going to be tan?
The calculation of star distance? Yes, because we want the adjacent and we know the opposite.
@@nutshellphy yaaa thanks
Can I get source of your data?Wanted to write an article actually
Source of which data? The star stuff? Oh that was from multiple places sourced over a few years, I couldn’t tell you exactly where from at this stage. Sorry. But you can probably find similar data on any decent astronomy page.
Okay,thank you 💙
Actually wanted to know about the limitations of trigonometric parallax .100 parsec/1000 parsec?