Wow, great solution. This was my initial idea: Initialization: Initialize max_length to 0. This variable will store the maximum length of contiguous 1's found after "removing" each element. Iterate Over the Array: For each element in the array, consider it as the element to be removed. This involves temporarily ignoring the element and calculating the length of the longest contiguous subarray of 1's that includes elements before and after the "removed" element. Calculate Length of 1's Around the Removed Element: For each element at index i: If the element is 0, calculate the length of contiguous 1's to the left (left_ones) and to the right (right_ones). The length of contiguous 1's after "removing" this element is the sum of left_ones and right_ones. Update the Maximum Length: Update max_length with the maximum value found by considering the current length of 1's after "removing" the element at index i. Special Case Handling: If the array contains all 1's, the result should be the total number of elements minus one, since we must remove one element. I like yours more, because it is simpler, but it was pretty embarrassing how you didn't realize the last sum wouldn't be appended because I noticed that.
Wow, great solution. This was my initial idea:
Initialization:
Initialize max_length to 0. This variable will store the maximum length of contiguous 1's found after "removing" each element.
Iterate Over the Array:
For each element in the array, consider it as the element to be removed. This involves temporarily ignoring the element and calculating the length of the longest contiguous subarray of 1's that includes elements before and after the "removed" element.
Calculate Length of 1's Around the Removed Element:
For each element at index i:
If the element is 0, calculate the length of contiguous 1's to the left (left_ones) and to the right (right_ones).
The length of contiguous 1's after "removing" this element is the sum of left_ones and right_ones.
Update the Maximum Length:
Update max_length with the maximum value found by considering the current length of 1's after "removing" the element at index i.
Special Case Handling:
If the array contains all 1's, the result should be the total number of elements minus one, since we must remove one element. I like yours more, because it is simpler, but it was pretty embarrassing how you didn't realize the last sum wouldn't be appended because I noticed that.