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Minor correction - Grind 75 is not by LeetCode :)

Sorry about the buggy audio! I'll get it fixed before next stream

Great stuff! Someone like you deserves more than a 90% in leadership.

Love from sholingnallur

Can you do a video on how to expand (a+b)^3

I think you can also do this in O(1) space without using a map since the majority element occurs more than 50% of time. You can just use a simple count variable.

Love the thumbnail art style. It’s very unique and you should stick to it

what do you use for your hair?

Wow, great solution. This was my initial idea: Initialization: Initialize max_length to 0. This variable will store the maximum length of contiguous 1's found after "removing" each element. Iterate Over the Array: For each element in the array, consider it as the element to be removed. This involves temporarily ignoring the element and calculating the length of the longest contiguous subarray of 1's that includes elements before and after the "removed" element. Calculate Length of 1's Around the Removed Element: For each element at index i: If the element is 0, calculate the length of contiguous 1's to the left (left_ones) and to the right (right_ones). The length of contiguous 1's after "removing" this element is the sum of left_ones and right_ones. Update the Maximum Length: Update max_length with the maximum value found by considering the current length of 1's after "removing" the element at index i. Special Case Handling: If the array contains all 1's, the result should be the total number of elements minus one, since we must remove one element. I like yours more, because it is simpler, but it was pretty embarrassing how you didn't realize the last sum wouldn't be appended because I noticed that.

vid was too long bro😅...keep it short..

Smart asf

Good job 👏👍

LOVE THAT TRICK YA PULLED OFF ON ME!! HOPE TO SEE YOU AGAIN DO THEM TRICKS AGAIN

gaming content pls with Facecam

Nice video

u did this to me on omegle and i was lost

if people invest in this will they get a share of sour candy if yes then i'll help

Are you sponsored by OCEAN?

0:22 removes 50 cards from pack of 52 remains with 4 cards bro teach us how to get those extra 2 cards teleported into our packs too

Nice video and trick man

Great video but many might not understand such a complex topic like vectors(i.e. i^ or j^). Same stands for matrices. Still all the best. Check out my video though.

Brilliant!! Well presented . Good luck Anish 👍🏻👍🏻

This was very useful. I understood everything. Thank you! :)

Nice presentation, Anish. Good Luck!