Moment Distribution Method for Beam Analysis - Problem No 6

[@joashisa813]

This was very helpful 👍, Thank you.

[@uitian9951]

thanks a lot for teaching ,your explanation is just awesome, 👍

[@kelvinmawuko6200]

Simple to understand. Thanks

[@madanrathor2871]

Very helpful thankyou so much 😍😍

[@VickyKumar-lu4pe]

awesome
😮😮😮

[@pratikkc1063]

Sir...Can we use k = I/L for fixed and I =3/4×I/L for simply supported end ? Instead of these?

[@Stanacademy]

you can use.

[@pratikkc1063]

@Stanacademy thank you sir... i also checked..the answer comes same... love from Nepal 🇳🇵

[@_NusratZahanTisa]

Can I get a pdf on ur moment distribution method?

[@ebenezeryeboah6780]

Sir please I have problem with the way to do analysis on the table , I did it but values were slightly different from yours for instance the one you had 21 and 21 mine one was 21 and 22

[@Stanacademy]

There can be slight differences. but no problem

[@CEFABIRAMIK]

Sir why you calculated upto 5th distribution....1st distribution is enough nah to find the final moment...if not can you explain why?

[@Stanacademy]

it is not enough. You have to do the distribution until you are getting smaller value. Kindly watch from the Problem No 1 from the playlist

[@praveen-sp7ks]

why we had used 4EI/L In bc and cb calculations why nor 3EI/L?

[@blaze102]

Because of continous end there are different formula

[@ebenezeryeboah6780]

😍