You could make an icosahedron then make a plane on one of the icosahedron faces. Then make your hexagons, one in the center of the triangle and the rest filling up the entire triangle. Project the vertices onto a sphere,connect and pattern
Thank you for your this great detailed video. I was able to make the first sketch, as the inital dimensions are for guidance only and should not be dimensioned on the sketch except the 100 on the triangle. I was able to get to 6:05 sucessfully but I not able to make the circular patterns after (at 6:06), they apear in yellow but will not construct and i do not have any error messages, can you help? Thank you again for your great videos!!!
Judging from yellow patterns and no error message, I think it's an overload on your computer. Please, try to reduce the number of circular patterns or try to use another PC.
Thank you for your kind reply, I do not think my computer is overloading as i have 64GB ram, the problem is making that circular pattern (x2) on the 6 face polygon, when trying x3 insted of x2 just to see what happens, i see it cuts through area of the solid but doest not build the solids, like if the circular pattern only cuts.The only way I was able to replicate the circular pattern x2 is by extruding a 6 face polygon before making the circular pattern, then it seems to work to build the second 6 face polygon as shown at 6.06, would you know how come the circular pattern does not build the solid all together with the cuts? Thank you again ;)
The values on the initial sketch are incorrect. When I try to replicate it using those numbers, I do not get the geometry shown. As well, the values of L1 and L2 are switched in relation to the geometry on the screen, but that's easy enough to work out. Since this video was posted over two years ago and there are only two comments on it, my guess is that the original poster hasn't come back here since they put it up. I'd love to try this exercise, but having an invalid Step 1 does make that problematic...
I'm sorry that the first figure is very confusing. However, L1 is the height of a equilateral triangle with a side length of L2. Therefore, L1= L2 x SQRT(3) /2 = 100 x SQRT(3) /2 = 86.6 . Please, check the figure at 0.46 sec. Thank you for watching and comments.
Thank you for the tutorial. Are all hexagons are same with all sides equal ? Is it just illusion, I am seeing the hexagons that directly adjacent to pentagons are different from other hexagons. Kindly clarify. I am looking to model in NX with even more hexagon faces. What I understand from google search is whatever the sphere size and what ever may be the polygon size, only 12 pentagons will be part of it..., but just struggling to execute.
Good morning. I'm working in building the goldberg polyhedron of class 3 with 560 vertex and 282 faces (it's the T=28 in wikipedia en.wikipedia.org/wiki/Goldberg_polyhedron). I want to do it in a similar way to yours, but currently I cannot figure the way. I assume I would have to change things in the first sketch... I would really appreciate some advice. Amazing job by the way!
I think Goldberg polyhedrons of T=7, 13, 19,... have skew angles for the pentagons. Therefore, these are based on Snub Dedecahedron. It can be "Truncated Pentakis Snub Dodecahedron". Please have a look these two instructions. How to make Snub Dodecahedron by SolidWorks ruclips.net/video/Ht-O1gzTMJ0/видео.html How to make Pentakis Snub Dodecahedron ruclips.net/video/LMZT0Y-U-og/видео.html
Hello! Thank you for your answers to me! Can you help me with one more question? I want to create a polyhedron with fewer polygons than here. Specifically, this one: commons.wikimedia.org/wiki/File:Conway_polyhedron_Dk6k5tI.png?uselang=ru In an article about Conway's notation for polyhedron, I read that the original polyhedron is also a truncated icosahedron, but I still can't figure out how to truncate it.
You could make an icosahedron then make a plane on one of the icosahedron faces. Then make your hexagons, one in the center of the triangle and the rest filling up the entire triangle. Project the vertices onto a sphere,connect and pattern
It's a good practice to make your own methods. I don't think my method is the best. Thank you for watching and comments.
Great tutorial. Could use a little explenation on the intro sketch, but I did get this far.
At 6.28 it is axis 4 instead of axis 3
Still not quite understanding how first sketch was accomplished with the values he's listed? Could you clarify this please?
Thank you for your this great detailed video. I was able to make the first sketch, as the inital dimensions are for guidance only and should not be dimensioned on the sketch except the 100 on the triangle. I was able to get to 6:05 sucessfully but I not able to make the circular patterns after (at 6:06), they apear in yellow but will not construct and i do not have any error messages, can you help? Thank you again for your great videos!!!
Judging from yellow patterns and no error message, I think it's an overload on your computer. Please, try to reduce the number of circular patterns or try to use another PC.
Thank you for your kind reply, I do not think my computer is overloading as i have 64GB ram, the problem is making that circular pattern (x2) on the 6 face polygon, when trying x3 insted of x2 just to see what happens, i see it cuts through area of the solid but doest not build the solids, like if the circular pattern only cuts.The only way I was able to replicate the circular pattern x2 is by extruding a 6 face polygon before making the circular pattern, then it seems to work to build the second 6 face polygon as shown at 6.06, would you know how come the circular pattern does not build the solid all together with the cuts? Thank you again ;)
@@Brioaquaponicsposts I have no idea about that. But, I'm glad to hear that you have solved the problem by yourself.
The values on the initial sketch are incorrect. When I try to replicate it using those numbers, I do not get the geometry shown. As well, the values of L1 and L2 are switched in relation to the geometry on the screen, but that's easy enough to work out.
Since this video was posted over two years ago and there are only two comments on it, my guess is that the original poster hasn't come back here since they put it up.
I'd love to try this exercise, but having an invalid Step 1 does make that problematic...
I'm sorry that the first figure is very confusing. However, L1 is the height of a equilateral triangle with a side length of L2. Therefore, L1= L2 x SQRT(3) /2 = 100 x SQRT(3) /2 = 86.6
. Please, check the figure at 0.46 sec. Thank you for watching and comments.
Thank you for the tutorial. Are all hexagons are same with all sides equal ? Is it just illusion, I am seeing the hexagons that directly adjacent to pentagons are different from other hexagons. Kindly clarify. I am looking to model in NX with even more hexagon faces. What I understand from google search is whatever the sphere size and what ever may be the polygon size, only 12 pentagons will be part of it..., but just struggling to execute.
No, they are not. There are four types of hexagons. Thank you for watching and comments.
@@HiroLaboOECU can you tell me how to create a polyhedron with the same hexagons?
@@HiroLaboOECU I think I got it!
From the SAME pentagons, hexagons, you can only get a truncated icosahedron! Right?
@@dimkadimka6018 Yes, you are right. Thank you for watching and comments.
Good morning. I'm working in building the goldberg polyhedron of class 3 with 560 vertex and 282 faces (it's the T=28 in wikipedia en.wikipedia.org/wiki/Goldberg_polyhedron). I want to do it in a similar way to yours, but currently I cannot figure the way. I assume I would have to change things in the first sketch... I would really appreciate some advice. Amazing job by the way!
I think Goldberg polyhedrons of T=7, 13, 19,... have skew angles for the pentagons. Therefore, these are based on Snub Dedecahedron. It can be "Truncated Pentakis Snub Dodecahedron". Please have a look these two instructions.
How to make Snub Dodecahedron by SolidWorks
ruclips.net/video/Ht-O1gzTMJ0/видео.html
How to make Pentakis Snub Dodecahedron
ruclips.net/video/LMZT0Y-U-og/видео.html
Hello! Thank you for your answers to me!
Can you help me with one more question?
I want to create a polyhedron with fewer polygons than here. Specifically, this one: commons.wikimedia.org/wiki/File:Conway_polyhedron_Dk6k5tI.png?uselang=ru
In an article about Conway's notation for polyhedron, I read that the original polyhedron is also a truncated icosahedron, but I still can't figure out how to truncate it.
This is a truncated pentakis dodecahedron.
@@HiroLaboOECU Thank you!