Trick to calculate bond pair and lone pair on central atom / chemical bonding

#chemistrygyanacademy #bondpair #lonepair #chemicalbondingandmolecularstructure
This is the video related to easiest way to calculate bond pairs and lone pairs on central atom.
Trick used is very useful for ur school exam as well as competitive exam like JEE, NEET , JAM , NET and GATE exam. bond pairs and lone pairs calculation on central atom can also be used to predict geometry and shape of different molecules as per VSEPR theory. This topic covers chemical bonding of class 11 and p- block elements of class 11 and class 12.
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Super Tricks For How To Find Lone Pair and Bond Pair in Central Metal
Calculation of Bond Pair
Lone Pair
Chemistry Class
Chemistry VSEPR THEORY
VSEPR CALCULATION
VSEPR theory Chemical Bonding
Chemistry Class
calculation of bond pair and lone pair which help in determining shape of the molecule.
#suresh #chemistry #bondpair #lonepair
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[@loksangeetharyanviwithasha1803]

Sir its wonderful trick...and the way u taught the whole lesson with patience is commedable🙏

[@devinderdevinder4977]

It may be 2lp

[@Chemistrygyanacademy]

Beta
S has 6 electrons
Out of 6 , 4 electrons are used by 2 oxygens ( 2 by each O )
So S has 2 remaining unshared electrons so one lone pair

[@devinderdevinder4977]

Oooh that's is

[@devinderdevinder4977]

Tysm sir ji

[@devinderdevinder4977]

Sir from where are you ?

[@dilshadalimallah8247]

Sir Meny bhut videos dekhy smjh me nahi aa raha tha
Ap k video se pora concept clear hogya
Thank u so.much sir

[@Rs76a]

Really bro🥺🥺
M to kota m hu fir bhi un teacher ka nhi smjh aaya🥺

[@kunalsharma1070]

Sir salute to you I didn't understand anywhere but u are the real teacher

[@Chemistrygyanacademy]

Thanks for appreciation

[@harshitpandey2212]

The easiest method I have ever seen , thank you sir

[@SayedMuhammadMuhammadSayed]

Very nice👍👍👍👍👍

[@user-lr4hx8ec4x]

Thank you so much Sir. Nice and helpful trick

[@gulalaikhan727]

Now this is called a real teacher ..❤👏👏

[@vijnn6704]

Watching this 8 min video is totally worth it, thankyou sir ❤

[@Chemistrygyanacademy]

My pleasure

[@soundararajan8667]

Best vdo👍#keep going

[@Chemistrygyanacademy]

Thank you, I will

[@tanmayn1984]

Very nice trick sir 👍👍 it's easy

[@prynka1803]

Mind blowing
I have lots of doubts in lone pair
But now I am able to understood .....
Thank you from bottom of my heart

[@Chemistrygyanacademy]

Glad to hear that

[@jeewanasha2754]

Thank you sir tomorrow is My exam in my institute and my this topic was
only left and u made it do

[@jayvikrant3250]

u made it too

[@divyeshpatel5138]

Nice sir 👍👍👍

[@Chemistrygyanacademy]

Thanks and welcome

[@dftba4055]

So simple and straight away method... 😊😀😀

[@jayvikrant3250]

straight-way

[@bajiraosingham3975]

Sir you are really very awesome teacher of this earth

[@Chemistrygyanacademy]

Thanks for appreciation

[@brijkishorjimaharaj]

Congratulations sir Ji I am Abhishek Pandey

[@shilpa3597]

Really it's very useful sir...thank you sir for this trick...

[@wajahatkhan9839]

Sir with this trick we cant find hybridization of NO2 Sir plz explain it.

[@arif8785]

Thank u so much sir, this topic was troubling me for quite a long time.

[@benedict1230]

Sir jee se phele dekh rha hu
U nailed it sir! 😘😘

[@samriddhimehta2738]

Wonderful explanation.

[@swetajhaofficial.5101]

It can be Very easily understood even by the weak and weak superative form of weak student by your teaching skills and techniques thanks thAanks so much sir

[@princemaurya9688]

Ty sir... Poora samjh aa gaya... Basics cleared

[@abdulfatah9602]

Zabardast yr,,, lucky are the students who are sitting there! Thank u❤

[@MilagritozBC]

Bless your soul, I've been trying to understand this for my exam today and I DID NOT AND NOW I DO.

[@jayvikrant3250]

now i did

[@farheenajaz]

It's amazing sir ..... Sir aapne bahot ache se smjhaya mujhe lga hi nhi tha ki mujhe kbhi lp aur bp aapaega smjh 👌👌👌👌👌

[@treezytrey88]

Thank you for this educational video. Clarified a lot of things for me

[@mohamedfathima2015]

Sir thank you very much.. And by the way u look like Vikrant Massey 😀

[@Chemistrygyanacademy]

Thank you dear

[@georgelynch2996]

Great video, saved me in my exam

[@kazifarhanshadik9701]

Very easy and simple..Thanks for making it simple..

[@avezkhan788]

In No3- bond pairs are 3or4??

[@Chemistrygyanacademy]

As per VSEPR theory 3 and as per LEWIS concept 4

[@ArbazKhan-ei6yk]

Amazing trick👍🎉thanks a lot sir ............,

[@vogilisettyakhilkumar9449]

Thank u so much sir ..super explanation ..I have cleared my concept..

[@dhanashreechorge6922]

Thnx sir u destroyed one of the biggest enemy😅😍😍

[@Chemistrygyanacademy]

😅

[@navdeeps6947]

Thank you sir....you made it very simple and easy

[@aswitrishu4465]

Super sir👌🏻👌🏻👌🏻👌🏻👌🏻

[@Chemistrygyanacademy]

So nice of you

[@cheongmingli6170]

sir, only oxygen is needed to count as 2 molecules? or chlorine and iodine need also?

[@Chemistrygyanacademy]

Because of valency it's counted as 2
Chlorine and iodine has valency 1
So count one for them

[@kontugaming6109]

Sir mast trick he thanks a lot🙏🏿🙏🏿

[@Chemistrygyanacademy]

So nice

[@sanjaymishra8502]

Nice and very useful,Thanks sir

[@kakalidasgupta4173]

Thanks sir this is so amazing

[@Chemistrygyanacademy]

Thanks for appreciation

[@rajeshbiswasroy6338]

How to calculate the bond pairs and lone pairs of NO,N2O3 using this method.
Sir please reply

[@Chemistrygyanacademy]

No method is applicable to these molecules.
We have to remember these structures.

[@mohammedkhan8749]

Actually I felt that it was an physical class
Btw superbb

[@priyamv5000]

Clear and concise. Thanks sir.

[@harekrishnashorts]

Thanku sir it helps me a lot🙏🏻

[@seaofsongs7830]

Thank you so much sir. You are a very calm and gentle man.

[@शिवम_210]

Sir bhut simple trick h.
Thank you sir

[@mallikarjunacheerala1745]

You told me very well sir thank you sir

[@manavharma7269]

Sir ek number thnx for solve my doubt.❤️

[@mahidharkollipara4071]

Sir mind blowing

[@snehadas9007]

Thank you Sir... you explained it in it's easiest way..

[@milind8541]

Sir u explained it in a very simple and brilliant way , thanks a lot!

[@michaeldsouza9294]

Sir was explanation was excellent , was not understanding the complete concept but after hearing your video it became absolutely clear.

[@lisavahora624]

Leaning made simple thank you very much Sir 👍

[@mehulaggarwal7776]

U can also use formula
(Valence electrons-bond pairs -charge)/2. Only to find lone pairs
I guess this will work

[@Chemistrygyanacademy]

God bless you!!!
Right that's what I said without writing mathematical equation.

[@priyajobikavungal]

But it doesn't work for oxygen containing compounds what do u do then? 🤔

[@Chemistrygyanacademy]

For oxygen containing compounds, consider two electrons of central atom for each oxygen.

[@zingurssa17]

This video cleared my doubt 👍 thanks a billion Sir👍🙏

[@Chemistrygyanacademy]

You are most welcome

[@gouravverma7001]

Very easy and useful trick

[@nightwingop-ER]

How many lone pair of electrons are there in H2SO4 and H2SO3 ?

[@Chemistrygyanacademy]

On S in H2SO4 THERE IS NO LONE PAIR
BUT TOTAL LONE PAIR IN H2SO4 ARE 8 (TWO LONE PAIRS ON EACH OXYGEN )

[@Chemistrygyanacademy]

On S in H2SO3 THRRE IS ONE LONE PAIR
BUT TOTAL LONE PAIR IN H2SO3 ARE 7 ( two lone pairs on each oxygen and one lone pair on Sulphur)

[@nightwingop-ER]

Thanks sir ☺️ your method is very quick and perfect for mcq's 😄 takes very less time to do and very easy

[@mohinimahajan8350]

Awesome sir

[@Manyaaa21]

This was soooo helpful ....thankyou sir!!!!😇♥️😇♥️

[@Chemistrygyanacademy]

Most welcome 😊

[@venusvlogs3032]

Tq so much sir..clear explanation...

[@easylearning5124]

Amgaing teaching sir ...😯😯

[@vrufus2372]

Super video sir and great explanation sir

[@studentofscience3952]

Awesome👏✊👍

[@mah-rukhyousafzai9499]

Thank you so much! God bless you!

[@user-pj5dd9kz8l]

Very well done sir

[@ruhaniverma5302]

Thank you so much sir........i m happy just bcz of you ...bcz mere doubt cllr ho Gaya....pllz sir chemistry me or tricks upload kijiye....mainly on chemical kinetics... thanks again sir

[@sinchanas1724]

Very helpful
Thank you so much sir.......🙏🙏🙏🙏🙏

[@vamsikrishna9611]

That i3- came in 2018 offline

[@fathima5413]

Thank you sir, very helpful video

[@Chemistrygyanacademy]

Happy to help

[@yashygamer349]

Explanation is understandable

[@rajkiranreddy6212]

Thank you so much sir for such patience explanation towards students👏👏🤝

[@Lavi3007]

Thanks alot u are the best

[@blackdevil2920]

Lit trick!🔥 Thanks sir!💕

[@rojalinnayak0386]

Very good explanation,thanks for this vdo🥰

[@melofleci8859]

Its the only video on internet with super tricks.Thanks a lot Sir 🙇

[@Chemistrygyanacademy]

Thanks and welcome

[@SK.Carrier]

Sir I can not understand well the lone pair only of these molecule please sir add a new video of it to understanding will in comparison to it.

[@Chemistrygyanacademy]

Sure

[@suryatejaswi7781]

S.k Carrier just calculate the hybridisation and subtract number of bond pairs from it,you'll get lone pairs

[@dineshmahara5731]

Lovely sir
Keep it up!!

[@afterdays6415]

sir i have a doubt basically to find the LP and BP of central atoms we should have an idea on lewis structures or molecular structure is this trick is useful in finding lp and bp

[@mashfiquehoquearonno2009]

Thank you so much sir, from a Bangladeshi student

[@Chemistrygyanacademy]

Most welcome

[@ananyashil754]

You explain so great!!

[@ilmfaint7449]

Thnku so much💖💖

[@harshimodi4970]

Thank u so much sir....helped a lott!!😊💯👍

[@funnybaba2282]

lajawab sir ji

[@virendrakumartyagi2044]

Thank u so much... This is the only video on RUclips that helped me out.... 👍👍👍 Thank u from the depth of my heart

[@kaustubhpatil6379]

Sir u taught nicely 👍🏻👍🏻👍🏻👍🏻👍🏻 I understood very welll

[@Chemistrygyanacademy]

Glad to hear that

[@RameshKumar-qo6hh]

Sir how many bond pairs and lone pairs are there in NO3 nagative?
Sir reply plz

[@Chemistrygyanacademy]

number of O - atoms attached to N are 3
That's why there are 3 bond pairs
Total electrons used are 6 (2 by each O)
Total valence electrons = 5 + 1(bcoz of one negative charge ) = 6
No electron left unshared so no lone pair
(NO3)^1- has three bond pairs and no lone pair
Understood!!!!

[@RameshKumar-qo6hh]

But sir according to Lewis structure it has 4 bond pairs and 0 lone pairs

[@Chemistrygyanacademy]

You are right but remember Lewis structure counts all the bonds means sigma as well as pi bonds.
NO3- has 3 sigma bonds and 1 pi bond.
Total electron pairs = 4
According to VSEPR theory
It has 3 bond pairs bcoz VSEPR theory takes into account only sigma bonds.
Only sigma bonds decides shape of the molecule.
Lewis structure doesn't tell shape of the molecule but VSEPR theory does.

[@RameshKumar-qo6hh]

Thanks sir

[@divyabharathi8556]

Thank u so much sir.You cleared my all doubts regarding this topic

[@florydr2j]

Wonderful sirrrrr❤️❤️❤️🔥🔥🔥🔥🔥

[@sukhdevmaan7517]

Sir it is a wonderful trick

[@tumpashaw2755]

Best video ever😘😘😘😘😘❤❤❤❤

[@AbhishekSharma-yw7zn]

Best explanation 👌

[@rappaccr7954]

Zabrdast sir

[@durgeshchaturvedi1021]

It is very fantastic

[@garvrajput9983]

Wooowwwwwww. Made it so easy

[@saadnagori904]

Thank you so much sir for uploading this video it helps me a lot in my exam🙏

[@shreyade3936]

awesome trick understood it so clearly!! thanks a lot sir!!

[@shreyade3936]

sir i had watched your video before my half yearly exam and i have secured 34/35 in my exams !! really hatsoff to you sir 😊

[@Chemistrygyanacademy]

All the best and thanks for your appreciation.

[@komalb2445]

thank u sir you made the topic easy which i used to feel tough

[@limparoy4392]

Sir it was so helpful. Thank you so much.

[@ishanigaur9014]

teaching like allen teacher very helpful

[@tasleemahmadmalik1251]

Sir apne jb SO2 btaya tb apne oxygen k liye 4 electron(2 bond pair kha) but jb apne ClF3 bola toh usme seedhe 3 bond pair electrons kyu liye...6 electrons ki jgh
Sir pls reply!

[@Chemistrygyanacademy]

Beta Oxygen is divalent while fluorine is monovalent