sir why 0.693 is used at the time 13.37, we are analyzing for 50% of Vdd. 0.693 is for (100- 63)% discharge time of capacitor. i have confusion about this. please explain.
since Vdd is very high so i is directly proportional to Vdd therefore Vdd/Vdd will be cancelled out from the equation and it will be independent of Vdd.
We learnt that , in short channel mosfet, after VD(sat) the current saturates but here in pic it shows nearly increasing. How is that?
sir why 0.693 is used at the time 13.37, we are analyzing for 50% of Vdd. 0.693 is for (100- 63)% discharge time of capacitor. i have confusion about this. please explain.
Use discharge equation of capacitor.
Vc(t) =Vo*e^(-t/tau)
Put Vc(t) /Vo=1/2 for 50℅ discharge. We get
t=ln2*tau=0.693*tau
@@alraghuschannel4023 thanks
sir how Req is not a function of vdd ? 21:42
since Vdd is very high so i is directly proportional to Vdd therefore Vdd/Vdd will be cancelled out from the equation and it will be independent of Vdd.