Since C'(t) is becoming less negative that means the values of C'(t) are increasing toward 0. Increasing rate doesn't necessarily mean larger magnitude it just implies the C' values are becoming less negative.
Yay! Time series problems! Love those kinds of challenges, especially if you can see the illustration of the trend curve. Great content, Christee! (Good morning from my side of the world) 🥰🤓😍
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For 1d.) I believe you have interpreted it wrong. The value of the C'(t) become less and less negative 12
Since C'(t) is becoming less negative that means the values of C'(t) are increasing toward 0. Increasing rate doesn't necessarily mean larger magnitude it just implies the C' values are becoming less negative.
that's what I put and I hope that's correct
You are fast!! Love that you got these up here quickly - THANK YOU for your awesome explanations!!
Yay! Time series problems! Love those kinds of challenges, especially if you can see the illustration of the trend curve. Great content, Christee! (Good morning from my side of the world) 🥰🤓😍