INDIAN Olympiads Exams || 99.9% of Students Failed This Tricky Math Test ||

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  • Опубликовано: 3 дек 2024

Комментарии • 12

  • @jonathandawson3091
    @jonathandawson3091 2 дня назад +6

    It seems very much in the line of -
    "How do you solve k^k = 11? Just invent a function since it is not solvable, and then we can call it solved."

  • @ralkadde
    @ralkadde 3 дня назад +4

    On RUclips there are a lot of videos dealing with this problem. kᵏ = 5, kᵏ = 7, ... Lets give a general solution for kᵏ = a. As you can see, k = e^(W(ln(a))) is at least one solution for any a.

  • @deandelvin9924
    @deandelvin9924 3 дня назад +1

    0:26 k^k=🦆

  • @RyanLewis-Johnson-wq6xs
    @RyanLewis-Johnson-wq6xs 3 дня назад +1

    K^K=11 K=e^(W(Ln(11))) K=e^(W(Ln(11)+2πin)) n=z It’s in my head.

  • @chinmayvaze
    @chinmayvaze День назад

    Now onwards i will use w function to get a fish. Why go to the market?

  • @patricklincoln5942
    @patricklincoln5942 3 дня назад

    @4:50: What's with the fish?

  • @IsaacR-c6k
    @IsaacR-c6k 2 дня назад

    I literally fucking solved it in my head, 2.56

    • @payoo_2674
      @payoo_2674 2 дня назад

      2.5556046121008206152514542654716688251666245546770082657444779051...

  • @John-qx1xn
    @John-qx1xn 2 дня назад

    Even better is k= 23/9 where k^k = 10.99895411