FIJI (ImageJ): Using 3D Objects Counter and 3D Manager to Measure Cells in a Z Stack

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  • Опубликовано: 20 дек 2024

Комментарии • 33

  • @MOLECULARBILL
    @MOLECULARBILL 2 года назад

    I must say, I use Fiji quite often, and still learn new stuff on your channel. Keep up with the good work!

  • @sikeyy6881
    @sikeyy6881 2 года назад +1

    Is there any way I can contact you about resolving my issues? I'm stuck at "Step 2/3 Connecting Structures" and I haven't found a solution in days.

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  2 года назад +1

      @sikEyy. Go to my channel. In the 'About' page, you can find my email.

    • @sikeyy6881
      @sikeyy6881 2 года назад +1

      @@johanna.m.dela-cruz Thank you! Sent the email

  • @nalar150
    @nalar150 Год назад +1

    with 3d object counter, can we obtain the position (x,y,z) in the result sheet?

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  Год назад +1

      Hi @nalar150. If you add Centroid (or center of mass) in the 3D OC Options, you can get coordinates of the centers of each object detected.

  • @claireseelingbranscomb2781
    @claireseelingbranscomb2781 24 дня назад

    Is there any way to set a ROI so that cells outside of it will not be counted? Additionally is there a way to keep the number labels on the 3D viewer? Or add them after the 3D image is generated? I wanted to look at multiple channels in 3D, but when I add an image, I keep accidentally selecting it and it keeps moving, is there a way to keep it stationary?

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  23 дня назад

      @@claireseelingbranscomb2781 hi there. Do you have 2 channels and would like to count objects in one channel using ROIs from the other channel? If yes, then I would give your first question a thumbs up. The 3D viewer is just one way to view your image in 3D. You would first have to merge the channels in your images before you do 3D reconstruction.

    • @claireseelingbranscomb2781
      @claireseelingbranscomb2781 19 дней назад

      @@johanna.m.dela-cruz Thank you for the reply. My biggest concern now is numbering the cells. Is there any way to add numbers to the 3D viewer?

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  18 дней назад

      @claireseelingbranscomb2781 I don't think the 3D viewer will show the numbers. You can try 3D Project or 3D Script.

  • @myriot123
    @myriot123 2 года назад

    Hi , thank you very much for this video, i was wondering if i can use this method to measure area fraction of a signal after thresholding on a Z stack ? Thanks

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  2 года назад +1

      Hi @Myriem OTMANI IDRISSI. Thanks for watching. For z stacks, instead of area, the volume is measured from both the 3D Objects Counter and 3D Manager. I don't think there is a direct way to measure the volume fraction. You might have to use the 3D Manager - under 3D Segmentation you will need to threshold the whole image stack (using 0 as low threshold and 255 as high threshold, if you have an 8-bit stack). After adding the segmented stack into the Manager, The Measure 3D button gives the volume of the whole stack (background and objects included). You can then calculate the volume percent by dividing the total volume of your objects by the total volume of the stack.
      Hope this helps.

    • @myriot123
      @myriot123 2 года назад +1

      @@johanna.m.dela-cruz Thank you very much, i will be trying this

  • @waelhamda
    @waelhamda 8 месяцев назад

    Thanks, how can i determine the x y z coordinate pf these particles or cells in 3D

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  8 месяцев назад

      Hi @waelhamda. You will need to set your measurements so that they would include either the centroid or center of mass of the objects.

  • @000irena000
    @000irena000 2 года назад +1

    This was REALLY helpful! Thank you for making this video and I love the happy music lol

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  2 года назад +1

      My pleasure. Thanks for listening, watching and learning. 😊

  • @octaviasantisl
    @octaviasantisl 4 месяца назад +1

    Can you create a mask out of that segmentation?

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  4 месяца назад +1

      Hi Octavia (@octaviasantisl). A labeled image/stack can be converted into a binary mask by using a low threshold of 1.

  • @rajaaalwodai5745
    @rajaaalwodai5745 20 дней назад

    Great video
    I followed all the step but for some reason it’s not loading when I press measure. Can you please help.
    Thanks

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  16 дней назад

      Hi there. I’m nit sure what you mean by not loading….do you have objects in the 3D Manager?

  • @08270216
    @08270216 2 года назад +1

    Thanks, It's really help for me.

  • @qingbowang4870
    @qingbowang4870 2 года назад

    Thanks very much for the excellent FIJI instruction. ^_^

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  2 года назад

      Thanks for watching, @Qingbo Wang. Comments like yours inspire me to continue with my series.

  • @annapurnasharma5716
    @annapurnasharma5716 6 месяцев назад

    Amazingggg🌸🌸

  • @sriti_hikari
    @sriti_hikari 4 месяца назад

    Hi do you have any idea on how to measure the fiber orientation on a 3d-z-Stack?

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  4 месяца назад

      @@sriti_hikari You can try Directionality or OrientationJ. My tutorial is here: ruclips.net/video/tN0bEVsumJc/видео.htmlsi=vxeAMMU906Wsts0z

    • @sriti_hikari
      @sriti_hikari 3 месяца назад

      @@johanna.m.dela-cruz Hi thank you for your help- this will only give the orientation in the x-y-plane right? so the direction in z is not considered?

    • @johanna.m.dela-cruz
      @johanna.m.dela-cruz  3 месяца назад

      @@sriti_hikari Since each image in a z-stack is an optical section of your sample, fiber orientation shows the angle per slice. If you do a maximum projection of your z stack and then run the plugin, the orientation is based on the xy plane.