in write opearation if Q=0 and Qbar=1 and capacitors are precharged to Vdd then if Wl=1 then capacitor on Q side discharges makeQ=1 then we need to make BIT bar ground
Hi, in write operation, if bit1 is sent then x gets (vdd-vtn) and m2 turns ON right? doesn't this have any effect? and also you said that when w=1 and r=0, m2 will be OFF, how?
keep going bro.. your method of explaination is way better than 3 months of classes
Haii mam
in write opearation if Q=0 and Qbar=1 and capacitors are precharged to Vdd then if Wl=1 then capacitor on Q side discharges makeQ=1 then we need to make BIT bar ground
You are young but very skilled in explaining contents in the most simple yet powerful way.
at 22:31 u told that when bit =1 then drain volatge =1 >vtn so mos on but vg>vt right already it happens by making write signal=1
draw diagram neatly
Mst explain tha bhai itna difficult bna rkkha tha sbne pur tumne bhot easy kr diya
Very nice explanation sir... 👏👏
The best Explanation and information is given by you sir.
Nice work
If BIT voltage decreases how op will come as 0 ?
I wish I found this video earlier :'(
Thnak you
how sense aplifier work?
can u suggest any good book for memory design
Thank u soo much
70 pages in 30 mins ,good sir
which book is that?
Why not VDD- Vt for 1T-DRAM write operation?
Explained in a perfect manner. Thank you so much
Even write is possible in rom
Great effort !!!
Ty 😇
share videos with your friends as well
Thanks brother
Hi,
in write operation, if bit1 is sent then x gets (vdd-vtn) and m2 turns ON right? doesn't this have any effect?
and also you said that when w=1 and r=0, m2 will be OFF, how?
Sir app cmos, nmos and magnetic, optical and ferroelectric memories ke aiye..
Shrenik jain ki video h ye😂😂😂😂
handwriting is very poor
Tumhara haat mein dard hein kaya? Please write correctly hold the pen tightly, your writing is horrific. please write correctly.
ኦሮሚያ ጀሞ ረከት እስከ
Thank you bro
Thank you bro