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Some food for thought. If Harry and Ron were both perfect logicians, they could theoretically continue with that same line of questioning ( "Do you know now?" "No" "Me neither. Do you know now?" over and over again) and they would eventually figure out how many times the other person has seen Titanic, even if its a really high number. The logic for it works as follows: Since neither of them know the answer from the start (Ron saying "I have no idea" and Harry saying "Me neither") they can both safely assume they've both watched Titanic at least twice. This is because if one of them only saw it once, they would immediately know the other person's seen it more times. However, when Harry asks Ron "Do you know now?", one of two things can happen. Ron could have seen it twice and deduced that Harry must have seen it three times (because they both know they've both seen it at least twice), and Ron says "yes! I know now" OR Ron saw it MORE than twice and answers with "No I still don't know". If Harry responds "Me neither" that means he TOO must have seen it more than twice, and at that point they both know they have both seen Titanic at least three times. This can continue on ad infinitum until the answer is revealed. For example, if Ron saw Titanic... say... 15 times (dear lord), when they reach the point where they both know they have both seen Titanic at least 15 times, Ron will answer with "Yes I do know now!" properly deducing that Harry must have seen it 16 times. All of this said, they could simply just TELL each other how many times they've seen Titanic. But if I saw Titanic 15 times, I wouldn't want to tell anyone either ;p If anyone actually read this, wow good job.
@@Reletr That's what I thought of. The clock on that problem is set by the number of green eyed creatures, whereas this one is just set by the number of times the movie has been seen. I expect that the result would be similar in a riddle involving multiple people having all seen Titanic a unique number of times.
Assuming Harry and Ron are perfect logicians, Harry has watched it 4 times, Ron 3. Here's the steps: A). Harry asks Ron if he's seen it more. This shows the score isn't H1, R2, because if it were, Harry would realize since he's only seen it once, Ron would have had to see it twice, and wouldn't have texted Ron to ask. Therefore, Harry has seen it at least twice. B) Ron says he doesn't know. This shows the score isn't H2, R1, because if it were, Ron would realize since he's only seen it once, Harry would have had to see it twice. Therefore, Ron has to have seen it twice. C) Ron also know, that because Harry asked in the first place, Harry *also* must have seen it at least twice (see A). If Ron had seen it exactly twice, that means Harry has watched it three times, and Ron would know the answer. Because he didn't, this means Ron has seen it at least 3 times. D) Because (B) and (C), Harry knows Ron has seen it at least 3 times. But he still doesn't know if he's seen it more or not. This means he's seen it more than twice (because he'd know that he'd seen it twice so ron saw it 3 times), and he's seen it more than three times (because he'd know if he saw it three times, then ron had watched it 4 times). Because Harry doesn't know, he's seen it at least 4 times. E) Now Ron knows! Because Harry has seen it at least 4 times, and he knows he himself only saw it 3 times, we have a match. Harry 4, Ron 3.
It's also possible for Ron to have 4, and Harry 5, and Ron could have deduced that this round as well. So the solution is a bit ambiguous. However, beyond those two outcomes, if Ron had seen more than 4, then there still wasn't enough information and Ron wouldn't have been able to say he'd figured it out when he did.
It's not ambiguous, the dude says at the end there are multiple solutions by asking for the sum of the possible times Ron has watched it. So the answer is 7
Well ... There is one assumption you are making here. Basically in point A .. you are assuming harry asking ron if he knows who has seen it more times implies harry does not know right away. At this point in time, the answer might indeed be H1, R2 and harry knows that Ron has seen more times, yet still asks Ron if he knows (which he wouldnt since it could very well be H3,R2 for all he knows). This assumption changes the solution quite a bit. If you don't make the assumption that harry asking ron if ron knows implies harry doesn't outright know, then the possible answers are H3, R2 and H4, R3
Harry: "Hey, Ron! So how many times did you watch Titanic?" Ron: "Hey, Harry! I reckon I watched it 127 times. How about you?" Harry: "You're a sick sick man, Ron. I watched it only twice. The first time was when it was originally released, and the second time was when it came in 3D." Ron: "Oh. Okay. Bye bye then."
if they started at 2,4 and 6 the chance for them not to visit 3 ever would be less than 0,01%, and you could just fly away from 3 and return to catch them
This riddle is really cool! I have seen the linear version before where all of the "planets" are aligned in 1 dimension. I haven't seen the split on the third planet before. It is also nice to see that the same line of reasoning works in both cases. The key to note in these types of puzzles is when given that one side MUST do something in a oscillatory fashion, you can take advantage of that. For example, this is applicable in certain chess positions. Surprisingly, the linear case comes down to needing 2(n-2) steps to win, but this branched case also seems to need the same number of steps.
“Mom, can I have a list of planets from Star Wars?” “We have a list of planets from Star Wars at home” The list of planets from Star Wars at home: 0:17
I paused the video for two days until I finally got it! I was tired of not being able to solve these. These riddle videos are so good been following them for years, I love them! Keep'em up!
I must add that I was not the whole two days fully trying to solve it haha. I took like 1.5 hour each day during work when I didn't have much to do. But yeah, it was hard, it took me quite a few sheets and a pen to trace every pattern.
Bonus riddle answer - Harry asks Ron whether he had watched titanic more times, therefore he does not know himself. If he had watched it only once, then he would have known. Therefore- Harry watched titanic at least twice. Then Ron answers that he does not know. If Ron had watched titanic exactly twice then he would have known that Harry must have watched it 3 times, therefore Ron must have watched it at least 3 times. Harry then answers that he still doesn't know. If harry had watched it exactly 3 times, then he would have known that Ron must have watched it 4 times, and so he watched it at least 4 times. Ron then says that he does know whether he watched more times or not. That can only be the case if he watched it 3 times or 4 times, because then he would know that harry must have watched it 4 or 5 times respectively. So Ron must have watched titanic either 3 or 4 times, so their sum is 7.
Then this look would keep going until they hit over 100 times. Each would just keep saying "I don't know, do you know now?" "No, I don't. Do you know now?" Each time ups the number for each.
The logic is correct, but I think the website messed up and didn’t count Harry’s first question as an “I don’t know” for Harry, so the ‘actual’ answer is 5 (2+3 rather than 3+4), seeing as there is one less “I don’t know” moment.
oren shacham I understand the logic behind, it yet wouldn’t this riddle be slightly misleading if the audience was not aware whether both Ron and Harry were aware of the minimum possible number of times the other watched the movie? The riddle is plausible but, to me, it seems slightly illogical.
comment section be like 70%: star wars 15%: harry potter 5%: actually did the riddle/bonus riddle other 5%: dem voice so soothing- other other 5%: green fly double mouth nose thingy
The answer is 5 A) Harry asks Ron. It means H > 1 he wouldn't ask elsewhere. B) Ron doesn't know. It means R > 1. If it was he would've known. C) Harry still doesn't know. Therefore H > 2. D) Ron knows already. It means R < 4. If he watched it 3 times Harry watched 4 and if he watched twice Harry watched 3 times. If Ron watched Titanic 4 times, he wouldn't know if Harry did it 5 times. E) if Ron already knows the answer R < H. Otherwise Ron wouldn't know yet. And if H = 3 -> R = 2 If H = 4 -> R = 3 If H = 5 or more -> R doesn't know yet If H = 2 or less -> H would've already known before then. F) Left possibilities are R = 2 or 3 Sum of which is 5
If R = 2, H can be 1 or 3 If H = 1, Harry would've not asked the first question. So Ron would know that H = 3 and he wouldn't reply by saying "No idea!" So I believe R = 2 should not be a possible solution. Correct me if I'm wrong though.
@@akshaydamle95 I also thought about it, but If Harry knows how many times he watched titanic, which we assume: he does. He should follow the same logic ( at least to some point ) as I did. Therefore if he knew possible answers are R=2 or R=3, he would immediately know the answer If H=3, then R=2 If H=4, then R=3 Because he didn't know the answer we have to assume he couldn't follow the Ron's logic. In conclusion: because Harry didn't know whether R=2 or 3, we can't know either. But I'm glad you asked.
A friend of mine told me about this question last night, I found a similar solution but in my case the police car doesn't need to move more than one planet per hour (instead it stays on the same planet for two hours, basicaly it's the same trick): 2-3-4-3-6-6-3-2-3-4. This remind me chess. For example in an end-game of king and rook against king it's well known that to achieve checkmate you have to do a sort of "opposition" with kings and then push the rook in the same row/column of the opponent's king. To allow it, if the kings are not "synchronized", you need to loose a tempo by moving your rook. This is the same idea of loosing a tempo to "synchronize" cars by mooving of two planets or by staying on the same planet. Very interesting, thanks!
I want to clarify a few things for everyone who doesn't understand (as there are quite a few comments demonstrating some confusion): 1.) The layout of the planets is as shown in the video. There is no need for TED-Ed to explicitly state that the planets are in that layout as we are introduced to the planets by being shown that specific layout at 0:16 and are given no other possibilities. If the layout of the planets could be different, the video would have mentioned something along the lines of, "Let's assume the planets are in this configuration" or, "If the planets are in this configuration, we can use this method." It says neither, and just introduces the planets in the Y formation and never changes it. Therefore, there is no possibility of the planets in another formation. 2.) The warp feature simply allows the Police Cruiser to move between any two planets without them needing to be adjacent. The Rebel Beat-Up Smuggling Ship can only move between adjacent planets (see 0:34 to 0:45). Travel time between planets, regardless of how far apart they are, will take the same amount of time for both ships. (Yes, this is at odds with real-world physics. But treat it more like moving a game piece to a new spot as opposed to driving a car or flying a plane - as the video clearly intends.) Ultimately, each ship can move to a new planet each hour, or turn, only once because of the recharge time. 3.) The two ships cannot and will not meet during their jumps between planets. This is indicated in Rule #2 (1:08) which says, "Every hour, you MAY warp to any of the seven planets to search for the rebels there." Note the final word "there". This implies that the searching is *on* the planet not between planets. (Regardless, this point is absolutely demonstrated in the solution at point 4:13 to 4:15 when the Police move from Planet 3 to Planet 4 and the Rebels move from Planet 4 to Planet 3. If the Rebels could be found mid-flight, this move would not be possible.) 4.) Rule #3 (1:08) says, "Starting after your first search, the rebels MUST move every hour to a planet adjacent to their current location. They will not stay still." This very plainly states - along with the lines at 0:45 to 0:51 - that the rebels do not like to stay put and that they will relocate when they can. The only stipulation put on whether or not the rebels can relocate is the recharge time on their ship. The Rebels would never choose to stay put when they have the option to move. (Furthermore, this practically demonstrates that the Rebels do not know which planet the Police are on just as the Police do not know which planet the Rebels are on. If the Rebels knew, or could see, which planet the Police were on, they would either move in a different direction or just stay put. Since they do not have this information, they keep moving at every chance they get.) 5.) The "game", so to speak, began when the Rebels used their "turn" to pick a planet. Your turn begins with you choosing a planet to search. The hour it takes for the warp/jump features to recharge on the ships is the allotted search time. That is the end of turn 1 out of 10. Once the recharge/search hour is up, both players have another turn and can move again. The moves are made simultaneously, as both would move to a new planet as soon as possible, and a new search begins. End of turn 2 out of 10. Once that next hour is up, it is the start of another turn. This means that the Rebels cannot be on a planet you move to and then move while you are searching it but before you find them. Again, assume that this is like moving a game piece to a new space. Once both move, the search begins. If your move lands you on the same space that the Rebels are on, you find and capture them. 6.) Another note on Rule #2 (1:08), "Every hour, you MAY warp to any of the seven planets to search for the rebels there." You MAY move. This means that *you* may choose to stay put and see if the Rebels come to you. It is a valid strategy and one that MAY work in some scenarios. But you are not looking for a solution that works in *some* scenarios. Rule #6 (1:08), "Your sequence must be capable of finding the rebels in every possible scenario." If there is any way that the Rebels can escape when using a certain search option, that option is not a valid solution to the puzzle. (You can test your solution by playing as the Rebels and attempting to avoid the Police, who are searching according to your proposed solution. If you can escape, the solution fails. If you can't, it succeeds.) Your goal is to guarantee that you will catch the Rebels in 10 moves or less. without needing to know which planet they started on. If your solution allows for any escape, it cannot be trusted. 7.) It is possible the Rebels may decide to simply jump between 2 planets. As you do not know which planet they started on, simply staying on 1 planet in this scenario would never work unless you got lucky and chose either the planet they started on or the planet they move to second. And, as mentioned above, this solution is invalid as it does not guarantee success. There are a lot of riddles in the world that require you to have some bit of information that has not been given in the set-up and that you could not have known previously. These types of riddles are designed to be unsolvable and allow the "riddle" teller to laugh at you. This riddle is not one of those. It gives all the required information and the solution presented does not assume or use things that you are unaware of. It may require a bit of "outside the box" thinking, but that is what it and Brilliant is trying to teach you to do with these puzzles. Have I solved every TED-Ed riddle? No, of course not. But as far as I can remember, the ones I did not solve, and the logic behind them, were easy to understand once the solution was presented. In the end, if you think logically and are willing to work through the problem at hand, it can be solved. And, you might just learn something along the way.
Did u realise all planets r names of Star wars planets/moons with the wrong spelling. Endor Yavin 4 Bespin(on which cloud city is) Tatooine Dagobah Alderaan Kashyyyk
That last riddle was like math problem solving: John and Larry like to play minecraft, there are 76 people on their server but only 40 players have been to space. How many teeth does the crocodile have?
Easy, 40 is equal to 65 as proven by the amount of letters in seventy six when translated 40 times. crocodile has 10 letters including the space, and 65÷10 equals 6.5. The number for space is 0.5, adding that to 6.5 equals 7, and that's your answer!
That’s wrong because John has 4 letters and Larry has 5. 4 + 5 = 9. Add that to the 76 players to get 85. Subtract the ones that went to space. 85 - 40 = 45 Finally, the crocodile eats 1/3 of the population making the total 30
"Why in God's name would they bounce back and forth between 1 & 2?" You said "Why can't they just wait for them on planet #3?" and 1 is only connected to 2 and 2 is connected to 1 and 3. when you just stay put in 3 they only have the option of 1 and 2 as saying like you did... Why in God's name would they go to the planet where the police waits for them?
If someone had watched Titanic only once, then that person would know the answer immediately. Since both Harry and Ron did not know the answer initially, both must have watched it at least twice. Let us assume that Ron watched Titanic twice, and analyze the conversation in Ron's perspective. Ron knows that Harry watched Titanic either once or thrice. Thus initially Ron would not know if he watched Titanic more than Harry did. However, Harry said "me neither", which implies that Harry did not watch Titanic once. Hence Harry must have watched Titanic three times, which Ron now knows with certainty. So, Ron could reply "yes, indeed!". This time suppose that Ron watched Titanic three times. Then Ron knows that Harry watched Titanic either twice or four times. Again, Ron would not know if he watched Titanic more than Harry did. Now, assume that Harry watched Titanic two times. Then Harry initially knows that Ron watched Titanic either once or thrice. After listening to Ron's answer "I have no idea", Harry would then know that Ron had watched it three times. However, as Harry replied "me neither", Harry could not have watched Titanic two times. Therefore Ron knows that Harry watched Titanic four times. Next, assume that Ron watched Titanic four times. Initially Ron knows that Harry watched it either three times or five times. At this point Ron does not know if he watched Titanic more than Harry did. Now, let's say that Harry watched Titanic three times. Then Harry initially knows that Ron watched Titanic either two times or four times. In both cases, Ron would not know if he had watched it more times than Harry; thus Ron's reply "I have no idea" does not yet give additional information to Harry. Thus Harry replies "me neither". Ron also knows that Harry would not know the answer yet, whether Harry had watched Titanic three times or five times. Hence Ron also does not know the answer at this point, and therefore Ron wouldn't have replied "yes, indeed!". Therefore Ron did not watch Titanic four times. In a similar manner, if Ron had watched Titanic more than four times, then it would require a longer conversation for Ron and Harry to figure out the answer. In conclusion, Ron could have watched Titanic either 2 or 3 times. Therefore our answer is 2+3=5
Thank you for the answer. I honestly still dont get it but it is obvious that the second riddle is much harder than the first. I dont really get why does harry saying me neither imply that he didnt saw it only once?
Well, if Harry had only watched it once, he would know Ron had watched it twice (you're supposed to assume that 1 is the least times each of them may have watched the movie).
If you look closely at 0:12, you can see the info about the criminals. Here they are: Pete: RePete: Height: Height: 3'-ish 3'4.20 Weight: Weight: 80-something lbs 84.71072 lbs Wanted for: Wanted for: General Apathy Specific Larceny
I solved it, but it is hard to explain the whole method without a picture. The key that makes it possible is to realize that for any given start position, all the other positions can only be accessed either on an even turn or an odd turn. There are only two possible pictures of even/odd positions, depending on their start position. You assume one picture first, and alternatingly check each arm at the appropriate even/odd spot, and then the middle again to check that they didn't move to a different arm. If you don't find them after 5 moves (checking each arm once and the middle twice), your initial assumption was wrong, and you must use the other map of the even/odd positions and check again for 5 more moves in the same way.
Here’s the solution if someone’s looking: If someone had watched Titanic only once, then that person would know the answer immediately. Since both Harry and Ron did not know the answer initially, both must have watched it at least twice. Let us assume that Ron watched Titanic twice, and analyze the conversation in Ron's perspective. Ron knows that Harry watched Titanic either once or thrice. Thus initially Ron would not know if he watched Titanic more than Harry did. However, Harry said "me neither", which implies that Harry did not watch Titanic once. Hence Harry must have watched Titanic three times, which Ron now knows with certainty. So, Ron could reply "yes, indeed!". This time suppose that Ron watched Titanic three times. Then Ron knows that Harry watched Titanic either twice or four times. Again, Ron would not know if he watched Titanic more than Harry did. Now, assume that Harry watched Titanic two times. Then Harry initially knows that Ron watched Titanic either once or thrice. After listening to Ron's answer "I have no idea", Harry would then know that Ron had watched it three times. However, as Harry replied "me neither", Harry could not have watched Titanic two times. Therefore Ron knows that Harry watched Titanic four times. Next, assume that Ron watched Titanic four times. Initially Ron knows that Harry watched it either three times or five times. At this point Ron does not know if he watched Titanic more than Harry did. Now, let's say that Harry watched Titanic three times. Then Harry initially knows that Ron watched Titanic either two times or four times. In both cases, Ron would not know if he had watched it more times than Harry; thus Ron's reply "I have no idea" does not yet give additional information to Harry. Thus Harry replies "me neither". Ron also knows that Harry would not know the answer yet, whether Harry had watched Titanic three times or five times. Hence Ron also does not know the answer at this point, and therefore Ron wouldn't have replied "yes, indeed!". Therefore Ron did not watch Titanic four times. In a similar manner, if Ron had watched Titanic more than four times, then it would require a longer conversation for Ron and Harry to figure out the answer. In conclusion, Ron could have watched Titanic either 2 or 3 times.
Mr. Nice Man the answers can not be 2 times because both have them have to have watched the movie at least two time to start the conversation. If somebody has watched the movie only once, he would then only know he has watched it less times and would not initiate the conversation ( comes with the condition nobody has watched it zero times as i believe hermoine )
This riddle was super ambigous. They never explained whether the rebels and we move at the same time or after one another and even in the explanation video it jumped back and forth between the two scenraios. That makes it so much harder to solve since you have no idea which ruleset is the correct one.
Bonus riddle: Harry has watched it 4-5 times and Ron 3-4. Both results work. Ron and Harry are learning new information with each text, we just have to summarize it. 1: Harry and Ron know that they have watched the movie at least once, so, since Harry asks Ron if he has seen the movie more times than him, we know that Harry has seen it 2 or more times. 2: Since Ron doesn't know the answer, we now know that he hasn't seen it 2 times, but 3 or more, thanks to the new info adquired. 3: Harry answers that he (still) doesn't know either, so he has watched it 4 or more times. 4: Now Ron says that he knows, so he has watched it 3 or 4 times. Both work since we know that Harry has seen it 4+ times, so if Ron knows the answer now, he must have seen it 3 times (and Harry 4 since it's the minimum) or 4 times (and Harry 5, since it can't be the same number). Ron's number can't be 5, because knowing that Harry has watched it 4+ times, he could have seen it 4 or 6 times, so Ron can't be sure about his number being higher.
For everyone who thought staying on planet 3 was fine, they could just keep alternating between 2 planets on the outside, meaning you'll never catch them, etc. 7-6 x5, 5-4 x5, or 1-2 x 5, or vice versa, with starting on even numbers instead of odd
Look at the green alien officer at 0:10. He has a mouth but why is he sticking the straw in the protution on his face? Is it his nose or he just happens to have two mouths. OR it just happens to be an animation mistake.
I can do it in 6 visits. Imagine starting at the center. If that's where they were, you're done. If not, hop to one of the outermost planets. If you happen to hop to the outermost planet on the *correct* arm, you've either just caught them or forced them to hop to the center planet, and you'll catch them on your return. But if you jumped to the outermost planet on one of the two *incorrect* arms, they'll either hop to the center (you'll catch them on your return), or to an outer planet. They cannot at any point leave that arm, so you'll catch them when you reach that arm (or on the hop back to the center afterward). You'll notice that this method requires 7 moves. To get it down to 6, just skip the first visit to the center, it's superfluous. All it would accomplish would be to keep them from switching from one arm you haven't even checked yet to the other arm you haven't checked yet.
The rebels are not caught on their own turn. If the rebels move to the planet you just searched, they aren't caught unless you choose to search that planet again. Example: You search planet 7. The rebels are actually on planet 6, so you don't find them. Rebel's turn. They move to planet 7. Your turn. If you search 7 again, the rebels are caught, but ONLY if you search 7 again.
The space bandit riddle could be solved way easier if you start at planet 3 and go to planet 2 after that. After that you complete the first sequence because the bandits have to be at an even after the first turn. So it will only take you 6 warps in stead of 10.
It is waste of turn and makes it take 11 turns. 1 and 3 are neighbours of 2, 2 is neighbour of 1, 4 is neighbour of 5, 5 is neighbour of 4, 6 is neighbour of 7 and 7 is neighbour of 6. They could be on any planet.
Solution linked is *behind registration wall*, so no thanks. I was promised a link "straight to the" answer. "Your answer seems reasonable. Find out if you're right! [email/facebook/google+...]" Again, no thanks.
The answer was posted by Julia Chang one month before. Search for it in the comments. Harry : Did you watch Titanic more than I did? Ron : I have no idea! This blurb tells us three things: 1. Each must have watched the Titanic at least two times, otherwise one of them would have known definitely who watched more than the other. So somewhere there has to be a 2 to 3 ratio (one more than the other). That is the new status quo. 2. If Ron watched Titanic twice, he knows Harry must have watched Titanic three times and so game over. But Ron says he has no idea, so Ron must've watched it at least three times, as he does not know how many times Harry watched it. 3. Based off of number 2, if Ron watched Titanic at least three times, then Harry must either have watched Titanic two times or four times. Harry : Me neither. Do you know now? 4. So Harry doesn't know either. If Ron had watched Titanic at least three times and Harry himself knows he watched it only twice, then he would respond, "Oh, I know." But he doesn't know either, so Harry must have watched the Titanic at least four times. Ron : "Yes, indeed!" 5. Ok, so Ron gets the logic said above, and so he knows he has watched Titanic three times while Harry has watched the Titanic four times. (On a side note that also means that Ron must have watched it an odd number of times while Harry would watched it an even number of times.) Harry : Really? Then so do I. 6. When Ron said "Yes, indeed!" it is a confirmation to Harry that Ron watched Titanic only three times. He realizes that Ron must have watched Titanic one time less than him, and so knows the answer. Answer : At the minimum, Ron watched Titanic three times and Harry watched Titanic four times. The Final Question : What's the sum of the possible number of times that Ron watched Titanic? 7. Ron couldn't have watched Titanic once or twice, as it would have been evident right away in the conversation either to him or to Harry. We already proved that "3 times" is a viable answer choice for Ron. How about trying 4 times for Ron? We already know Harry must have watched Titanic at least four times, but both of them can't have watched Titanic the same number of times. So Ron definitely has not watched Titanic 4 times. So that pushes the ratio up to 4:5, meaning it's possible Ron has watched Titanic 5 times. If there were any number higher than 5 (for Ron), Ron would no longer know for a fact how many times Harry watched the Titanic and the conversation would not proceed in this fashion and would be greatly extended. Hence, to answer the question, there are only two possible times that Ron watched Titanic: 3 times and 5 times. 3+5= 8 I think the key to solving this problem is to trust your logic each step of the way and don't doubt what you just understood when using it to understand the next part. If there is a flaw to my logic, please do point it out.
@@frankmalenfant2828 or: ron watched titanic 1 time Line 1 Harry: have you watched more than me? Line 2 Ron: I dont know Line 3 Harry: I dont know either Line 4 Ron: Since you said that, now i know Line 5 Harry: And since you said *that,* now i know aswell because they both know one of them watched titanic 1 more than the other, if ron watched 1 time, harry would have watched it either 0 or 2 times, so when first asked, ron does not know (line 2). if harry watched 0 times, he would already know that ron watched more than him. but since he does not (line 3) this means he watched 2 times. Upon hearing this, ron knows that harry watch 2 times, so he knows himself (line 4). Harry realizes the logic above and because of this now knows himself (line 5) the assumption you made was that they had both watched at least 1 time, which i do not believe was said. even so, if ron had watched 2 times, he still would not know, at least until line 3. because harry could have watched it once, or twice. (perhaps you assumed line 1 as harry saying he does not know? this is not the case i believe. he is asking ron if ron knows, not saying he himself does not know)
I have always have fun on teded videos, but not this one, I hate the fact that the bonus riddle is not answered, I visit the ads, but it make me signing up, but after signing up? It told me to be premium member. duh.
Peace Guard 5 is the correct answer and also the answer on Brilliant. There are two different possibilities, Ron could have seen the movie either 2 or 3 times. It has already been explained multiple times, but in short: Ron isn't sure wether he saw it more often, so he must have seen it at least 2 times. Harry knows that and isn't sure neither, so he must have seen it at least 3 times. Now Ron knows, which means he either saw it 2 times and Harry 3 or 3 times and Harry 4. Thus, the answer is 2+3=5.
gnampf1234 I don't think Ron could have seen the movie 2 times. Suppose Ron saw the movie 2 times, that implies Harry saw it 1 or 3 time(s). Case 1: If Harry saw it only once, he wouldn't have bothered asking the first question, since he already knows Ron has seen it 2 times (0 is not possible). Case 2: If Harry saw it 3 times, he would ask Ron first question since he is not sure if Ron watched it 2/4 times. Now if Ron had watched it only twice, he would know Harry watched it 3 times exactly, since the other option (Harry watched only once) means Harry wouldn't have asked the question in the first place. So Ron would be able to answer as soon as Harry asks the first question.
“Hey, glass here, I can’t call in for work” “Why, they’re criminals, we need you!” “No... it’s to complicated, and my brain is fried” That would be my excuse if they asked me to do this...
What about 7-6-3-4-2-4? Land on 7 move to 6 then 3 = that row is clear and landing on 3 blocks their movement Move to 4 then 2 = only 5 is left as a possibility as if they're on 1 they have to move to 2 and be apprehended Move to 4 = if they were on 5 they would have to move to 4 Maybe I missed a rule but this seems easier.
Alright but what about this: Say you start at 3, and your pattern goes like this: 3, 7, 3, 5, 3, 1, 3. the video says they are forced to move every hour, so if they start on literally ANY of the 7 planets, you will have found them. returning to #3 every other time ensures they can never leave whichever pair of planets they are stuck on from the beginning.
nunya bizniz no they cant. in the 6th hour as you say, when they're on 2, you are on 1. at the end of the hour, it says they are FORCED to move, so they must move to either 1 or 3. if they move to 1, you're already there. if they move to 3, then you're going to catch them, because that's where YOU go next for your 7th hour. there's literally no way for them to escape, you've caught them in 7 turns or less.
Teve an important distinction is the order of operations. Cops move -> search -> rebels move. As we see at 2:00, the rebels can move onto the same planet as the cops. They aren't caught on arrival and are safe until the cops check the planet a second time.
The riddle was not explained in sufficient detail, i.e. how the moving works, are we warping while they are there or travelling? Who moves first? Because let's say we started at 1. And they are at 2. Clock starts ticking now? Or when they start travelling? Let's say it starts after they land. First move, they go to number 1. Do we decide to warp while they are there? When does our clock start? Let's say we warped to planet 2 while they are at number 1. When does to time start for the new move? If this is like chess, played in turn, how do we know when the other side's turn ended? Bad riddle.
I agree. I got confused at the start with "When I warp to the first planet, have they just moved, or are they still stationary till my next move?" They also didn't explain how many there were, and I originally assumed there were multiple members on multiple planets. Not clear enough starting information.
You can choose (3!)^2=36 different solutions, choose planet 3 on turns 2, 4, 7, and 9, for the first five rounds, you can choose 3!=6 ways to search planets 2, 4, and 6 on turns 1, 3, 5. You follow a similar pattern in the last five rounds. the rebels always move to an adjacent planet. But you can choose to move to any planet after another, you can even search the same planet twice in a row.
I think it's 3. When Rony answered for the first time, harry would knew that Rony watched at least 2 times, but he said that he didnt knew eighter, so Rony knew that Harry too watched at least 2 times, but since Harry wanst sure, Rony knew that Harry watched only 2 times, and then Rony watched 3.
Hi ikkeduitser! Thanks for playing along! We fixed the problem with the link to the bonus riddle solution, so now you can find it here: brilliant.org/TedEdTitanic/
I think I could solve this riddle in 6 moves - start on planet 3, either criminals start on odd or positive not 3, - you move to 1 and back to 3, if they were on either 1 or 2 you would have caught them if not repeat for the other two wings. My reasoning is if they start on 3 you catch them if not they start on positive or odd so moving to 1 means if they are there they are caught, if on 2 they move to 3, you then move to 3 and catch them. If not on 1 or 2 then repeat for 4&5 and 6&7.
This is a simple strategy that lets you catch them in under 10 moves. 1: Start at the 3rd planet. 2: If they are not there, move to one of the other planets nearby, 6, 2, and 4. 3: If they are not in those planets, they cannot go anywhere else other than back track to the original planet they were in. If they move to 3, we can catch them. If they dont, they back tracked. (If they back track) 4: Move to one of the middle planets. If they arent in the one you went to, they can now only move to the same outer planet or planet 3. You can repeat as much as you want, as long as you do it in under 10 turns.
2024 here. For the first riddle I chose to stay on planet 3 throughout as the riddle says you MAY move, but they MUST. In 10 moves it is impossible for them to stay alternating between the planets on one end. They'd meet me at the junction definitely😊
This galaxy sounds very familiar. In my galaxy we have 1-Endor 2-Yavin IV 3-Bespin 4-Tatooine 5-Dagobah 6-well... we used to have Alderaan 7 and Kashyyyk
Hello Ted-Ed. Although your riddles are most often presented with clear rules so that we are given a chance to solve them, this one seems quite flawed to me. I might of course be mistaken. It isn't said clearly whether police and rebels move simultaneously or by turn. In the first explanation for a 5-planets cluster, you say rebels can be found in 2 moves. Well in that case it means they move simultaneously with police. Why so ? Because if i don't find them at first on center planet it means they were on center planet and moved to an external planet as police was warping to center planet. If that wasn't the case i.e if they were moving by turn, and police goes to center planet, either they find the rebels there, or either the rebels started on external planet and come to the center planet right after, thus stumbling onto the police. the 5-planets cluster would actually be solved in 1 move, which isn't the case according to you. So it implies that police and rebels move *simultaneously*, ok. But in the explanation of the actual riddle, you seem to imply police and rebels move by turn. At 2:35 it is said that rebels can be on either planet 3,5 or 7, and then as you simulate police moving to planet 3 and finding nothing, the conclusion is "they were not on planet 3". Okay, so it isn't considered that rebels might have been on planet 3 and moved elsewhere during police warp to planet 3. Which means rebels move *after* police has moved and not in the meantime. The riddle isn't coherent on that. Cheers
I was assuming simultaneous moves based on the description at the beginning (0:40 - "their beat-up smuggling can only jump to an adjacent planet in THAT SAME TIME"). This makes it harder (if not impossible) as the rebels could slip by planet 3 when you move off of it. e.g. you move from 3 -> 4 and they move from 6->3 on one turn, then you move 4 ->3 while they move 3 -> 2.
Some instruction are unclear. Because i think the rebel and police are move in same time. It means when police in planet 2, and go to planet 1, rebel can go undetected from planet 1 to planet 2. Nice riddle tho.
Here's what seems like a 9-move solution to the seven planets problem: 2-2-3-4-3-4-3-6-6. The first three moves clear out one arm. The next three moves clear a second arm while preventing access to the first arm. The last three moves clear the last arm. Did I miss something? Are there even better solutions, or is 9 the minimum?
Yeah...no. As soon as the force goes to 4, the dark side can go to 3, then to 2, so they are now in the first arm :') Going by your moves, their moves can be: 6-7-6-3-2-... good try though. loving these puzzles XD
if you arrive at 4 and searched, then the rebels do their move and can jump from 5 to 4, you only search on arrival. Then if you jump back to 3 to see if the other branch didn't jump there, then rebels on 4 can follow you to 3 after searching there. And then if you don't revisit 3, they can escape in the cleared branch. 2-2-3-5-3-5-3-7-3-7 seems and alternate sollution based on your strategy
"They must cross over to the left bank of a crocodile infested water." Solution: Wait until the crocodiles die, because that water looks like slime. Then, jump on the corpses and get to the other side :D
"Every time they can relocate, they will." Does this mean that if the cops are on the planet they would have to move to (say they are on the outside and the cops are one planet inward), then they *can't* relocate, therefore they won't? If you follow the list instructions when they summarize it, it says that they MUST move every hour. So there is no implication that there is any situation where they can't. See, I have a solution that works if they absolutely must move each hour, guaranteed, and it gets them in 7 moves if that is the case. So... honestly this feels important to know for sure. The use of the word "can" implies there might be a situation where they can't (blocked route), yet the use of the word MUST (in all caps in the video even) tells me that there's no such situation. So what's the deal? Would my solution be valid?
I found a different solution i think. 1+2: We start on an even planet, waiting one round, so we can ensure there didn't start on that outer planets too. 3: We then move to the middle planet. They have to be in one of the other two planet rows. 4: We go to one outer Planet, because if they are on an even planet, their next move will go to the outer planet, where we would get them, or the middle planet. If they are on the outer planet we get them immediatly. 5: As they could have been on the even planet, we have to go to the middle planet again, where we would get them too, if they were on the other row. 6: From there on we just go towards the last two planets, going first for the even planet. 7: As our seventh move we would get them on the outer planet. That seems correct, right? I don't know any move or starting position by them where we couldn't get them.
So If the east example problem was: 6 | 3 - 4 | 2 And if the actual problem was: 7 | 6 | 3 - 4 - 5 | 2 | 1 Then can anyone solve (with any number of moves) this: 9 | 7 | 6 | 3 - 4 - 5 - 8 | 2 | 1 | 0 Reply if you have a answer :D
If you want to practice more problem-solving for free, head to brilliant.org/TedEd/. If you want to signup for a "premium" account, hurry! The first 833 of you to visit that link will receive 20% off the annual premium subscription. Thanks to Brilliant for supporting this video!
TED-Ed hi love the videos
TED-Ed Thank you. I love your videos.
TED-Ed Im gonna try this
I hate how you're forced to pay to know the solution of the bonus puzzle
Awesome
Some food for thought. If Harry and Ron were both perfect logicians, they could theoretically continue with that same line of questioning ( "Do you know now?" "No" "Me neither. Do you know now?" over and over again) and they would eventually figure out how many times the other person has seen Titanic, even if its a really high number.
The logic for it works as follows:
Since neither of them know the answer from the start (Ron saying "I have no idea" and Harry saying "Me neither") they can both safely assume they've both watched Titanic at least twice. This is because if one of them only saw it once, they would immediately know the other person's seen it more times. However, when Harry asks Ron "Do you know now?", one of two things can happen. Ron could have seen it twice and deduced that Harry must have seen it three times (because they both know they've both seen it at least twice), and Ron says "yes! I know now" OR Ron saw it MORE than twice and answers with "No I still don't know". If Harry responds "Me neither" that means he TOO must have seen it more than twice, and at that point they both know they have both seen Titanic at least three times. This can continue on ad infinitum until the answer is revealed. For example, if Ron saw Titanic... say... 15 times (dear lord), when they reach the point where they both know they have both seen Titanic at least 15 times, Ron will answer with "Yes I do know now!" properly deducing that Harry must have seen it 16 times. All of this said, they could simply just TELL each other how many times they've seen Titanic. But if I saw Titanic 15 times, I wouldn't want to tell anyone either ;p
If anyone actually read this, wow good job.
yes i read it
metoo
So essentially it's the same logic as the green eyes riddle, where by not doing anything more information is revealed just from the stalling
@@Reletr That's what I thought of. The clock on that problem is set by the number of green eyed creatures, whereas this one is just set by the number of times the movie has been seen. I expect that the result would be similar in a riddle involving multiple people having all seen Titanic a unique number of times.
So Ron saw it twice and Harry saw it three times in the provided example, right? Or am I not caffeinated enough this morning?
Assuming Harry and Ron are perfect logicians, Harry has watched it 4 times, Ron 3. Here's the steps:
A). Harry asks Ron if he's seen it more. This shows the score isn't H1, R2, because if it were, Harry would realize since he's only seen it once, Ron would have had to see it twice, and wouldn't have texted Ron to ask. Therefore, Harry has seen it at least twice.
B) Ron says he doesn't know. This shows the score isn't H2, R1, because if it were, Ron would realize since he's only seen it once, Harry would have had to see it twice. Therefore, Ron has to have seen it twice.
C) Ron also know, that because Harry asked in the first place, Harry *also* must have seen it at least twice (see A). If Ron had seen it exactly twice, that means Harry has watched it three times, and Ron would know the answer. Because he didn't, this means Ron has seen it at least 3 times.
D) Because (B) and (C), Harry knows Ron has seen it at least 3 times. But he still doesn't know if he's seen it more or not. This means he's seen it more than twice (because he'd know that he'd seen it twice so ron saw it 3 times), and he's seen it more than three times (because he'd know if he saw it three times, then ron had watched it 4 times). Because Harry doesn't know, he's seen it at least 4 times.
E) Now Ron knows! Because Harry has seen it at least 4 times, and he knows he himself only saw it 3 times, we have a match. Harry 4, Ron 3.
It's also possible for Ron to have 4, and Harry 5, and Ron could have
deduced that this round as well. So the solution is a bit ambiguous. However, beyond those two outcomes, if Ron had seen more than 4, then there still wasn't enough information and Ron wouldn't have been able to say he'd figured it out when he did.
It's not ambiguous, the dude says at the end there are multiple solutions by asking for the sum of the possible times Ron has watched it. So the answer is 7
Well ... There is one assumption you are making here. Basically in point A .. you are assuming harry asking ron if he knows who has seen it more times implies harry does not know right away. At this point in time, the answer might indeed be H1, R2 and harry knows that Ron has seen more times, yet still asks Ron if he knows (which he wouldnt since it could very well be H3,R2 for all he knows). This assumption changes the solution quite a bit. If you don't make the assumption that harry asking ron if ron knows implies harry doesn't outright know, then the possible answers are H3, R2 and H4, R3
Ron could have watched it either 3 or 4 times so the answer is 7
uh
Ron did 91 times
Harry did 73 times
:3
what makes you a eligible detective?
*I solved a ted ed video before the timer ran out*
Holy sh-
It is true lol
The timer is three seconds Jesus Christ
without pausing that is
That’s some god tier detective
You're lying!!!!!!!!!!!
Me: Okay I'm gonna try to solve the riddle this time
Inner me: You know you want to see that answer
lol basically me all the time
Yeah me too 😂
I see u every where
Me 2
not me
Harry: "Hey, Ron! So how many times did you watch Titanic?"
Ron: "Hey, Harry! I reckon I watched it 127 times. How about you?"
Harry: "You're a sick sick man, Ron. I watched it only twice. The first time was when it was originally released, and the second time was when it came in 3D."
Ron: "Oh. Okay. Bye bye then."
The amount of hours he lost by watching Titanic..
@@eagletgriff in today's technology you can speed up videos. Ron can watch it 127 times in 10 mins.
When you realized that the planets names are a rip off/discounted version of star wars
Dias Amreé
127?
_Like NCT 127?!?_
Sorry I had to
*I’ll leave now*
#ANIMATEona hello fellow nctzen
Tip for the rebels:
Confirm they have green eyes
Ask the police if they can leave
Died
The police respond ‘Uzu’
@@supermouse73 That must mean that one of them is Lying and thus, possesed.
Then the janitor can cross the river with the lion
@@supermouse73 it’s ulu
Endorra = Endor
Yavine Fore = Yavin IV
PinBes = Bespin
Tattooide = Tatooine
Dagovah = Dagobah
Aldoran = Alderaan
Cashyyyyk - Kashyyyk
I wasn't the only one...
Awesome
Does Kashyyyk really have 3 Ys? That’s too much, man
I caught that too
Oh you know your planets
cant help but notice the ad-blocker plug-in on the screenshot @5:24
wenzjayy same
shhhhh..
TED-Ed's security will come and get you.
Yikes
wenzjayy yes
Just party on planet 3 until aliens arrive and then invite them over too for a big bang
Exactly, they'd come there on the third step anyway
I assume they wouldn't intentionally run into the planet with the police, so they would hop between the outer two planets.
if they started at 2,4 and 6 the chance for them not to visit 3 ever would be less than 0,01%, and you could just fly away from 3 and return to catch them
@@The360MlgNoscoper That is, assuming they move randomly
@@akshyun8920 they must move
Why are Harry and Ron texting each other? Didn't they live in the same room?
How do they have cellphones?
nicemelbs, and why are they using phones?
Yeah, they also aren't aliens and don't have cell phones. It's a fictional scenario; just roll with it.
NoriMori they're sorcerer tho they could make themselves like aliens and have phones
IT'S A....... ! ! !
CANON
This riddle is really cool! I have seen the linear version before where all of the "planets" are aligned in 1 dimension. I haven't seen the split on the third planet before. It is also nice to see that the same line of reasoning works in both cases. The key to note in these types of puzzles is when given that one side MUST do something in a oscillatory fashion, you can take advantage of that. For example, this is applicable in certain chess positions. Surprisingly, the linear case comes down to needing 2(n-2) steps to win, but this branched case also seems to need the same number of steps.
oh yes, the hiding cat puzzle
Second dimension, not third.
“Mom, can I have a list of planets from Star Wars?”
“We have a list of planets from Star Wars at home”
The list of planets from Star Wars at home: 0:17
True
Yep
Lol
Eks dee
At me I’m saying the other place and they say yes so yes since I never watch Star Wars
I paused the video for two days until I finally got it! I was tired of not being able to solve these. These riddle videos are so good been following them for years, I love them! Keep'em up!
Congratulations! It takes grit, brains and determination to solve this one.
I must add that I was not the whole two days fully trying to solve it haha. I took like 1.5 hour each day during work when I didn't have much to do. But yeah, it was hard, it took me quite a few sheets and a pen to trace every pattern.
Bonus riddle answer - Harry asks Ron whether he had watched titanic more times, therefore he does not know himself. If he had watched it only once, then he would have known. Therefore- Harry watched titanic at least twice.
Then Ron answers that he does not know. If Ron had watched titanic exactly twice then he would have known that Harry must have watched it 3 times, therefore Ron must have watched it at least 3 times.
Harry then answers that he still doesn't know. If harry had watched it exactly 3 times, then he would have known that Ron must have watched it 4 times, and so he watched it at least 4 times.
Ron then says that he does know whether he watched more times or not. That can only be the case if he watched it 3 times or 4 times, because then he would know that harry must have watched it 4 or 5 times respectively. So Ron must have watched titanic either 3 or 4 times, so their sum is 7.
Then this look would keep going until they hit over 100 times. Each would just keep saying "I don't know, do you know now?" "No, I don't. Do you know now?" Each time ups the number for each.
The logic is correct, but I think the website messed up and didn’t count Harry’s first question as an “I don’t know” for Harry, so the ‘actual’ answer is 5 (2+3 rather than 3+4), seeing as there is one less “I don’t know” moment.
It is possible to ask if someone else knows something you already know, so harry's first question gives no information to Ron and the answer is 5
😓😓😓😓😓😓😓😓😓😓😓😓😓😓
oren shacham I understand the logic behind, it yet wouldn’t this riddle be slightly misleading if the audience was not aware whether both Ron and Harry were aware of the minimum possible number of times the other watched the movie? The riddle is plausible but, to me, it seems slightly illogical.
comment section be like
70%: star wars
15%: harry potter
5%: actually did the riddle/bonus riddle
other 5%: dem voice so soothing-
other other 5%: green fly double mouth nose thingy
1% explaining an easy answer to the riddle/bonus riddle (me)
The rebels must not escape!
*Darth Vader Breathing.*
The names of the planets are litterally inspired by Star Wars
Well don't tell that to Solo.
Just be careful not to drop out of hyperspace too close to the system or they will raise the shield.
*are we the bad guys?*
Darth vader Noises
Did anyone notice its the names of planets from star wars but wrong spelling
Aditya Parab love it!
Duh
its because of copyright
No, and because of that you are a literal genius. Congratulations.
Interesting. Don't know much about the Star Wars universe, but I I knew I regonized some of 'em.
“Your friends harry, ron, and hermione”
**sounds of harry potter fans screaming intensifies**
Yass
yes
_Ravenclaw_ 💙
Hogwarts riddles?
*intensify**
One of the planets looks like a marshmallow
Amy Lu yeah four
Amy Lu yea they r actually candy planets
@user name yeah its 2 *planet 2*
Thats a tasty planet
Amy Lu planet five is just chalos. (Comment "🧀" if you get it)
If harry and Ron are smart, then the answer is
JUST TEXT THE NUMBERS TO EACH OTHER
who else is just here for the relaxing voice?
Me!
Meeeeee
Me
Meeeeeeee
Addison Anderson REALLY does have a soothing voice...
The Star Wars reference is strong with this video
made my day
Hmm yed
oppa gangnam Harry Potter references, you’re in Gryffindor!
lol.
Lol
The answer is 5
A) Harry asks Ron. It means H > 1 he wouldn't ask elsewhere.
B) Ron doesn't know. It means
R > 1. If it was he would've known.
C) Harry still doesn't know. Therefore H > 2.
D) Ron knows already. It means
R < 4. If he watched it 3 times Harry watched 4 and if he watched twice Harry watched 3 times. If Ron watched Titanic 4 times, he wouldn't know if Harry did it 5 times.
E) if Ron already knows the answer R < H. Otherwise Ron wouldn't know yet.
And if H = 3 -> R = 2
If H = 4 -> R = 3
If H = 5 or more -> R doesn't know yet
If H = 2 or less -> H would've already known before then.
F) Left possibilities are R = 2 or 3
Sum of which is 5
If R = 2, H can be 1 or 3
If H = 1, Harry would've not asked the first question. So Ron would know that H = 3 and he wouldn't reply by saying "No idea!"
So I believe R = 2 should not be a possible solution. Correct me if I'm wrong though.
@@akshaydamle95 I also thought about it, but If Harry knows how many times he watched titanic, which we assume: he does.
He should follow the same logic ( at least to some point ) as I did. Therefore if he knew possible answers are R=2 or R=3, he would immediately know the answer
If H=3, then R=2
If H=4, then R=3
Because he didn't know the answer we have to assume he couldn't follow the Ron's logic.
In conclusion: because Harry didn't know whether R=2 or 3, we can't know either.
But I'm glad you asked.
Why not seven? ( joking )
A friend of mine told me about this question last night, I found a similar solution but in my case the police car doesn't need to move more than one planet per hour (instead it stays on the same planet for two hours, basicaly it's the same trick): 2-3-4-3-6-6-3-2-3-4. This remind me chess. For example in an end-game of king and rook against king it's well known that to achieve checkmate you have to do a sort of "opposition" with kings and then push the rook in the same row/column of the opponent's king. To allow it, if the kings are not "synchronized", you need to loose a tempo by moving your rook. This is the same idea of loosing a tempo to "synchronize" cars by mooving of two planets or by staying on the same planet. Very interesting, thanks!
does no-one notice the rules at 1:08 go 1,2,3,5,6?
WHERE IS 4!!!
Pranked
It's on Yavine Fore.
No one noticed that because no one reads the rules again, they just want to see the answer
Good eye tho
thx@@cobcorn8749
I want to clarify a few things for everyone who doesn't understand (as there are quite a few comments demonstrating some confusion):
1.) The layout of the planets is as shown in the video. There is no need for TED-Ed to explicitly state that the planets are in that layout as we are introduced to the planets by being shown that specific layout at 0:16 and are given no other possibilities. If the layout of the planets could be different, the video would have mentioned something along the lines of, "Let's assume the planets are in this configuration" or, "If the planets are in this configuration, we can use this method." It says neither, and just introduces the planets in the Y formation and never changes it. Therefore, there is no possibility of the planets in another formation.
2.) The warp feature simply allows the Police Cruiser to move between any two planets without them needing to be adjacent. The Rebel Beat-Up Smuggling Ship can only move between adjacent planets (see 0:34 to 0:45). Travel time between planets, regardless of how far apart they are, will take the same amount of time for both ships. (Yes, this is at odds with real-world physics. But treat it more like moving a game piece to a new spot as opposed to driving a car or flying a plane - as the video clearly intends.) Ultimately, each ship can move to a new planet each hour, or turn, only once because of the recharge time.
3.) The two ships cannot and will not meet during their jumps between planets. This is indicated in Rule #2 (1:08) which says, "Every hour, you MAY warp to any of the seven planets to search for the rebels there." Note the final word "there". This implies that the searching is *on* the planet not between planets. (Regardless, this point is absolutely demonstrated in the solution at point 4:13 to 4:15 when the Police move from Planet 3 to Planet 4 and the Rebels move from Planet 4 to Planet 3. If the Rebels could be found mid-flight, this move would not be possible.)
4.) Rule #3 (1:08) says, "Starting after your first search, the rebels MUST move every hour to a planet adjacent to their current location. They will not stay still." This very plainly states - along with the lines at 0:45 to 0:51 - that the rebels do not like to stay put and that they will relocate when they can. The only stipulation put on whether or not the rebels can relocate is the recharge time on their ship. The Rebels would never choose to stay put when they have the option to move. (Furthermore, this practically demonstrates that the Rebels do not know which planet the Police are on just as the Police do not know which planet the Rebels are on. If the Rebels knew, or could see, which planet the Police were on, they would either move in a different direction or just stay put. Since they do not have this information, they keep moving at every chance they get.)
5.) The "game", so to speak, began when the Rebels used their "turn" to pick a planet. Your turn begins with you choosing a planet to search. The hour it takes for the warp/jump features to recharge on the ships is the allotted search time. That is the end of turn 1 out of 10. Once the recharge/search hour is up, both players have another turn and can move again. The moves are made simultaneously, as both would move to a new planet as soon as possible, and a new search begins. End of turn 2 out of 10. Once that next hour is up, it is the start of another turn. This means that the Rebels cannot be on a planet you move to and then move while you are searching it but before you find them. Again, assume that this is like moving a game piece to a new space. Once both move, the search begins. If your move lands you on the same space that the Rebels are on, you find and capture them.
6.) Another note on Rule #2 (1:08), "Every hour, you MAY warp to any of the seven planets to search for the rebels there." You MAY move. This means that *you* may choose to stay put and see if the Rebels come to you. It is a valid strategy and one that MAY work in some scenarios. But you are not looking for a solution that works in *some* scenarios. Rule #6 (1:08), "Your sequence must be capable of finding the rebels in every possible scenario." If there is any way that the Rebels can escape when using a certain search option, that option is not a valid solution to the puzzle. (You can test your solution by playing as the Rebels and attempting to avoid the Police, who are searching according to your proposed solution. If you can escape, the solution fails. If you can't, it succeeds.) Your goal is to guarantee that you will catch the Rebels in 10 moves or less. without needing to know which planet they started on. If your solution allows for any escape, it cannot be trusted.
7.) It is possible the Rebels may decide to simply jump between 2 planets. As you do not know which planet they started on, simply staying on 1 planet in this scenario would never work unless you got lucky and chose either the planet they started on or the planet they move to second. And, as mentioned above, this solution is invalid as it does not guarantee success.
There are a lot of riddles in the world that require you to have some bit of information that has not been given in the set-up and that you could not have known previously. These types of riddles are designed to be unsolvable and allow the "riddle" teller to laugh at you. This riddle is not one of those. It gives all the required information and the solution presented does not assume or use things that you are unaware of. It may require a bit of "outside the box" thinking, but that is what it and Brilliant is trying to teach you to do with these puzzles.
Have I solved every TED-Ed riddle? No, of course not. But as far as I can remember, the ones I did not solve, and the logic behind them, were easy to understand once the solution was presented. In the end, if you think logically and are willing to work through the problem at hand, it can be solved. And, you might just learn something along the way.
Oh my gosh yay! I love these riddle videos 🙋🏻
They're the only ones I ever watch!
Yeah and there was a bonus riddle too!
LOL, they actually liked our comment.
You have been featured in the tree pirate thingy puzzle!!
ikr i see her comment on every vid i go to
Did u realise all planets r names of Star wars planets/moons with the wrong spelling.
Endor
Yavin 4
Bespin(on which cloud city is)
Tatooine
Dagobah
Alderaan
Kashyyyk
Yeah, I noticed.
Aamu Rantala (Probably)
Granth Tiwari My favourite is not there D: (Mustafar)
Yeah I also noticed
Shengyang Quek well it’s not Anakin’s favourite
That last riddle was like math problem solving:
John and Larry like to play minecraft, there are 76 people on their server but only 40 players have been to space. How many teeth does the crocodile have?
Easy, 40 is equal to 65 as proven by the amount of letters in seventy six when translated 40 times. crocodile has 10 letters including the space, and 65÷10 equals 6.5. The number for space is 0.5, adding that to 6.5 equals 7, and that's your answer!
That’s wrong because John has 4 letters and Larry has 5.
4 + 5 = 9. Add that to the 76 players to get 85. Subtract the ones that went to space. 85 - 40 = 45
Finally, the crocodile eats 1/3 of the population making the total 30
0, Mojang hasn't added crocodiles yet😜
@@rigure r/ruinedthejoke
green eyes
I want an interactive version of the riddle, playable from both sides
Agreed
Play Scotland Yard
Why can't they just wait for them on planet #3?
They can bounce between 1 and 2
That could work realistically but we are looking for a method that works 100% of the time
Why in God's name would they bounce back and forth between 1 & 2? Nobody tries to avoid the cops by alternating between two locations...
"Why in God's name would they bounce back and forth between 1 & 2?"
You said "Why can't they just wait for them on planet #3?" and 1 is only connected to 2 and 2 is connected to 1 and 3. when you just stay put in 3 they only have the option of 1 and 2 as saying like you did... Why in God's name would they go to the planet where the police waits for them?
The riddle implied that the criminals would not know which planet you were on since you "warped" there.
Ted Ed: Apprehend the group of rebels
Me: I dont work for the empire
Time to watch another video to make yourself feel that you've gotten smarter, but we all know the reality.
Time to continue writing my bachelor thesis then.
“More Smarter” 🤨
Henry Zeigerson I just noticed, tysm!
Ayush Kumar lol
Ayush Kumar ha ha ha🤣
Can someone post the answer to the second riddle?
If someone had watched Titanic only once, then that person would know the answer immediately. Since both Harry and Ron did not know the answer initially, both must have watched it at least twice.
Let us assume that Ron watched Titanic twice, and analyze the conversation in Ron's perspective. Ron knows that Harry watched Titanic either once or thrice. Thus initially Ron would not know if he watched Titanic more than Harry did. However, Harry said "me neither", which implies that Harry did not watch Titanic once. Hence Harry must have watched Titanic three times, which Ron now knows with certainty. So, Ron could reply "yes, indeed!".
This time suppose that Ron watched Titanic three times. Then Ron knows that Harry watched Titanic either twice or four times. Again, Ron would not know if he watched Titanic more than Harry did. Now, assume that Harry watched Titanic two times. Then Harry initially knows that Ron watched Titanic either once or thrice. After listening to Ron's answer "I have no idea", Harry would then know that Ron had watched it three times. However, as Harry replied "me neither", Harry could not have watched Titanic two times. Therefore Ron knows that Harry watched Titanic four times.
Next, assume that Ron watched Titanic four times. Initially Ron knows that Harry watched it either three times or five times. At this point Ron does not know if he watched Titanic more than Harry did. Now, let's say that Harry watched Titanic three times. Then Harry initially knows that Ron watched Titanic either two times or four times. In both cases, Ron would not know if he had watched it more times than Harry; thus Ron's reply "I have no idea" does not yet give additional information to Harry. Thus Harry replies "me neither". Ron also knows that Harry would not know the answer yet, whether Harry had watched Titanic three times or five times. Hence Ron also does not know the answer at this point, and therefore Ron wouldn't have replied "yes, indeed!". Therefore Ron did not watch Titanic four times.
In a similar manner, if Ron had watched Titanic more than four times, then it would require a longer conversation for Ron and Harry to figure out the answer.
In conclusion, Ron could have watched Titanic either 2 or 3 times. Therefore our answer is 2+3=5
wow
Thank you for the answer. I honestly still dont get it but it is obvious that the second riddle is much harder than the first. I dont really get why does harry saying me neither imply that he didnt saw it only once?
Also who is to say that someone didnt watch Titanic zero times and the other one time
Well, if Harry had only watched it once, he would know Ron had watched it twice (you're supposed to assume that 1 is the least times each of them may have watched the movie).
The true bonus riddle is how and why does hermone know how many times Ron and Harry have seen Titanic
No, but can you solve this riddle?
“What goes up that must come down?”
My self esteem 😭
LMAO
Maybe it never went up in the first place
My morning wood.
I️ thought that before pressing read more!
+FRISHR ? I don't get it
electronic gadgets such as phones dont work in Hogwarts.......riddle is a LIE!!!!!!
Who said it has to be in Hogwarts? It could be in their homes
“iTs iN hOGwArTS A hIstORy” commented Hermione
What about Colin Creevey's camera?
I don't think they are at Hogwarts if they were why wouldn't they just talk
Ron is a wizard and wizards dont use TV.
If you look closely at 0:12, you can see the info about the criminals. Here they are:
Pete: RePete:
Height: Height:
3'-ish 3'4.20
Weight: Weight:
80-something lbs 84.71072 lbs
Wanted for: Wanted for:
General Apathy Specific Larceny
TED EEDDD! I LOVE YOU♥
Our school used this for their Math Olympiad. This helped a lot!
0:17 very long pause -- 1:07 barely any time to read -- 1:23 loud volume change -- 4:29 very loud volume change
Doctor: you have 6 minutes to live
Me: *watches video*
REALLY?!?!?
Ahaha wow that's so hilarious!!
You missed 1 second
damn, you still can’t finish it...
Hexpresso no that's a lie
I solved it, but it is hard to explain the whole method without a picture. The key that makes it possible is to realize that for any given start position, all the other positions can only be accessed either on an even turn or an odd turn. There are only two possible pictures of even/odd positions, depending on their start position. You assume one picture first, and alternatingly check each arm at the appropriate even/odd spot, and then the middle again to check that they didn't move to a different arm. If you don't find them after 5 moves (checking each arm once and the middle twice), your initial assumption was wrong, and you must use the other map of the even/odd positions and check again for 5 more moves in the same way.
TED-ed: can you solve the seven planets riddle?
Me: ozo
Here’s the solution if someone’s looking:
If someone had watched Titanic only once, then that person would know the answer immediately. Since both Harry and Ron did not know the answer initially, both must have watched it at least twice.
Let us assume that Ron watched Titanic twice, and analyze the conversation in Ron's perspective. Ron knows that Harry watched Titanic either once or thrice. Thus initially Ron would not know if he watched Titanic more than Harry did. However, Harry said "me neither", which implies that Harry did not watch Titanic once. Hence Harry must have watched Titanic three times, which Ron now knows with certainty. So, Ron could reply "yes, indeed!".
This time suppose that Ron watched Titanic three times. Then Ron knows that Harry watched Titanic either twice or four times. Again, Ron would not know if he watched Titanic more than Harry did. Now, assume that Harry watched Titanic two times. Then Harry initially knows that Ron watched Titanic either once or thrice. After listening to Ron's answer "I have no idea", Harry would then know that Ron had watched it three times. However, as Harry replied "me neither", Harry could not have watched Titanic two times. Therefore Ron knows that Harry watched Titanic four times.
Next, assume that Ron watched Titanic four times. Initially Ron knows that Harry watched it either three times or five times. At this point Ron does not know if he watched Titanic more than Harry did. Now, let's say that Harry watched Titanic three times. Then Harry initially knows that Ron watched Titanic either two times or four times. In both cases, Ron would not know if he had watched it more times than Harry; thus Ron's reply "I have no idea" does not yet give additional information to Harry. Thus Harry replies "me neither". Ron also knows that Harry would not know the answer yet, whether Harry had watched Titanic three times or five times. Hence Ron also does not know the answer at this point, and therefore Ron wouldn't have replied "yes, indeed!". Therefore Ron did not watch Titanic four times.
In a similar manner, if Ron had watched Titanic more than four times, then it would require a longer conversation for Ron and Harry to figure out the answer.
In conclusion, Ron could have watched Titanic either 2 or 3 times.
Wow biiiigg
Answer is either 3or 4 times
Abhinav Ranaut bro I didn’t write this, this is the legit answer on the web lol
.
Mr. Nice Man the answers can not be 2 times because both have them have to have watched the movie at least two time to start the conversation. If somebody has watched the movie only once, he would then only know he has watched it less times and would not initiate the conversation ( comes with the condition nobody has watched it zero times as i believe hermoine )
Please make more riddles more often!! Thank you!!😊 BTW I love your videos and I am inspired by them. Thanks you all for being amazing.
This riddle was super ambigous. They never explained whether the rebels and we move at the same time or after one another and even in the explanation video it jumped back and forth between the two scenraios. That makes it so much harder to solve since you have no idea which ruleset is the correct one.
I agree
This
Didn't they say they move at the same time
Basically what happened to me
Did you not read the rules?
i love how the planets are named after star war planets lol
Bonus riddle:
Harry has watched it 4-5 times and Ron 3-4. Both results work.
Ron and Harry are learning new information with each text, we just have to summarize it.
1: Harry and Ron know that they have watched the movie at least once, so, since Harry asks Ron if he has seen the movie more times than him, we know that Harry has seen it 2 or more times.
2: Since Ron doesn't know the answer, we now know that he hasn't seen it 2 times, but 3 or more, thanks to the new info adquired.
3: Harry answers that he (still) doesn't know either, so he has watched it 4 or more times.
4: Now Ron says that he knows, so he has watched it 3 or 4 times.
Both work since we know that Harry has seen it 4+ times, so if Ron knows the answer now, he must have seen it 3 times (and Harry 4 since it's the minimum) or 4 times (and Harry 5, since it can't be the same number).
Ron's number can't be 5, because knowing that Harry has watched it 4+ times, he could have seen it 4 or 6 times, so Ron can't be sure about his number being higher.
For everyone who thought staying on planet 3 was fine, they could just keep alternating between 2 planets on the outside, meaning you'll never catch them, etc. 7-6 x5, 5-4 x5, or 1-2 x 5, or vice versa, with starting on even numbers instead of odd
Look at the green alien officer at 0:10. He has a mouth but why is he sticking the straw in the protution on his face? Is it his nose or he just happens to have two mouths. OR it just happens to be an animation mistake.
They are aliens, can have 2 mouths, or drink via nose too
I can do it in 6 visits. Imagine starting at the center. If that's where they were, you're done. If not, hop to one of the outermost planets.
If you happen to hop to the outermost planet on the *correct* arm, you've either just caught them or forced them to hop to the center planet, and you'll catch them on your return.
But if you jumped to the outermost planet on one of the two *incorrect* arms, they'll either hop to the center (you'll catch them on your return), or to an outer planet. They cannot at any point leave that arm, so you'll catch them when you reach that arm (or on the hop back to the center afterward).
You'll notice that this method requires 7 moves. To get it down to 6, just skip the first visit to the center, it's superfluous. All it would accomplish would be to keep them from switching from one arm you haven't even checked yet to the other arm you haven't checked yet.
The rebels are not caught on their own turn. If the rebels move to the planet you just searched, they aren't caught unless you choose to search that planet again.
Example: You search planet 7. The rebels are actually on planet 6, so you don't find them.
Rebel's turn. They move to planet 7.
Your turn. If you search 7 again, the rebels are caught, but ONLY if you search 7 again.
The space bandit riddle could be solved way easier if you start at planet 3 and go to planet 2 after that. After that you complete the first sequence because the bandits have to be at an even after the first turn. So it will only take you 6 warps in stead of 10.
It is waste of turn and makes it take 11 turns. 1 and 3 are neighbours of 2, 2 is neighbour of 1, 4 is neighbour of 5, 5 is neighbour of 4, 6 is neighbour of 7 and 7 is neighbour of 6. They could be on any planet.
If you start at planet 3, the bandits could've started on any even planet and would now be on an odd numbered planet. Starting at three wastes a turn
Lol I always thought the purple guy's nose was his eyes
Now I look above him and those eyes are his eyes
MY LIFE WAS A LIE
Yeah......
Why is he drinking with his nose? 0:11
Solution linked is *behind registration wall*, so no thanks. I was promised a link "straight to the" answer.
"Your answer seems reasonable. Find out if you're right! [email/facebook/google+...]" Again, no thanks.
The answer was posted by Julia Chang one month before. Search for it in the comments.
Harry : Did you watch Titanic more than I did?
Ron : I have no idea!
This blurb tells us three things:
1. Each must have watched the Titanic at least two times, otherwise one of them would have known definitely who watched more than the other. So somewhere there has to be a 2 to 3 ratio (one more than the other). That is the new status quo.
2. If Ron watched Titanic twice, he knows Harry must have watched Titanic three times and so game over. But Ron says he has no idea, so Ron must've watched it at least three times, as he does not know how many times Harry watched it.
3. Based off of number 2, if Ron watched Titanic at least three times, then Harry must either have watched Titanic two times or four times.
Harry : Me neither. Do you know now?
4. So Harry doesn't know either. If Ron had watched Titanic at least three times and Harry himself knows he watched it only twice, then he would respond, "Oh, I know." But he doesn't know either, so Harry must have watched the Titanic at least four times.
Ron : "Yes, indeed!"
5. Ok, so Ron gets the logic said above, and so he knows he has watched Titanic three times while Harry has watched the Titanic four times. (On a side note that also means that Ron must have watched it an odd number of times while Harry would watched it an even number of times.)
Harry : Really? Then so do I.
6. When Ron said "Yes, indeed!" it is a confirmation to Harry that Ron watched Titanic only three times. He realizes that Ron must have watched Titanic one time less than him, and so knows the answer.
Answer : At the minimum, Ron watched Titanic three times and Harry watched Titanic four times.
The Final Question : What's the sum of the possible number of times that Ron watched Titanic?
7. Ron couldn't have watched Titanic once or twice, as it would have been evident right away in the conversation either to him or to Harry. We already proved that "3 times" is a viable answer choice for Ron. How about trying 4 times for Ron? We already know Harry must have watched Titanic at least four times, but both of them can't have watched Titanic the same number of times. So Ron definitely has not watched Titanic 4 times. So that pushes the ratio up to 4:5, meaning it's possible Ron has watched Titanic 5 times. If there were any number higher than 5 (for Ron), Ron would no longer know for a fact how many times Harry watched the Titanic and the conversation would not proceed in this fashion and would be greatly extended. Hence, to answer the question, there are only two possible times that Ron watched Titanic: 3 times and 5 times.
3+5= 8
I think the key to solving this problem is to trust your logic each step of the way and don't doubt what you just understood when using it to understand the next part. If there is a flaw to my logic, please do point it out.
@@frankmalenfant2828 or:
ron watched titanic 1 time
Line 1 Harry: have you watched more than me?
Line 2 Ron: I dont know
Line 3 Harry: I dont know either
Line 4 Ron: Since you said that, now i know
Line 5 Harry: And since you said *that,* now i know aswell
because they both know one of them watched titanic 1 more than the other, if ron watched 1 time, harry would have watched it either 0 or 2 times, so when first asked, ron does not know (line 2). if harry watched 0 times, he would already know that ron watched more than him. but since he does not (line 3) this means he watched 2 times. Upon hearing this, ron knows that harry watch 2 times, so he knows himself (line 4). Harry realizes the logic above and because of this now knows himself (line 5)
the assumption you made was that they had both watched at least 1 time, which i do not believe was said. even so, if ron had watched 2 times, he still would not know, at least until line 3. because harry could have watched it once, or twice. (perhaps you assumed line 1 as harry saying he does not know? this is not the case i believe. he is asking ron if ron knows, not saying he himself does not know)
STAR WARS REFERENCE!!!!!! :D :D :D 0:19 this makes me very happy because I love Star Wars. Thank you Ted-Ed for making me very happy
Planet 2 looks tasty 😋
Planet 4 looks like a half burnt marshmallow
Britt Groenewegen yeah it does lol
Julia Budziejewska (Eats planet two and four)
I have always have fun on teded videos, but not this one, I hate the fact that the bonus riddle is not answered, I visit the ads, but it make me signing up, but after signing up? It told me to be premium member. duh.
Bagas Irwansyah
I followed the link and it worked without signing up for premium. If you want to know the answer, look at the end of this comment.
5
gnampf1234 Thank you very much
That answer is wrong, it's 3.
Peace Guard
5 is the correct answer and also the answer on Brilliant.
There are two different possibilities, Ron could have seen the movie either 2 or 3 times. It has already been explained multiple times, but in short:
Ron isn't sure wether he saw it more often, so he must have seen it at least 2 times.
Harry knows that and isn't sure neither, so he must have seen it at least 3 times.
Now Ron knows, which means he either saw it 2 times and Harry 3 or 3 times and Harry 4. Thus, the answer is 2+3=5.
gnampf1234 I don't think Ron could have seen the movie 2 times.
Suppose Ron saw the movie 2 times, that implies Harry saw it 1 or 3 time(s).
Case 1: If Harry saw it only once, he wouldn't have bothered asking the first question, since he already knows Ron has seen it 2 times (0 is not possible).
Case 2: If Harry saw it 3 times, he would ask Ron first question since he is not sure if Ron watched it 2/4 times. Now if Ron had watched it only twice, he would know Harry watched it 3 times exactly, since the other option (Harry watched only once) means Harry wouldn't have asked the question in the first place. So Ron would be able to answer as soon as Harry asks the first question.
I love that almost every bridge, or raft, get to the other side riddle, they all wave on the other side.
Ted-d spends more time on the scenario then the riddle itself
Change my mind
I like how all seven planets are Star Wars references.
“Hey, glass here, I can’t call in for work”
“Why, they’re criminals, we need you!”
“No... it’s to complicated, and my brain is fried”
That would be my excuse if they asked me to do this...
I haven't watched it, but I'm sure that I won't be able to do this as well.
This video was a lot smarter then I thought it would be, It was quite more challenging then I thought too, maybe I’ll show it to my math teacher.
Good idea! Let me know what she/he says.
I love the crazy themes of these riddles, now were a galactic patrol member chasing rebels across a funky planet system
Another riddle I can't solve.!
What about 7-6-3-4-2-4?
Land on 7 move to 6 then 3 = that row is clear and landing on 3 blocks their movement
Move to 4 then 2 = only 5 is left as a possibility as if they're on 1 they have to move to 2 and be apprehended
Move to 4 = if they were on 5 they would have to move to 4
Maybe I missed a rule but this seems easier.
easiest flaw I can see with this is that the Rebels can just repeat 1-2-1-2-1-2
Alright but what about this:
Say you start at 3, and your pattern goes like this: 3, 7, 3, 5, 3, 1, 3.
the video says they are forced to move every hour, so if they start on literally ANY of the 7 planets, you will have found them. returning to #3 every other time ensures they can never leave whichever pair of planets they are stuck on from the beginning.
still can do 1-2-1-2-1-2
nunya bizniz no they cant.
in the 6th hour as you say, when they're on 2, you are on 1. at the end of the hour, it says they are FORCED to move, so they must move to either 1 or 3.
if they move to 1, you're already there.
if they move to 3, then you're going to catch them, because that's where YOU go next for your 7th hour.
there's literally no way for them to escape, you've caught them in 7 turns or less.
Teve an important distinction is the order of operations. Cops move -> search -> rebels move. As we see at 2:00, the rebels can move onto the same planet as the cops. They aren't caught on arrival and are safe until the cops check the planet a second time.
But the real riddle Ted ed want us to solve is:
*is that green fly alien girl's mouth or nose?*
Yes
Yes
Yes
Yes
Yes
This is the best thing of ted-ed
Rotnecca Sacyn yes
The riddle was not explained in sufficient detail, i.e. how the moving works, are we warping while they are there or travelling? Who moves first? Because let's say we started at 1. And they are at 2. Clock starts ticking now? Or when they start travelling? Let's say it starts after they land. First move, they go to number 1. Do we decide to warp while they are there? When does our clock start? Let's say we warped to planet 2 while they are at number 1. When does to time start for the new move? If this is like chess, played in turn, how do we know when the other side's turn ended? Bad riddle.
There is no turn they move at the same time every hour.
I agree. I got confused at the start with "When I warp to the first planet, have they just moved, or are they still stationary till my next move?" They also didn't explain how many there were, and I originally assumed there were multiple members on multiple planets.
Not clear enough starting information.
You can choose (3!)^2=36 different solutions, choose planet 3 on turns 2, 4, 7, and 9, for the first five rounds, you can choose 3!=6 ways to search planets 2, 4, and 6 on turns 1, 3, 5. You follow a similar pattern in the last five rounds. the rebels always move to an adjacent planet. But you can choose to move to any planet after another, you can even search the same planet twice in a row.
Harry has green eyes soo...
What is the answer to the bonus riddle?
ikkeduitser tje sum is 5
Either Ron has watched it 2 times and Harry 3 times or Harry has watched it 2 times and Ron 3 times.
I think it's 3. When Rony answered for the first time, harry would knew that Rony watched at least 2 times, but he said that he didnt knew eighter, so Rony knew that Harry too watched at least 2 times, but since Harry wanst sure, Rony knew that Harry watched only 2 times, and then Rony watched 3.
Hi ikkeduitser! Thanks for playing along! We fixed the problem with the link to the bonus riddle solution, so now you can find it here: brilliant.org/TedEdTitanic/
Making us sign up just to see the answer is not cool TED-Ed... maybe don't partner with websites that practice this nonsense.
brilliant : how many sponsors do u want from us?
ted-ed : YES
pls make a bonus riddle but u show the answer in youtube
0:17 Ted-Ed, listen to me.
Did you just rip off 7 Star Wars planets!?
We both have names that are from video games =|
4:30
Can't you get out.
Really.
Can't you
KaiWut the pic is a close up si shot from the bars :D ...and yeah, nice one there xD
Rebels: "wait we can just-" *teleports to a completely different solar system and tells their friends* "*YOU WILL NEVER FIND US!*"
Both Harry and Ron have seen Titanic many more times than me because I did not watch it...
If you failed this riddle...
*”You have failed me for the last time, Officer!”*
LA Noire reference? Idk...:/
@@Daniel-ef1mw It's a Darth Vader reference, as in this riddle, we're dealing with the "rebels".
The line is "You have failed me for the last time Admiral", but yes
I think I could solve this riddle in 6 moves - start on planet 3, either criminals start on odd or positive not 3, - you move to 1 and back to 3, if they were on either 1 or 2 you would have caught them if not repeat for the other two wings. My reasoning is if they start on 3 you catch them if not they start on positive or odd so moving to 1 means if they are there they are caught, if on 2 they move to 3, you then move to 3 and catch them. If not on 1 or 2 then repeat for 4&5 and 6&7.
That wouldn't work, here's why :
R-Rebels, Y-You.
Start : R-2 Y-3
Move 1 : R-3 Y-1
Move 2 : R-4 Y-3
Move 3 : R-3 Y-5
Move 4 : R-6 Y-3
Move 5 : R-3 Y-7
Move 6 : R-2/4/6 Y-3
They can avoid you literally forever if you use that strategy.
@@skiller5034 i see the error in my reasoning
This is a simple strategy that lets you catch them in under 10 moves.
1: Start at the 3rd planet.
2: If they are not there, move to one of the other planets nearby, 6, 2, and 4.
3: If they are not in those planets, they cannot go anywhere else other than back track to the original planet they were in. If they move to 3, we can catch them. If they dont, they back tracked.
(If they back track) 4: Move to one of the middle planets. If they arent in the one you went to, they can now only move to the same outer planet or planet 3. You can repeat as much as you want, as long as you do it in under 10 turns.
Doesn't work. I think you assume that they start on an odd numbered planet
@@rybiryj yes
4:24
Teded - thanks to your deductive reasoning!
Me - mine ? 🤔😏
2024 here. For the first riddle I chose to stay on planet 3 throughout as the riddle says you MAY move, but they MUST.
In 10 moves it is impossible for them to stay alternating between the planets on one end. They'd meet me at the junction definitely😊
Why is no one talking about the Star Wars references at 0:21?
This galaxy sounds very familiar. In my galaxy we have
1-Endor
2-Yavin IV
3-Bespin
4-Tatooine
5-Dagobah
6-well... we used to have Alderaan
7 and Kashyyyk
Nice
Star wars AND Harry Potter in 1 RIDDLE video?
This deserves a like.
Hello Ted-Ed. Although your riddles are most often presented with clear rules so that we are given a chance to solve them, this one seems quite flawed to me. I might of course be mistaken.
It isn't said clearly whether police and rebels move simultaneously or by turn.
In the first explanation for a 5-planets cluster, you say rebels can be found in 2 moves.
Well in that case it means they move simultaneously with police. Why so ? Because if i don't find them at first on center planet it means they were on center planet and moved to an external planet as police was warping to center planet.
If that wasn't the case i.e if they were moving by turn, and police goes to center planet, either they find the rebels there, or either the rebels started on external planet and come to the center planet right after, thus stumbling onto the police. the 5-planets cluster would actually be solved in 1 move, which isn't the case according to you. So it implies that police and rebels move *simultaneously*, ok.
But in the explanation of the actual riddle, you seem to imply police and rebels move by turn.
At 2:35 it is said that rebels can be on either planet 3,5 or 7, and then as you simulate police moving to planet 3 and finding nothing, the conclusion is "they were not on planet 3". Okay, so it isn't considered that rebels might have been on planet 3 and moved elsewhere during police warp to planet 3. Which means rebels move *after* police has moved and not in the meantime. The riddle isn't coherent on that.
Cheers
I was assuming simultaneous moves based on the description at the beginning (0:40 - "their beat-up smuggling can only jump to an adjacent planet in THAT SAME TIME"). This makes it harder (if not impossible) as the rebels could slip by planet 3 when you move off of it. e.g. you move from 3 -> 4 and they move from 6->3 on one turn, then you move 4 ->3 while they move 3 -> 2.
I'm to lazy to make another essay so I'm just gonna reply so you would get a notification and see my reply telling you to read the first reply
Some instruction are unclear. Because i think the rebel and police are move in same time.
It means when police in planet 2, and go to planet 1, rebel can go undetected from planet 1 to planet 2.
Nice riddle tho.
yes, that's true. But the answer covers this case.
Here's what seems like a 9-move solution to the seven planets problem: 2-2-3-4-3-4-3-6-6. The first three moves clear out one arm. The next three moves clear a second arm while preventing access to the first arm. The last three moves clear the last arm. Did I miss something? Are there even better solutions, or is 9 the minimum?
Yeah...no. As soon as the force goes to 4, the dark side can go to 3, then to 2, so they are now in the first arm :') Going by your moves, their moves can be: 6-7-6-3-2-... good try though. loving these puzzles XD
if you arrive at 4 and searched, then the rebels do their move and can jump from 5 to 4, you only search on arrival. Then if you jump back to 3 to see if the other branch didn't jump there, then rebels on 4 can follow you to 3 after searching there. And then if you don't revisit 3, they can escape in the cleared branch. 2-2-3-5-3-5-3-7-3-7 seems and alternate sollution based on your strategy
this one is correct 2-2-3-5-3-4-3-7-3-6 (3-5-3-5 doesn't work)
Wow just suscribed and a new video.....this one i was able to solve.....easy i knew that before
"They must cross over to the left bank of a crocodile infested water." Solution: Wait until the crocodiles die, because that water looks like slime. Then, jump on the corpses and get to the other side :D
Title: can you solve the seven planets riddle?
Me, thinking he is talking about the planets orbiting the sun: *”Wait, hold on”*
"Every time they can relocate, they will."
Does this mean that if the cops are on the planet they would have to move to (say they are on the outside and the cops are one planet inward), then they *can't* relocate, therefore they won't? If you follow the list instructions when they summarize it, it says that they MUST move every hour. So there is no implication that there is any situation where they can't.
See, I have a solution that works if they absolutely must move each hour, guaranteed, and it gets them in 7 moves if that is the case. So... honestly this feels important to know for sure. The use of the word "can" implies there might be a situation where they can't (blocked route), yet the use of the word MUST (in all caps in the video even) tells me that there's no such situation.
So what's the deal? Would my solution be valid?
They probably have to refuel their ship every hour, and the “they can relocate” simply means that their ship is working
or you can just scan for infrared light from the engines firing
I found a different solution i think.
1+2: We start on an even planet, waiting one round, so we can ensure there didn't start on that outer planets too.
3: We then move to the middle planet.
They have to be in one of the other two planet rows.
4: We go to one outer Planet, because if they are on an even planet, their next move will go to the outer planet, where we would get them, or the middle planet. If they are on the outer planet we get them immediatly.
5: As they could have been on the even planet, we have to go to the middle planet again, where we would get them too, if they were on the other row.
6: From there on we just go towards the last two planets, going first for the even planet.
7: As our seventh move we would get them on the outer planet.
That seems correct, right? I don't know any move or starting position by them where we couldn't get them.
Whoa this is insanely time consuming, the amount of paths is just gaaaaaahhhhhhhh
0:13
I like how our suspects weigh 80-something and 84.71072 pounds.
HOW DID YOU EVEN SEE THAT?? 😭🤣
The names are pete and repete lol
also "specific larceny" keyword specific
Pete is 3’-ish and 80-something pounds, wanted for general apathy. RePete is 3’4.20”, 84.71072 pounds, and is wanted for specific larceny.
So If the east example problem was:
6
|
3 - 4
|
2
And if the actual problem was:
7
|
6
|
3 - 4 - 5
|
2
|
1
Then can anyone solve (with any number of moves) this:
9
|
7
|
6
|
3 - 4 - 5 - 8
|
2
|
1
|
0
Reply if you have a answer :D
What I expected: Logic and strategy
What I got: Rip-offs of star wars planets