Finding Transfer Fucntion of a Block Diagram Example (Block Diagram Reduction Method)

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  • Опубликовано: 24 янв 2025

Комментарии • 32

  • @foreverfugazi245
    @foreverfugazi245 8 месяцев назад +11

    the most easiest explanation I've heard on anything till date, . thanks mate

  • @md.saiyedchowdhury2545
    @md.saiyedchowdhury2545 2 месяца назад +1

    Best with clear details, thanks sir, I'm seeing your lecture from Bangladesh 🇧🇩❤️

  • @Tankalty
    @Tankalty Месяц назад +2

    Very good explanations!

  • @heronn4137
    @heronn4137 2 месяца назад +7

    you are holding the pen like you were suppose to be left handed

  • @heaskeladden2711
    @heaskeladden2711 3 месяца назад +1

    great video, thank you so much for making this!

  • @piggypiggy855
    @piggypiggy855 2 года назад +2

    Very well explained

  • @zechenwei1139
    @zechenwei1139 4 месяца назад +1

    Very nice. Thank you!

  • @jumbojimbo706
    @jumbojimbo706 5 месяцев назад +4

    That sheet you have is so so good

  • @marriotnyeleti3564
    @marriotnyeleti3564 2 года назад +2

    Well explained sir

  • @dan_zem
    @dan_zem 7 дней назад +1

    Спасибо! ❤❤❤❤

  • @ARTIOMIVANCUEVACHEKALIOVA
    @ARTIOMIVANCUEVACHEKALIOVA 8 месяцев назад +1

    Thanks for your video mate

  • @ReZGaMeZ-eb7fc
    @ReZGaMeZ-eb7fc 25 дней назад

    that rules paper helps a lot

  • @Ali-cc3zz
    @Ali-cc3zz 2 года назад +1

    Well done pro

  • @مروةمحمد-ث7ح
    @مروةمحمد-ث7ح Месяц назад +1

    perfect

  • @akhilm7080
    @akhilm7080 3 месяца назад +1

    Bro where are you from?

  • @michaelgershon9077
    @michaelgershon9077 2 года назад

    I don't get the same answer when I move the junction between G3 and G4 in front of G4 , Why?

    • @dmdengineering
      @dmdengineering  2 года назад +6

      I just went through the problem again starting with moving the right-most summing junction to the right of G4 putting a G4 into the upper right branch. I got the same answer as in the video. The steps I followed were as follows:
      • move right most summing junction to right of G4 and make upper right branch contain G4
      • multiply original G4 with G3 since they are now in series
      • move takeoff point to right of G2 upstream similar to how I started in the video which makes the upper right branch G2G4
      • combine G1 and original G2 in parallel to get G1-G2
      • move summing junction to the left of G3G4 downstream of G3G4 making the bottom branch G3G4G5
      • multiply (G1-G2) with G3G4 since they are in series
      • combine left side of diagram in parallel to get (G2G4 + G1G3G4 - G2G3G4)
      • use feedback rule on right side of diagram (before G6) to get 1/(1-G3G4G5)
      • multiply together remaining three blocks in parallel to get final transfer function
      I hope this helps. There are many different ways you can do this kind of problem, but they should all get you to the same answer

  • @sesesYT
    @sesesYT 3 месяца назад +1

    thx

  • @rodrigomatos7686
    @rodrigomatos7686 5 месяцев назад

    Perfect

  • @osohmillicent2312
    @osohmillicent2312 4 месяца назад

    Can I get the rules please

    • @dmdengineering
      @dmdengineering  4 месяца назад +1

      The rules are shown on a sheet of paper I use throughout the video. Please pause the video and copy the rules down if you would like to have them for your notes

  • @michaelgershon9077
    @michaelgershon9077 2 года назад

    Can someone one take the junction downstream and get the same answer?...

    • @dmdengineering
      @dmdengineering  2 года назад

      Yes! There are many ways to solve this kind of problem, and I just showed one

    • @marcodiprima4989
      @marcodiprima4989 2 года назад

      I didn't moving g2 after g4 and not before g3. I got a different answer

  • @vassilisbakalas3423
    @vassilisbakalas3423 Год назад +2

    godsent

  • @reillyjensen2641
    @reillyjensen2641 2 года назад

    Use masons gain formula! It always works

  • @elmertalara7915
    @elmertalara7915 4 месяца назад

  • @MusaYmc
    @MusaYmc Год назад

    +rep

  • @RavenMagbanua-if9qg
    @RavenMagbanua-if9qg 4 месяца назад

    the G5 is not a feedback, just evaluate it by parallel lol

    • @Neekalos
      @Neekalos 3 месяца назад +2

      Yes it is lol, look at the direction of the arrows

  • @rafeyhasan1189
    @rafeyhasan1189 8 месяцев назад

    How the hell are you holding that pen!!🫥