Conductors in Electrostatic Equilibrium | Rules for Electric Fields | Doc Physics

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  • Опубликовано: 6 янв 2025
  • This video lists and sorta explains the rules of conductors so you can solve problems. If you still wonder why charges like pointy bits, please view my video (and the ensuing glorious discussion with other nerds in the comments) right hurre: • Electric Potential of ...

Комментарии • 92

  • @JordanEdmundsEECS
    @JordanEdmundsEECS 9 лет назад +59

    Why on earth is that incredibly elegant explanation of charge distribution on the outside of a conductor absent from my Physics textbook?

    • @adeeb1787
      @adeeb1787 4 года назад +4

      Maybe the authors wanted to make you more struggle than they did.

  • @atothejjj
    @atothejjj 5 лет назад +40

    Why am i laughing and having fun learning physics

    • @sairakhan8880
      @sairakhan8880 4 года назад +1

      Because u need to go for phyciatrist😂

  • @abdulhamitprlk
    @abdulhamitprlk 8 лет назад +137

    as a white person, can confirm.

    • @amansoni158
      @amansoni158 4 года назад +3

      y'all are blessed with such hair

  • @rishabhpandey4575
    @rishabhpandey4575 8 лет назад +12

    Helpful......was banging my head trying to understand it from book👍

  • @lphoebe3634
    @lphoebe3634 9 месяцев назад +2

    how is an 11 year old video still so helpful

  • @ophirophir1874
    @ophirophir1874 9 лет назад +17

    so happy I found this and I don't need to buy a book to understand my lame teacher.

  • @keerthanaputhuvaya8893
    @keerthanaputhuvaya8893 9 лет назад +1

    At 9:34 ....how do the charges cluster up , shouldn't like charges repel and wouldn't that sort of disturb the equilibrium with a flow ?

  • @kameelamareen
    @kameelamareen 7 лет назад +4

    A simple explaination for the accumaltion of charges at sharper regoins is as follows: charges move due to potential from high to low untill the potential is equal and electrostatic equilibrium is reached, now the potential is inversly proportional to the raduis and thus more chage is required where pot is = (k*q)/r.

  • @idster7
    @idster7 11 лет назад +2

    Your lectures are generally very clear (thank you for them), but this is the first I've been confused by. 1) is the excess charge on the surface of the conductor or on the outside of the conductor? 2) can you have both lone electrons & lone protons on the surface/outside or just one?

  • @THE______TRUTH
    @THE______TRUTH 9 лет назад +2

    I thought electric feild arrows point towards negative charges...is that wrong? Because 9:11 confused me.

    • @DocSchuster
      @DocSchuster  9 лет назад +1

      The Truth I was simply defining the direction that was out from the surface. You are correct that E points the opposite way.

  • @Picksandfrets
    @Picksandfrets 3 года назад +1

    I got my answer sir, thank you so much for uploading the video.

  • @jojo.s_bekaar_adventures
    @jojo.s_bekaar_adventures 5 лет назад +2

    9:50 umm.. why are the field lines going out from the -ve charge

    • @shreyanshrai1645
      @shreyanshrai1645 4 года назад

      just field just normal direction. perpendicular to surface .

    • @mysteryman595
      @mysteryman595 3 года назад

      Good catch, should be pointing in

  • @ItsAmirSheidaei
    @ItsAmirSheidaei 11 лет назад +6

    Loool, A white persons hair! This is a great series! Thanks a ton!

  • @DocSchuster
    @DocSchuster  12 лет назад +5

    This is an astoundingly good question! We're all scientists here - please do some research and get back to me.
    On an even more serious note, I've seen white people who wear long straight hair. If you look at these people from a meter away, you might come to the conclusion that their hair is always parallel to their head. BUT NO! Look closer and be surprised. Electric fields are similarly misleading. Now go get those Mexican people.

  • @abcdefg48141
    @abcdefg48141 5 лет назад

    Hi .....plz can you tell me how u set ur camera

  • @meerah2502
    @meerah2502 8 лет назад +1

    i like ur energy while explaining

  • @adosar7261
    @adosar7261 6 лет назад

    why perpendicular electric field cant make charge to move ? i mean E=F/q therefore the charges on surface must move out of the conductor...also if positive charges are in the surface where the negative are ?...i cant get it..help pls

  • @aml7481
    @aml7481 9 лет назад +2

    Here's my potential explanation of the "pointy bits":
    The answer lies not in the pointy bit itself, but in the area around the pointy bit. Since electric fields point at a tangent away from a conductor's surface, they will influence each other a lot in the area just around the pointy bits since they curve *into each other*.
    This means that the electrons in that area are closer to each other than normal, instead of curving outwards like they would in a sphere. Because of this, the electrons in that immediate area would push each other away, either congregating in the pointy bits or evenly distributing on the rest of the conductor's surface.
    So maybe we're not just looking at a lot more electrons on the pointy bits, but also at a lot fewer electrons in the areas just next to the pointy bits and a few more electrons on the rest of the conductor's surface.

  • @sydneyorr2904
    @sydneyorr2904 5 лет назад +3

    Love how the blue marker was feeling left out and rolled in @4:43 lol

  • @ElQaheryProductions
    @ElQaheryProductions 10 лет назад

    Shouldn't the outer charges repel with the incoming charges from the inside?

  • @mechailreydon3784
    @mechailreydon3784 5 лет назад +1

    Education at it's finest!

  • @JossinJax
    @JossinJax 6 лет назад

    Doc, why did you draw positive charges relocating to the surface after stating that protons don't move? How are positive charges (I'm assuming of course that we're talking about protons) moving if they're "trapped" in the atoms of the metal? Also, is it that there is no NET charge on the inside, or no charge on the inisde? Thanks!

    • @DocSchuster
      @DocSchuster  6 лет назад +2

      No net on the inside, for sure. And it can look like positive charges migrate to the surface when negatives in fact leave the surface!

  • @alecallee-munoz1868
    @alecallee-munoz1868 9 лет назад

    Why don't the charges distribute evenly throughout the conductor like most other things in equilibrium (ions in a solution). Wouldn't the high concentration of positive charges on the surface repel each other back into the interior of the conductor?

  • @gary.richardson
    @gary.richardson 6 лет назад

    @9:49 Look at the distance from the tip to the bulb is greater than across the thin section. Formula, similar to m sub 1 m sub 2 / r^2

  • @DocSchuster
    @DocSchuster  11 лет назад +1

    Hi Joe. You have totally missed my point.
    And how did I get called risqué and "PC wussy" for the same statement? Ah, the internets.

  • @Алексей-с6в7ъ
    @Алексей-с6в7ъ 7 лет назад

    Why electrons do not fly off the surfaces of a negatively charged body?

  • @roshansphotography4140
    @roshansphotography4140 7 лет назад

    is the conductor always hollow? Please help

  • @redwanmahmud7323
    @redwanmahmud7323 8 лет назад

    But wont the negative charges on the surface repel the electrons that are moving from inside towards the surface :\ ?

    • @DocSchuster
      @DocSchuster  8 лет назад

      +Redwan Mahmud Yes, but so are the (many more) on the opposite side of it. The net effect of all charges on the outside is zero.

  • @vbcambajogai
    @vbcambajogai 6 лет назад

    I didn't get why ground is like upper postive and lower negative ?

  • @ArtyBoney
    @ArtyBoney 9 лет назад +3

    The reason why there are more charges at the "pointy bits" is because of this:
    Imagine 2 spheres with a radius (r). Both have linear surface distribution( σ ).
    So for Sphere 1 we have σ1= Q1/S1 and for Sphere 2 we have σ2= Q2/S2...
    These 2 spheres have potentials V1= (σ1*r1) / ε0 and V2= (σ2*r2) / ε0
    Let's pretend that V1=V2=V that means
    (σ1*r1) / ε0 = (σ2*r2) / ε0
    .... ε0 cancel out so we have
    σ1*r1 = σ2*r2
    => σ1/σ2 = r2/r1
    From this we see that the raport of surface distributions is inversely proportional with the bending radius of the 2 points on the surface. So that means the "pointy bitiER" the object it, the more charges it will have.

    • @takashgon6691
      @takashgon6691 7 лет назад

      but for a conductor it's surface charge density is constant all over right?

    • @yashraj-ml2rq
      @yashraj-ml2rq 7 лет назад

      No it is not , it's potential is constant everywhere but not surface charge density

    • @nikkuthakur6905
      @nikkuthakur6905 7 лет назад

      Ya definitely rt

  • @dinodorkin9477
    @dinodorkin9477 6 лет назад

    Why would electrons (negative) move from a surface where there is already a deficit of electrons to the inside of the conductor where there is also a lack of electrons. Shouldn't they stay on the surface?

    • @lollolzi2996
      @lollolzi2996 5 лет назад

      would like to know the answer too. Please reply if you have found it.

  • @kega4062
    @kega4062 4 года назад

    MIND BLOWN

  • @keshavbansal5148
    @keshavbansal5148 7 лет назад

    just what I needed to understand, thanks

  • @idster7
    @idster7 11 лет назад

    it seems that if there are lone electrons & lone proteons, they will always draw each other until there are only lone charges of one kind or the other. e.g. at 5:05, if there were no lone proton in the middle, the lone electrons on the surface would still be attracted by both lone protons on the surface and one would link with the lone electron. so, i don't see how there could be both lone protons & lone electrons on the surface.

  • @physicstorque8084
    @physicstorque8084 4 года назад

    Electric fields in a conductor are perpendicular to the surface because if they were not, there would be a component of the electric field parallel to the potential direction of motion of the electrons inside the conductor. This would cause acceleration, but of course, this cannot be the case due to the net electric field inside the conductor being zero.

  • @KeepLearning--inderjeetsingh
    @KeepLearning--inderjeetsingh 6 лет назад +1

    Nice I really impress bro

  • @DocSchuster
    @DocSchuster  11 лет назад

    I like it!

  • @clashwithriders7724
    @clashwithriders7724 7 лет назад

    9.42, I think for(-) charge configuration... The field lines should be radially inward.

  • @wouterdewachter1559
    @wouterdewachter1559 6 лет назад +2

    Am I listening to Michael Scott?

  • @sam08090
    @sam08090 3 года назад

    Why Electric field should be normal for a perfect conductors? My guess - any tangential Electric field will cause movements(they can move freely) in charges in outer surface. So if they are stationary they must have the field normal.

  • @hitmanLis
    @hitmanLis 10 лет назад +2

    If lightning strikes that rod it will burn the conducting wire like a midnight dream. Not conventional wire can withstand the current from lightning. Its not there for lighting to strike it lol

  • @Klaus-Schwab_Dictator
    @Klaus-Schwab_Dictator 2 года назад

    Hey Vsauce, Michael here

  • @djlfjslkjflksdjlkfjs
    @djlfjslkjflksdjlkfjs 9 лет назад

    I think it like this.E = σ/(2ε) = q/(2εS).
    In pointy things at the very top.
    S → 0
    lim(S → 0) E = lim(S → 0) q/(2εS) =∞

  • @lionstudio1..
    @lionstudio1.. 5 лет назад

    (🙏 help me)
    A conductor has deficiate of 45electrons find the charge on that conductor

  • @Yousef-bp7oj
    @Yousef-bp7oj 10 месяцев назад +1

    6:00 why not black person

  • @jawnho9653
    @jawnho9653 6 лет назад +2

    I'd say it's more like a native aborigninal papaguinean's hair

  • @gurleenkaur1202
    @gurleenkaur1202 5 лет назад +1

    I LOVE U

  • @md65000
    @md65000 10 лет назад +1

    Your reasoning in the "counter example" (2:45) is poor & clumsy and not based on real physics. By your reasoning, as the interior charges approach the surface then repulsion from the surface should predominate and tend to send the charges back into the interior. Giving notice to electrons at the surface doesn't help because there are electrons everywhere--not just at the surface. Nevertheless, you made up for this with the "white people's hair" analogy--that was cute!

    • @DocSchuster
      @DocSchuster  10 лет назад

      md65000 No - it's cool. At least allow me a spherical object - the charges on the surface won't cause a net force on charges on the interior by symmetry. And you know I'm talking about electrons that are net charges. I agree it's clumsy, though. I'm trying to get the kids some things they can grab onto mentally.

    • @aml7481
      @aml7481 9 лет назад +1

      It's a lot more likely that the electrons reconfigure geometrically within their atoms to keep away from each other as much as possible. After all, it's not as if the conductor will suddenly change elements just because of electrons moving around (because then you'd have to start breaking atoms to move electrons at that distance).
      At higher level orbitals you start getting these types of geometric movements because the electron is getting far enough away from the nucleus. It's why most good conductors start at higher levels on the periodic table (higher number on the periodic table = more orbital levels).

    • @afsarafiq8115
      @afsarafiq8115 8 лет назад

      yyyeah

  • @rafaelnistor1652
    @rafaelnistor1652 5 лет назад

    If you wanna be super fancy. He literally just added a line.

  • @MrWoopydalan
    @MrWoopydalan 12 лет назад +2

    do mexican people's hair do something different?

    • @liamaxwell6451
      @liamaxwell6451 2 года назад

      i heard that shit he said (7:30) and was shook.
      like don't ALL people have hair?
      doesn't all hair grow perpendicularly to the surface of the scalp?
      like bro. why make it abt race and color?
      you have a wider audience than that.

  • @theoosinator23
    @theoosinator23 11 лет назад

    U MY F"IN DUDE MAN< FOR EVER GREAT FUL - austin sandoval

  • @fr0iler578
    @fr0iler578 7 лет назад +1

    I don't get why people are getting salty over the white people comment, it was a good joke and memorable, and rule 3 is always gonna be in my head cause of that.

  • @hypnoliz
    @hypnoliz 6 лет назад

    Brilliant

  • @zokhumsangapang1852
    @zokhumsangapang1852 7 лет назад

    Zlatan likes this.

  • @flowerlily5838
    @flowerlily5838 4 года назад

    Listening at 0.3

  • @minimaggykitchens646
    @minimaggykitchens646 4 года назад

    2020

  • @romelelectronics
    @romelelectronics 7 лет назад

  • @guillaume6373
    @guillaume6373 2 года назад

    hahahah love it

  • @ishan3147
    @ishan3147 5 лет назад

    I have better explanation for last fact, its very easy😚

  • @afsarafiq8115
    @afsarafiq8115 8 лет назад

    i dnt get it
    😈😈😈😈😈

  • @idster7
    @idster7 11 лет назад

    never mind. sorry. i think i see it.

  • @ishaac2520
    @ishaac2520 7 месяцев назад

    As a white person from Africa, I feel racist towards me.

  • @Durgesh2610
    @Durgesh2610 8 лет назад +11

    racist sala

    • @digitalstudy8547
      @digitalstudy8547 7 лет назад +5

      first u r indian .. second he is talking about his people . he himself is white. the way you do on your chai stalls ..

    • @SuperChristianMiiworld
      @SuperChristianMiiworld 6 лет назад +3

      How is he being racist when he's talking about his own people? One: he's being creative. Something your own Physics teacher lacks a lot. And two: that example alone helps us get a clear idea on how electric field looks and behaves like. It's not like he insulted white people. There is a huge difference! Sheesh...

    • @dm3248
      @dm3248 6 лет назад

      chutiya hai?

  • @scarleteyes415
    @scarleteyes415 5 лет назад

    I’ve never ever understood a word from this guy. Seems like I’ll just stick to Khan Academy.