Axial Loading - Statically Indeterminate Example 1

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  • Опубликовано: 9 сен 2024

Комментарии • 43

  • @tiagoperon306
    @tiagoperon306 10 лет назад +10

    i did not understand what my professor had done. you did in a comprehensively manner. thank you

  • @TerminusCOBHC
    @TerminusCOBHC 3 года назад +1

    This is a really great video. You did a fantastic job here. Thanks much.

  • @TheFlamedBoy
    @TheFlamedBoy 6 лет назад +1

    Just watching for 8 minutes and then whole chapter becomes clear :)

    • @SuperMusicMaker
      @SuperMusicMaker 4 года назад

      Mirranda Kerr yea, makes up for having a crappy professor

  • @andrewmills2729
    @andrewmills2729 3 года назад

    This was very helpful for my course project 1. Thank you.

  • @alisawi42
    @alisawi42 9 лет назад

    Simply explained! Thanks

  • @재현7704
    @재현7704 6 лет назад

    Also u can eliminate P so the equation will be " Sa-Sb = 0" negative sine indicates compression

  • @MrPlausibleDenial
    @MrPlausibleDenial 7 лет назад

    Shortcut for same material:
    Rc=1000(12/(12+18))=400lb
    Ra=1000(18/(12+18))=600lb

  • @DarvaishBandah
    @DarvaishBandah 5 лет назад

    What a nycc explanation.. 💕💕

  • @eddie2096
    @eddie2096 9 лет назад

    awesome video, should make more video and do more example

  • @sydneyneal1378
    @sydneyneal1378 8 лет назад

    Very helpful! Thank you

  • @vagelissmaragdis2778
    @vagelissmaragdis2778 5 лет назад

    Great job...

  • @rakibulhasannishat5803
    @rakibulhasannishat5803 Год назад

    in this video, you have written that the overall length change is zero
    AC=AB+AC.
    But the equation will be like this AC=AB+BC.
    please sir, you will clear my confusion.

  • @wdavis6814
    @wdavis6814 7 лет назад +2

    Thanks from ERAU.

  • @michaelloreantz
    @michaelloreantz 3 года назад +1

    Sir I have a question. In 4:08, isn't it a must to put Pbc pointing to the left? Recalling the whole system equilibrium equation, Ra+Rc=1000, therefore Rc=1000-Ra. If we use that equation (Pbc+1000-Ra=0), then Pbc=Ra-1000, which will contradict if we look the right side of the section where Pbc=Rc and Rc=1000-Ra, hence Pbc=1000-Ra.

    • @ECUSW
      @ECUSW  3 года назад +1

      Since Pbc is an internal force (stress resultant), the positive direction is always away from the cut face. This corresponds to tensile stress.

  • @aerostructures814
    @aerostructures814 7 лет назад

    excellent analysis. please click on the red airplane icon to see more

  • @재현7704
    @재현7704 6 лет назад

    i believe its " delta AB- delta BC" the force Rb is compress

  • @MilitaryConnect
    @MilitaryConnect 8 лет назад +5

    Shouldn't the reaction at A be pointing in the other way?

    • @juomarti5701
      @juomarti5701 7 лет назад +17

      It does not matter in which direction one writes the reaction force. Once calculations are complete, if a negative value is found for the reaction force in question, then it's direction is opposite to what was originally assumed.

  • @xBustx
    @xBustx 11 лет назад

    really helpful thank you

  • @chevarwilson6043
    @chevarwilson6043 6 лет назад +1

    @2:21 THE DELTA AC SHOULD BE "BC"?

  • @abdullahcivil3268
    @abdullahcivil3268 4 года назад

    teacher i have a question
    What is the importance of the statically indeterminate?

  • @mariellachica8788
    @mariellachica8788 5 лет назад

    ththank u sooooooooooooooo much

  • @angzaidbenaliabdellah7951
    @angzaidbenaliabdellah7951 7 лет назад

    Mhkwor Ola explanation is clear and we hope to be the explanation for the rest Mhazerat be but the Arab peace

  • @ikmalhakimharun3823
    @ikmalhakimharun3823 2 года назад

    why did u cancel AE ? is it bcs of the same diameter and the same E ?

  • @SirKaison
    @SirKaison 6 лет назад +2

    Why do the reaction forces at A and C point in the same direction?

    • @ECUSW
      @ECUSW  6 лет назад +2

      Because the applied force is to the right. Both of the reaction forces are to the left; this corresponds to the left portion of the rod being in tension and the right portion being in compression.

    • @SirKaison
      @SirKaison 6 лет назад

      Thank you so much for your response. My question seems really silly now :)

    • @rj-nj3uk
      @rj-nj3uk 6 лет назад

      ECUSW I took the direction of reaction forces by myself. And when I solved the problem(from the text book) i got a wrong answer. I gues your this comment explains it.

  • @vikashbisen6706
    @vikashbisen6706 7 лет назад

    thanks sir

  • @SuperTaiko95
    @SuperTaiko95 8 лет назад

    Hello Sir/Madam,
    I would like to ask, why does the force for P(BC) in the first example acts towards the right and not the left?

    • @kardelenyucekul3142
      @kardelenyucekul3142 3 года назад

      we cut beams each way then find internal forces all of them upwards. Later better than never :D

    • @SuperTaiko95
      @SuperTaiko95 3 года назад +1

      @@kardelenyucekul3142 Thanks, hahaha. I had graduated thanks to your videos xD Cheers

  • @saowalakaunok6554
    @saowalakaunok6554 10 лет назад

    excellent (y)
    ฉันเข้าใจ #thailand

  • @araceligarza6899
    @araceligarza6899 9 лет назад

    how do you know in which the direction are the reaction forces directed?

    • @lucickian0yoz
      @lucickian0yoz 9 лет назад

      It doesn't matter. If the reaction forces turn up negative, it means that the direction you've chosen is wrong. The whole idea is to stay consistent in notation through the problem, that meaning that if a reaction force turns up negative, you either keep it negative all the way through or you change direction and use it positive.

  • @germanosorio9979
    @germanosorio9979 7 лет назад

    Dear Sir could you give me your email please. I need one question about composite bars.
    Thanks you in advance.