thanks sir❤;however you didnt have to put a negative sign on the moment,because its direction already implies it,and again you forgot to calculate the angle of the resultant force
We don't eliminate it exactly. It is just part of the sum of moments we are looking for. Each of the forces also exerts a moment, in addition to the100 Nm pure torque.
That's simply the "right hand rule" convention. It doesn't really matter in a problem like this (so long as you are consistent), but if you are calculating moments with cross products it will matter.
@@zinc6748 Yes, typically when you include the direction (graphically in this case), then you write the absolute value of the scalar part. You could also write the equivalent moment as 115 N*m CW (clockwise).
The force would cause a clockwise rotation (negative rotation) overall, so the moment as a whole is negative. Personally, I always put the negative in front of the whole quantity, hence -(60)x(20).
This was very helpful. Now I FINALLY understand it! :)
It's very helpful in a very quick way .tq sir
thanks sir❤;however you didnt have to put a negative sign on the moment,because its direction already implies it,and again you forgot to calculate the angle of the resultant force
Very helpful. Thanks!
Your names gonna be be on my degree😂😂 thanks.
I have a question. Why do we eliminate the 100Nm moment in the first place?
We don't eliminate it exactly. It is just part of the sum of moments we are looking for. Each of the forces also exerts a moment, in addition to the100 Nm pure torque.
And pure moments are free vectors. So, they always show up in moment equations.
Thanks for making this
Very nice
VERY NICE .
Why is it anticlockwise rotation positive
That's simply the "right hand rule" convention. It doesn't really matter in a problem like this (so long as you are consistent), but if you are calculating moments with cross products it will matter.
But why did you write -115 Nm and not just 115 Nm at the end?
@@zinc6748 Yes, typically when you include the direction (graphically in this case), then you write the absolute value of the scalar part. You could also write the equivalent moment as 115 N*m CW (clockwise).
sir -excellent = which country ? what university ? -thank u sir
Nc
Thank u sir
Shouldn't that be -60×20 because we're calculating moment about A
The force would cause a clockwise rotation (negative rotation) overall, so the moment as a whole is negative. Personally, I always put the negative in front of the whole quantity, hence -(60)x(20).
tysm sir
watch first