Great stuff. I realized that the form of the question neccesitates that X (on the right half) be in the form 2^y. 2^x = (2^y)^32 which gives us that the log2 of x must be 32 times smaller than x, log2 both sides, 32y=x Then checked 2^6/6, 2^8/8 till i found 32 (as odd numbers cannot produce even ratios and X has to be above 32 minimally) and had the answer.
Great stuff. I realized that the form of the question neccesitates that X (on the right half) be in the form 2^y.
2^x = (2^y)^32
which gives us that the log2 of x must be 32 times smaller than x, log2 both sides, 32y=x
Then checked 2^6/6, 2^8/8 till i found 32 (as odd numbers cannot produce even ratios and X has to be above 32 minimally) and had the answer.