Celestial Navigation: How to find the altitude of a star

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---------ABOUT THE VIDEO---------
This video was originally uploaded to our other channel, Casual Navigation.
This video shows you how to use the nautical almanac to manually calculate the altitude of a star. Manual calculation of the altitude of stars is one of the steps towards celestial position fixing.
Once you master manual calculation of the altitude of stars, you have already completed most of the mathematics required for celestial position fixing.
Links mentioned in the video:
Spherical Trigonometry: en.wikipedia.org/wiki/Spheric...
Free Nautical Almanac: www.thenauticalalmanac.com
---------DISCLAIMER---------
Although we take all reasonable care to ensure the accuracy and reliability of the information provided in the content on this channel, the content is provided “as is”. We do not make any warranties about the accuracy, content, completeness, legality or reliability of the information contained within this channel.
The information contained within our videos is not professional or legal advice and should not be considered as such. If you need professional or legal advice, you should consult a suitably qualified professional.
Any action you take as a result of watching this video is strictly at your own risk.

[@markprange4386]

5:15 The US-published sight reduction books are not protected. You may copy and publish them or exerpts from them.

[@skinnysmile9937]

I proud of saying that I've clicked on this video to understand a topic that I don't, after watching I still don't understand and I'm confused

[@sfranklin1266]

Nice

[@ianndgod]

Hello sir, we always mention the "assume position". Where do we actualy take that? Is it the GPS position?

[@markprange2430]

Pick a nearby latitude in whole degrees, e.g. South 33°.
Pick a longitude that is a whole number of degrees from the star's meridian.
It helps to draw a diagram, or look on a globe.

[@rickeynaorem3594]

How do I put this sin -1...Cant seem to know how

[@christophedevos3760]

Is this 'inverted sine' in the beginning of the formula?

[@edwardfalk9997]

Yes. My own notes say:
sin(Hc) = sin(lat) * sin(dec) + cos(lat) * cos(dec) * cos(lha)
I found this in Ho 229 (the sight reduction tables). The equation for Azimuth is there too.
cos(dec) * sin(lha)
tan(Z) = ----------------------------------------------------
cos(lat) * sin(dec) - sin(lat) * cos(dec) * cos(lha)

[@christophedevos3760]

@@edwardfalk9997 Thanks , much appreciated.

[@cosmic_chaz]

Please for the love of god tell me this isnt calculus?