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Автовоспроизведение
Автоповтор
3^x+(3^x)²=(3^x)³(3^x)[(3^x)²-(3^x)-1]=0x=0 or 3^x=ß, golden ratio =½[1±sqrt(5)] x=[log(ß)]/log(3)
X=0 is not the answer, please watch the video.
MUSIC IS ANNOYING !
Lack an approximate result in a normal digits. Without any counting and calculating I assessed x as ca 0,7, in 10 sec.
x = log((√5 + 1)/2)/log(3) ≈ 0.4380178794859...
❤❤❤❤
3^x+(3^x)²=(3^x)³
(3^x)[(3^x)²-(3^x)-1]=0
x=0 or 3^x=ß, golden ratio
=½[1±sqrt(5)]
x=[log(ß)]/log(3)
X=0 is not the answer, please watch the video.
MUSIC IS ANNOYING !
Lack an approximate result in a normal digits. Without any counting and calculating I assessed x as ca 0,7, in 10 sec.
x = log((√5 + 1)/2)/log(3)
≈ 0.4380178794859...
❤❤❤❤